Chapter 10.6, Problem 2GP

To determine

To calculate: the probability of the outcome of spinner and describe the likelihood.

Answer to Problem 2GP

Probability of getting even number that is $P\left(even\right)=\underset{\_}{\frac{1}{2}}$ and event is equally likely to occur as not.

Explanation of Solution

Given information:

1. Spinner is spun once.
2. Spinner is divided into 10 equal sectors
3. Need to determine the outcome of getting even number .
4. Associated figure is as follows

  

Formula Used:

  $\text{probablity}\text{of}\text{an}\text{event=}\frac{\text{number}\text{of}\text{favorable}\text{outcomes}}{\text{number}\text{of}\text{possible}\text{outcomes}}$

Calculation:

Number of possible outcomes of spinner $=10$

Need to determine probability of getting even number that is $P\left(\text{even}\right)$ .

As favorable outcomes are even numbers that are 2 , 4 , 6 , 8 and 10 , number of favorable out come = 5

Using formula $\text{probablity}\text{of}\text{an}\text{event=}\frac{\text{number}\text{of}\text{favorable}\text{outcomes}}{\text{number}\text{of}\text{possible}\text{outcomes}}$

  $P\left(even\right)=\frac{5}{10}=\frac{1}{2}$

As $\frac{1}{2}$ is equal to $50\%$ , the event of getting even number is as likely to happen as not.

Hence probability of getting even number that is $P\left(even\right)=\underset{\_}{\frac{1}{2}}$ and event is equally likely to occur as not.