Concept explainers
To select the correct statements.
Answer to Problem 26PFA
A and B are correct.
Explanation of Solution
Given information:Data set is
5.87, 5.47, 5.02, 4.62, 6.83, 6.2, 6.15, 5.55, 3.05, 5.09, 5.07
Formula used: Standard deviation formula is,
Lower quartile is,
Upper quartile is,
Inter-quartile range is,
Median is,
Calculation:
Sorting data,
3.05,4.62,5.02,5.07,5.09,5.47,5.55,5.87,6.15,6.2,6.83
Verifyingthe options,
For option A,
3.05 is a value very far from the other data points. It is an outlier
Hence, A is correct.
For option B,
For Mean substituting values,
=
Solving,
=5.35
Value |
|
|
3.05 | -2.306363636 | 5.319313221 |
4.62 | -0.7363636364 | 0.542231405 |
5.02 | -0.3363636364 | 0.1131404959 |
5.07 | -0.2863636364 | 0.08200413225 |
5.09 | -0.2663636364 | 0.0709495868 |
5.47 | 0.1136363636 | 0.01291322313 |
5.55 | 0.1936363636 | 0.03749504131 |
5.87 | 0.5136363636 | 0.263822314 |
6.15 | 0.7936363636 | 0.6298586776 |
6.2 | 0.8436363636 | 0.711722314 |
6.83 | 1.473636364 | 2.171604133 |
Total |
|
For Standard deviation substituting the value,
On solving
=0.95
B is correct.
For option C.
For lower quartile substituting the value,
So,
On solving,
On substituting the value,
For upper quartile substituting the value,
So,
On solving,
On substituting the value,
For Interquartile range. Substituting the value,
On solving,
Hence, C is incorrect.
For option D
For Median substituting the value,
On solving,
On substituting the value,
Hence, D is incorrect.
For option E
The measure of central tendency most affected by an outlier is mean.
Hence, E is incorrect
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Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
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