Pre-Algebra, Student Edition
Pre-Algebra, Student Edition
1st Edition
ISBN: 9780078885150
Author: McGraw-Hill
Publisher: Glencoe/McGraw-Hill
bartleby

Concept explainers

Contingency Table
A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear re…
Binomial Distribution
Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.
bartleby

Videos

Question
Book Icon
Chapter 1.1, Problem 37HP

(a)

To determine

To find:the expression for the number of centimeters in 200 inches.

(a)

Expert Solution
Check Mark

Answer to Problem 37HP

The expression for number of centimeters in 200 inches is 200(2.54)

There are 508 cm in 200 inches.

Explanation of Solution

Given:

One package contains 350 centimeters of trim.

The second package contains 200 inches of trim.

Calculation:

Now, 1 inch ≈ 2.54 cm

Then, to find number of cm in 200 inches, multiply 200 by the number of cm in 1 inch.

That is, 200(2.54)

  200 inch = 200(2.54) cm=508 cm

Thus the expression for number of centimeters in 200 inches is 200(2.54)

And there are 508 cm in 200 inches.

Conclusion:

Thus the expression for number of centimeters in 200 inches is 200(2.54)

There are 508 cm in 200 inches.

(b)

To determine

To find: The total number of centimeters of trim in two packages.

(b)

Expert Solution
Check Mark

Answer to Problem 37HP

Thus, total number of centimeters in the two packages 858cm

Explanation of Solution

Given:

One package contains 350 centimeters of trim. The second package contains 200 inches of trim.

Calculation:

Total number of centimeters in the two packages is equal to the sum of number of centimeters in the first package (given in question) and number of centimeters in the second package (obtained in part (a))

Thus, total number of centimeters in the two packages = 350+508=858cm

Conclusion:

Therefore, total number of centimeters in the two packages = 350+508=858cm

(c)

To determine

To find: the number of packages of trim that have thesame amount of trim from part b

(c)

Expert Solution
Check Mark

Answer to Problem 37HP

Thus, he needs to buy about 4 packages of 90 inches trim.

Explanation of Solution

Given:

One package contains 350 centimeters of trim. The second package contains 200 inches of trim.

Calculation:

Leah wants to buy 858 cm of trim in total.

If he buyspackages which contains 90 inches of trims each, then find total number of such packages that he needs to buy to have total 858 cm of trim.

Since, 1 inch = 2.54 cm

Then, number of cm in 90 inches is.

90 inch = 90(2.54) cm

≈ 229 cm

That is, 1 package contains nearly 229 cm of trim.

To find the number of packages that he needs to buy to have 858 cm of trim, divide 858 by 229.

Total number of packages he needs to buy is given by

  858÷229≈3.75

Thus, he needs to buy about 4 packages of 90 inches trim.

Conclusion:

