Concept explainers
To find mean median mode, range and standard deviation.
Answer to Problem 4CYU
Mean=20.5
Median=20.75
Mode=21
Range=6.5
Standard deviation=1.83
Explanation of Solution
Given information:
42,39,45,44,37,42,38,37,41,49,42,36
Constant=0.5
Formula used:
Mean=
Where, n=total number of terms,
Mode= most repeating numbers.
Median=
Range= maximum- minimum
Standard deviation,
Where
Calculation:
After multiplying with constant,
New data is 21,19.5,22.5,22,18.5,21,19,18.5,20.5,24.5,21,18
Substituting the value,
Mean=
Sort the number in ascending order,
18,18.5,18.5,19,19.5,20.5,21,21,21,22,22.5,24.5
Median=
Mode= 21(because it is most repetitive number)
Range=
For standard deviation,
values | Difference= | ( |
21 | 0.5 | 0.25 |
19.5 | -1 | 1 |
22.5 | 2 | 4 |
22 | 1.5 | 2.25 |
18.5 | -2 | 4 |
21 | 0.5 | 0.25 |
19 | -1.5 | 2.25 |
18.5 | 2 | 4 |
20.5 | 0 | 0 |
24.5 | 4 | 16 |
21 | 0.5 | 0.25 |
18 | -2.5 | 6.25 |
Chapter 10 Solutions
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
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