Two children are playing on stools at a restaurant counter. Their feet do not reach the footrests, and the tops of the stools are free to rotate without friction on pedestals fixed to the floor. One of the children catches a tossed ball, in a process described by the equation
(a) Solve the equation for the unknown
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Physics for Scientists and Engineers, Volume 1
- Rank the following quantities of energy from largest to the smallest. State if any are equal. (a) the absolute value of the average potential energy of the SunEarth system (b) the average kinetic energy of the Earth in its orbital motion relative to the Sun (c) the absolute value of the total energy of the SunEarth systemarrow_forwardWhen a particle decays, it splits into two different particles and each is shot off in opposite direction. The speed of each particle is such that momentum is conserved. uranium 238 decays into thorium 234 by emitting an alpha particle (helium 4). If the alpha particle leaves with a speed of 6.8 x 10^3 m/s, what is the speed of the thorium atom? Give your answer in m/s to three significant figures. Use atomic mass units for the mass of each particle. Uranium 238 in atomic mass units is 238 to three significant figures.arrow_forwardStudents are given two spherical balls made of different materials, but of identical mass and diameter to experiment with. Each ball is dropped from an initial height, h0. The “sad ball” comes to rest without visibly bouncing when it strikes the tabletop. The “happy ball” bounces up to a final height h, where h<h0 A fellow student wants to use one of the balls in a carnival game where cups are knocked over by a thrown ball. Which ball should they use, happy or sad? In a clear, coherent, paragraph-length response that may also contain figures and/or equations, explain what physics principles explain why the happy ball bounces higher off of the tabletop and explain which ball makes the better choice as a projectile in the carnival game. COMPLETE THE TABLE BELOW A Answer the Question B Basic Physics C Cite Information D Draw it all togetherarrow_forward
- (a) 15.4 kg m^2/s (a) 18.5 kg m^2/s (a) 6.4 kg m^2/s (a) 10 kg m^2/s (b) 0.30 m (b) 3.34 m (b) 5.14 m (b) 4.11 m (c)-14.9 J (c) 14.9 J (c)-17.4 J (c) 17.4 J entum Ho of the p (b) the distance r₁1 between O and Q,arrow_forwardLo= 0.09 m , g= 10 m/s? m (kg) L (m) x = L – Lo (m) F (N) 0.02 0.108 0.018 0.2 0.04 0.126 0.036 0.4 0.06 0.145 0.055 0.6 0.08 0.167 0.077 0.8 0.1 0.185 0.095 1 2. Plot a graph between Fg versus slope for the best fit line. And experiment value of K for spring by using the slope of graph? in your graph book. And from graph calculate thearrow_forwardA particle with kinetic energy equal to 233 J has a momentum of magnitude 22.4 kg · m/s. Calculate the speed (in m/s) and the mass (in kg) of the particle.arrow_forward
- An object has a kinetic energy of 304 J and a momentum of magnitude 24.7 kg · m/s. Answer parts a-b.arrow_forwardA 0.50 g/cm³ B 0.80 g/cm³ C 1.40 g/cm³ D 2.00 g/cm³ 20g 20g /40cm² = 0.5g/cm 10 A cube of side 2 cm is placed in a graduated measuring cylinder. 145 cm³ of oil is then added and the cube remains at the bottom of the cylinder. What will be the reading on the measuring cylinder? A 147 cm³ B 149 cm³ C 151 cm³ 153 cm³ D Structured Questions (Paper 2 Section A) 1 The diameter of a screw was measured as accurately as possible using the following instruments: a micrometer, vernier calipers and a metre rule. The table below shows the readings obtained. Complete the table to inarrow_forwardAn object has a kinetic energy of 312 J and a momentum of magnitude 29.3 kg · m/s. (a) Find the speed of the object. _____m/s (b) Find the mass of the object. ______kgarrow_forward
- A particle P of mass m = 0.56 kg is released from rest at a point h = 7 m above the surface of a liquid in a container. P falls through the air into the liquid. Assume there is no air resistance and there is no instantaneous change in speed of P as it enters the liquid. When P is at a distance of d = 0.71 m below the surface of the liquid, P's speed is v = 4.9 m/s. The only force acting on P due to the liquid is a constant resistance to motion of magnitude R N. Find the following: v1: The speed (in m/s) of P the moment just before it strikes the surface of the fluid.a1: The magnitude of the deceleration (in m/s2) of P while it is falling through the liquid.R: The magnitude of the resistance force (in N). The depth of the liquid in the container is dp = 3.9 m. P is taken from the container and attached to one end of a light inextensible string. P is placed at the bottom of the container and then pulled vertical upwards with a constant acceleration, a2. The resistance force to motion R N…arrow_forwardif A⃗ =2i+3j+6kA→=2i+3j+6k and A⃗ =3i−4j+2kA→=3i−4j+2k, then the angle between the two vectors isarrow_forwardA 2.29 µg particle moves at 2.03 × 10° m/s. What is its momentum p? 0.464 p = kg-m/s Incorrectarrow_forward
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