Therefore, he needs to buy about 4 packages of 90 inches trim

Previous
Chapter 1.1, Problem 36HP
Next
Chapter 1.1, Problem 38HP

Chapter 1 Solutions

Pre-Algebra, Student Edition

Ch. 1.1 - Prob. 1ACYPCh. 1.1 - Prob. 1BCYPCh. 1.1 - Prob. 2ACYPCh. 1.1 - Prob. 2BCYPCh. 1.1 - Prob. 2CCYPCh. 1.1 - Prob. 2DCYPCh. 1.1 - Prob. 3CYPCh. 1.1 - Prob. 1CYUCh. 1.1 - Prob. 2CYUCh. 1.1 - Prob. 3CYU
Ch. 1.1 - Prob. 4CYUCh. 1.1 - Prob. 5CYUCh. 1.1 - Prob. 6CYUCh. 1.1 - Prob. 7CYUCh. 1.1 - Prob. 8CYUCh. 1.1 - Prob. 9CYUCh. 1.1 - Prob. 10CYUCh. 1.1 - Prob. 11CYUCh. 1.1 - Prob. 12PPSCh. 1.1 - Prob. 13PPSCh. 1.1 - Prob. 14PPSCh. 1.1 - Prob. 15PPSCh. 1.1 - Prob. 16PPSCh. 1.1 - Prob. 17PPSCh. 1.1 - Prob. 18PPSCh. 1.1 - Prob. 19PPSCh. 1.1 - Prob. 20PPSCh. 1.1 - Prob. 21PPSCh. 1.1 - Prob. 22PPSCh. 1.1 - Prob. 23PPSCh. 1.1 - Prob. 24PPSCh. 1.1 - Prob. 25PPSCh. 1.1 - Prob. 26PPSCh. 1.1 - Prob. 27PPSCh. 1.1 - Prob. 28PPSCh. 1.1 - Prob. 29PPSCh. 1.1 - Prob. 30PPSCh. 1.1 - Prob. 31PPSCh. 1.1 - Prob. 32PPSCh. 1.1 - Prob. 33PPSCh. 1.1 - Prob. 34HPCh. 1.1 - Prob. 35HPCh. 1.1 - Prob. 36HPCh. 1.1 - Prob. 37HPCh. 1.1 - Prob. 38HPCh. 1.1 - Prob. 39STPCh. 1.1 - Prob. 40STPCh. 1.1 - Prob. 41STPCh. 1.1 - Prob. 42STPCh. 1.2 - Prob. 1ACYPCh. 1.2 - Prob. 1BCYPCh. 1.2 - Prob. 2ACYPCh. 1.2 - Prob. 2BCYPCh. 1.2 - Prob. 3ACYPCh. 1.2 - Prob. 3BCYPCh. 1.2 - Prob. 3CCYPCh. 1.2 - Prob. 4CYPCh. 1.2 - Prob. 1CYUCh. 1.2 - Prob. 2CYUCh. 1.2 - Prob. 3CYUCh. 1.2 - Prob. 4CYUCh. 1.2 - Prob. 5CYUCh. 1.2 - Prob. 6CYUCh. 1.2 - Prob. 7CYUCh. 1.2 - Prob. 8CYUCh. 1.2 - Prob. 9CYUCh. 1.2 - Prob. 10CYUCh. 1.2 - Prob. 11CYUCh. 1.2 - Prob. 12PPSCh. 1.2 - Prob. 13PPSCh. 1.2 - Prob. 14PPSCh. 1.2 - Prob. 15PPSCh. 1.2 - Prob. 16PPSCh. 1.2 - Prob. 17PPSCh. 1.2 - Prob. 18PPSCh. 1.2 - Prob. 19PPSCh. 1.2 - Prob. 20PPSCh. 1.2 - Prob. 21PPSCh. 1.2 - Prob. 22PPSCh. 1.2 - Prob. 23PPSCh. 1.2 - Prob. 24PPSCh. 1.2 - Prob. 25PPSCh. 1.2 - Prob. 26PPSCh. 1.2 - Prob. 27PPSCh. 1.2 - Prob. 28PPSCh. 1.2 - Prob. 29PPSCh. 1.2 - Prob. 30PPSCh. 1.2 - Prob. 31PPSCh. 1.2 - Prob. 32PPSCh. 1.2 - Prob. 33PPSCh. 1.2 - Prob. 34PPSCh. 1.2 - Prob. 35PPSCh. 1.2 - Prob. 36PPSCh. 1.2 - Prob. 37PPSCh. 1.2 - Prob. 38PPSCh. 1.2 - Prob. 39PPSCh. 1.2 - Prob. 40PPSCh. 1.2 - Prob. 41HPCh. 1.2 - Prob. 42HPCh. 1.2 - Prob. 43HPCh. 1.2 - Prob. 44HPCh. 1.2 - Prob. 45STPCh. 1.2 - Prob. 46STPCh. 1.2 - Prob. 47STPCh. 1.2 - Prob. 48STPCh. 1.2 - Prob. 49SRCh. 1.2 - Prob. 50SRCh. 1.2 - Prob. 51SRCh. 1.2 - Prob. 52SRCh. 1.2 - Prob. 53SRCh. 1.2 - Prob. 54SRCh. 1.2 - Prob. 55SRCh. 1.2 - Prob. 56SRCh. 1.2 - Prob. 57SRCh. 1.2 - Prob. 58SRCh. 1.2 - Prob. 59SRCh. 1.2 - Prob. 60SRCh. 1.2 - Prob. 61SCh. 1.2 - Prob. 62SCh. 1.2 - Prob. 63SCh. 1.2 - Prob. 64SCh. 1.3 - Prob. 1CYPCh. 1.3 - Prob. 2ACYPCh. 1.3 - Prob. 2BCYPCh. 1.3 - Prob. 2CCYPCh. 1.3 - Prob. 2DCYPCh. 1.3 - Prob. 3ACYPCh. 1.3 - Prob. 3BCYPCh. 1.3 - Prob. 4CYPCh. 1.3 - Prob. 1CYUCh. 1.3 - Prob. 2CYUCh. 1.3 - Prob. 3CYUCh. 1.3 - Prob. 4CYUCh. 1.3 - Prob. 5CYUCh. 1.3 - Prob. 6CYUCh. 1.3 - Prob. 7CYUCh. 1.3 - Prob. 8CYUCh. 1.3 - Prob. 9CYUCh. 1.3 - Prob. 10CYUCh. 1.3 - Prob. 11CYUCh. 1.3 - Prob. 12CYUCh. 1.3 - Prob. 13CYUCh. 1.3 - Prob. 14CYUCh. 1.3 - Prob. 15PPSCh. 1.3 - Prob. 16PPSCh. 1.3 - Prob. 17PPSCh. 1.3 - Prob. 18PPSCh. 1.3 - Prob. 19PPSCh. 1.3 - Prob. 20PPSCh. 1.3 - Prob. 21PPSCh. 1.3 - Prob. 22PPSCh. 1.3 - Prob. 23PPSCh. 1.3 - Prob. 24PPSCh. 1.3 - Prob. 25PPSCh. 1.3 - Prob. 26PPSCh. 1.3 - Prob. 27PPSCh. 1.3 - Prob. 28PPSCh. 1.3 - Prob. 29PPSCh. 1.3 - Prob. 30PPSCh. 1.3 - Prob. 31PPSCh. 1.3 - Prob. 32PPSCh. 1.3 - Prob. 33PPSCh. 1.3 - Prob. 34PPSCh. 1.3 - Prob. 35PPSCh. 1.3 - Prob. 36PPSCh. 1.3 - Prob. 37PPSCh. 1.3 - Prob. 38PPSCh. 1.3 - Prob. 39PPSCh. 1.3 - Prob. 40PPSCh. 1.3 - Prob. 41PPSCh. 1.3 - Prob. 42PPSCh. 1.3 - Prob. 43PPSCh. 1.3 - Prob. 44HPCh. 1.3 - Prob. 45HPCh. 1.3 - Prob. 46HPCh. 1.3 - Prob. 47HPCh. 1.3 - Prob. 48HPCh. 1.3 - Prob. 49STPCh. 1.3 - Prob. 50STPCh. 1.3 - Prob. 51STPCh. 1.3 - Prob. 52STPCh. 1.3 - Prob. 53SRCh. 1.3 - Prob. 54SRCh. 1.3 - Prob. 55SRCh. 1.3 - Prob. 56SRCh. 1.3 - Prob. 57SRCh. 1.3 - Prob. 58SRCh. 1.3 - Prob. 59SRCh. 1.3 - Prob. 60SRCh. 1.3 - Prob. 61SRCh. 1.3 - Prob. 62SRCh. 1.3 - Prob. 63SRCh. 1.3 - Prob. 64SCh. 1.3 - Prob. 65SCh. 1.3 - Prob. 66SCh. 1.3 - Prob. 67SCh. 1.3 - Prob. 68SCh. 1.3 - Prob. 69SCh. 1.3 - Prob. 70SCh. 1.3 - Prob. 71SCh. 1.4 - Prob. 1ACYPCh. 1.4 - Prob. 1BCYPCh. 1.4 - Prob. 1CCYPCh. 1.4 - Prob. 1DCYPCh. 1.4 - Prob. 2ACYPCh. 1.4 - Prob. 2BCYPCh. 1.4 - Prob. 3CYPCh. 1.4 - Prob. 4ACYPCh. 1.4 - Prob. 4BCYPCh. 1.4 - Prob. 1CYUCh. 1.4 - Prob. 2CYUCh. 1.4 - Prob. 3CYUCh. 1.4 - Prob. 4CYUCh. 1.4 - Prob. 5CYUCh. 1.4 - Prob. 6CYUCh. 1.4 - Prob. 7CYUCh. 1.4 - Prob. 8CYUCh. 1.4 - Prob. 9CYUCh. 1.4 - Prob. 10CYUCh. 1.4 - Prob. 11CYUCh. 1.4 - Prob. 12PPSCh. 1.4 - Prob. 13PPSCh. 1.4 - Prob. 14PPSCh. 1.4 - Prob. 15PPSCh. 1.4 - Prob. 16PPSCh. 1.4 - Prob. 17PPSCh. 1.4 - Prob. 18PPSCh. 1.4 - Prob. 19PPSCh. 1.4 - Prob. 20PPSCh. 1.4 - Prob. 21PPSCh. 1.4 - Prob. 22PPSCh. 1.4 - Prob. 23PPSCh. 1.4 - Prob. 24PPSCh. 1.4 - Prob. 25PPSCh. 1.4 - Prob. 26PPSCh. 1.4 - Prob. 27PPSCh. 1.4 - Prob. 28PPSCh. 1.4 - Prob. 29PPSCh. 1.4 - Prob. 30PPSCh. 1.4 - Prob. 31PPSCh. 1.4 - Prob. 32PPSCh. 1.4 - Prob. 33PPSCh. 1.4 - Prob. 34PPSCh. 1.4 - Prob. 35PPSCh. 1.4 - Prob. 36HPCh. 1.4 - Prob. 37HPCh. 1.4 - Prob. 38HPCh. 1.4 - Prob. 39HPCh. 1.4 - Prob. 40HPCh. 1.4 - Prob. 41STPCh. 1.4 - Prob. 42STPCh. 1.4 - Prob. 43STPCh. 1.4 - Prob. 44STPCh. 1.4 - Prob. 45SRCh. 1.4 - Prob. 46SRCh. 1.4 - Prob. 47SRCh. 1.4 - Prob. 48SRCh. 1.4 - Prob. 49SRCh. 1.4 - Prob. 50SRCh. 1.4 - Prob. 51SRCh. 1.4 - Prob. 52SCh. 1.4 - Prob. 53SCh. 1.4 - Prob. 54SCh. 1.4 - Prob. 55SCh. 1.4 - Prob. 56SCh. 1.4 - Prob. 57SCh. 1.5 - Prob. 1CYPCh. 1.5 - Prob. 2ACYPCh. 1.5 - Prob. 2BCYPCh. 1.5 - Prob. 1CYUCh. 1.5 - Prob. 2CYUCh. 1.5 - Prob. 3CYUCh. 1.5 - Prob. 4PPSCh. 1.5 - Prob. 5PPSCh. 1.5 - Prob. 6PPSCh. 1.5 - Prob. 7PPSCh. 1.5 - Prob. 8PPSCh. 1.5 - Prob. 9PPSCh. 1.5 - Prob. 10PPSCh. 1.5 - Prob. 11PPSCh. 1.5 - Prob. 12HPCh. 1.5 - Prob. 13HPCh. 1.5 - Prob. 14HPCh. 1.5 - Prob. 15STPCh. 1.5 - Prob. 16STPCh. 1.5 - Prob. 17STPCh. 1.5 - Prob. 18STPCh. 1.5 - Prob. 19SRCh. 1.5 - Prob. 20SRCh. 1.5 - Prob. 21SRCh. 1.5 - Prob. 22SRCh. 1.5 - Prob. 23SRCh. 1.5 - Prob. 24SRCh. 1.5 - Prob. 25SRCh. 1.5 - Prob. 26SRCh. 1.5 - Prob. 27SRCh. 1.5 - Prob. 28SRCh. 1.5 - Prob. 29SRCh. 1.5 - