Chapter 10.2, Problem 1P

To determine

The acceleration due to gravity on the planet surface.

Answer to Problem 1P

The acceleration due to gravity is $25\text{m}/{\text{s}}^2$.

Explanation of Solution

Write the expression to obtain the acceleration due to gravity $\left(g\right)$.

$c=\sqrt{gy}$

$g=\frac{c^2}{y}$ (I)

Here, depth of pond is y and speed of wave is c.

Conclusion:

Substitute $5\text{m}/\text{s}$ for c and 1 m for y in Equation (I).

  $\begin{array}{c}g=\frac{{\left(5\text{m}/\text{s}\right)}^2}{1\text{ m}}\\ =25\text{m}/{\text{s}}^2\end{array}$

Thus, the acceleration due to gravity is $25\text{m}/{\text{s}}^2$.