(a)
The graph for the characteristic strength and Weibull modulus.
(a)
Answer to Problem 11.13P
The graph for the characteristic strength and Weibull modulus is shown in figure (1)
Explanation of Solution
Given:
The following characteristic strengths are given as,
Formula Used:
Write the expression for the calculation of polymer specimen as:
Here,
Calculation:
The coordinates for the characteristic strength and Weibull modulus is calculated in table below.
Rank | Stress | |||||
Table (1)
The graph between
Figure (1)
From Figure (1) it is found that the natural log of characteristics strength on the horizontal axis is
Conclusion:
Thus, the graph for the characteristic strength and Weibull modulus is shown in figure (1)
(b)
The stress for the
(b)
Explanation of Solution
Introduction:
At very low stresses, such as
From Table (1), it is found that the stress for 90% probability of survival is
Conclusion:
Therefore, the stress for 90% probability of survival is
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Chapter 11 Solutions
Materials Science And Engineering Properties
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- Materials Science And Engineering PropertiesCivil EngineeringISBN:9781111988609Author:Charles GilmorePublisher:Cengage Learning