Chapter 11, Problem 16SGR

To determine

To find: The area of the trapezium.

Answer to Problem 16SGR

The area of the trapezium is $84f{t}^2$ .

Explanation of Solution

Given Information: Parallel sides of trapezium are $8ft,4ft$ and height is $14ft$ .

Parallel sides of trapezium are $8ft,4ft$ and height is $14ft$ .

Area of trapezium is:

  $\begin{array}{l}=\frac{1}{2}(sumofparallelsides)\times height\\ =\frac{1}{2}(8+4)\times 14\\ =\frac{1}{2}(12)\times 14\\ =6\times 14\\ =84f{t}^2\end{array}$

Thus, the area of the trapezium is $84f{t}^2$ .