BIOL.CONCEPTS+INVERTIGATION-ACCESS CARD
4th Edition
ISBN: 9781260195316
Author: Hoefnagels
Publisher: INTER MCG
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Chapter 10, Problem 6GP
Summary Introduction
To create:
A linkage map for the chromosome having three genes, namely-Q, R, and S.
Concept introduction:
Linkage map is based on the linkage analysis of the genes on a chromosome. It does not represent the physical distance between the gene rather it only depicts the relative positions of genes. The relative position of the gene is determined by the percentage of their linkage.
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Students have asked these similar questions
Genes Q, R, and S are on the same chromosome. The crossoverfrequency between S and Q is 5%, the crossover frequency betweenQ and R is 30%, and the crossover frequency between R and S is35%. Use this information to create a linkage map for thechromosome
Imagine that the genes for seed color and seed shape are located on the same chromosome. A cross is made between two true-breeding plants. One plant produces green wrinkled seed (rryy) and the second parent produced round yellow seeds (RRYY). A test cross is made between the F1 generation with the following results:
green, wrinkled 645
green round 36
yellow wrinkled 29
yellow round 590
a) Draw the chromosomes of parents and four types of offsprings and show the recombinant and non-recombinants in the offsprings.
b) What is the recombination frequency between two loci?
In most tests of genetic linkage, the number of double crossovers is less than the number expected due to what effect, which limits the number of crossovers that can
occur in a short length of chromosome?
Chapter 10 Solutions
BIOL.CONCEPTS+INVERTIGATION-ACCESS CARD
Ch. 10.1 - Describe the relationships among chromosomes, DNA,...Ch. 10.1 - Prob. 2MCCh. 10.2 - Why did Gregor Mendel choose pea plants as his...Ch. 10.2 - Distinguish between dominant and recessive;...Ch. 10.2 - Prob. 3MCCh. 10.3 - What is a monohybrid cross, and what are the...Ch. 10.3 - How are Punnett squares helpful in following...Ch. 10.3 - Prob. 3MCCh. 10.3 - How does the law of segregation reflect the events...Ch. 10.4 - Prob. 1MC
Ch. 10.4 - Prob. 2MCCh. 10.4 - How can the product rule be used to predict the...Ch. 10.5 - How do patterns of inheritance differ for unlinked...Ch. 10.5 - What is the difference between recombinant and...Ch. 10.5 - Prob. 3MCCh. 10.6 - Prob. 1MCCh. 10.6 - Differentiate between pleiotropy and epistasis.Ch. 10.6 - How can the same phenotype stem from many...Ch. 10.6 - Figures 10.18 and 10.20 show two ways that a...Ch. 10.7 - Prob. 1MCCh. 10.7 - Prob. 2MCCh. 10.7 - Why do males and females express recessive...Ch. 10.7 - Prob. 4MCCh. 10.8 - How are pedigrees helpful in determining a...Ch. 10.8 - Prob. 2MCCh. 10.9 - Prob. 1MCCh. 10.9 - What is polygenic inheritance, and how is it...Ch. 10.10 - Prob. 1MCCh. 10.10 - Prob. 2MCCh. 10 - In the list of four terms below, which term is the...Ch. 10 - According to Mendel, if an individual is...Ch. 10 - Prob. 3MCQCh. 10 - Each letter below represents an allele. Which of...Ch. 10 - Which of the following is a possible gamete for an...Ch. 10 - Use the product rule to determine the chance of...Ch. 10 - Refer to the linkage map in figure 10.16b. A...Ch. 10 - How can epistasis decrease the number of...Ch. 10 - Prob. 9MCQCh. 10 - Prob. 10MCQCh. 10 - Prob. 1WIOCh. 10 - Prob. 2WIOCh. 10 - Some people compare a homologous pair of...Ch. 10 - How did Mendel use evidence from monohybrid and...Ch. 10 - Prob. 5WIOCh. 10 - Prob. 6WIOCh. 10 - Prob. 7WIOCh. 10 - Prob. 8WIOCh. 10 - Prob. 9WIOCh. 10 - A family has an X-linked dominant form of...Ch. 10 - X inactivation explains the large color patches in...Ch. 10 - Prob. 12WIOCh. 10 - Prob. 13WIOCh. 10 - Prob. 14WIOCh. 10 - Design an experiment using twins to determine the...Ch. 10 - Prob. 1GPCh. 10 - In Mexican hairless dogs, a dominant allele...Ch. 10 - A species of ornamental fish comes in two colors;...Ch. 10 - Two lizards have green skin and large dewlaps...Ch. 10 - Prob. 5GPCh. 10 - Prob. 6GPCh. 10 - Prob. 7GPCh. 10 - Prob. 8GPCh. 10 - Prob. 1PITCh. 10 - Explain the effects of a mutation, using allele,...Ch. 10 - 3. Add meiosis, gametes, incomplete dominance,...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- What would be the gene map for the following genes with known recombination frequencies? D and A is 5.1 cM, A and C is 15.8 cM, A and B is 7.8 cM, C and D is 10.7 cM, and C and B is 8.0 cM.arrow_forwardTo build a genetic map, how many types of crosses will be required to perform if you have three genes to map? Explain.arrow_forwardConstruct a chromosome map from the following chart showing crossover frequencies for linkage groups on autosomes. Gene Combinations Recombination Frequency a/b 2.5 a/c 3.0 b/c 5.5 b/s 5.5 a/s 8.0 c/s 11.0arrow_forward
- What is a contig? Explain how you would determine that two clones in a contig are overlapping.arrow_forwardRecombination frequencies between three loci in corn are shown in the following table: Loci Recombination frequency (%) R and W2 17 R and L2 35 W2 and L2 18 What is the order of the genes on the chromosome?arrow_forwardCould you have generated a chromosome map from the F2 progeny in cross 1 (assuming you crossed F1 males and females to each other to generate the F2)? What is the advantage of using cross 2 instead?arrow_forward
- In linkage mapping, how do we measure the distance between genes on a chromosome? options: A) The number of gametes used is proportional to the percent recombination in offspring. B) The number of offspring produced is equal to the percent recombination during crossover. C) The number of chromosomes resulting from crossover is equal to the distance the genes are apart in any one gamete. D) The percentage of recombinant offspring is directly proportional to how far apart the genes are on the chromosome.arrow_forwardYou perform a cross between two plants, one MmPp and one mmpp, and obtain offspring with the following phenotypes: 42 MP; 374 Mp; 367 mP; 27 mp. What can you conclude from these data? Group of answer choices The M and P genes are on different chromosomes The recombinant progeny are mP and Mp The M and P genes are far apart on the same chromosome The recombinant progeny are MP and mparrow_forwardFor linkage analysis, a test cross is used rather than a hybrid cross. Why is this essential? Why would a hybrid cross result in incorrect estimates of genetic distance?arrow_forward
- Construct a chromosome map from the following charts showing crossover frequencies for linkage groups on autosomes. (this one is tricky due to the unusual recombinations Gene Combinations Recombination Frequency y/w 2.2 v/m 3.0 v/r 26.6 v/w 30.0 v/y 32.2 w/m 33.0 y/m 35.2 w/r 56.6arrow_forwardWhat is the expected number of double crossovers based on the map? What is observed number of double crossover’s based on the data in the table? Calculate the interference using the formula.. Interpret the interference in terms of whether a crossover inhibits or stimulates an additional crossover in the same interval of the chromosome?arrow_forwardConsider the genetic map below. (a) In a total of 1000 observed progeny, how many would be expected to be parental, non-recombinant? (b) If the total number of observed double-crossover recombinant progeny is 0, what is the interference? A-------20 cm-----B—5cm----Carrow_forward
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