Chapter 10.1, Problem 6IP

To determine

To find: The mean, mode and median of the data.

Answer to Problem 6IP

The Mean is $57$ , Median is $60$ and there is no Mode.

Explanation of Solution

Given information: The minutes spent biking each day in one week $45,30,65,90,74,60,35$ .

Calculation: The minutes spent biking each day in one week $45,30,65,90,74,60,35$ .

Mean of data is:

  $\begin{array}{l}\mathrm{Mean}=\frac{sumofdata}{\mathrm{number}\mathrm{of}\mathrm{data}}\\ \mathrm{Mean}=\frac{45+30+65+90+74+60+35}{7}=\frac{399}{7}=57\end{array}$

Median of the data:

Data in ascending order $30,35,45,60,65,74,90$ .

  $\begin{array}{l}\mathrm{n}=7\\ \mathrm{Median}=\frac{n+1}{2}=\frac{7+1}{2}=\frac{8}{2}th=4th\\ 4th\mathrm{term}\mathrm{is}60\\ \end{array}$

So median is $60$ .

Mode:

In this case, none of the items are more frequent. So there is no mode.

Thus, the Mean is $57$ , Median is $60$ and there is no Mode.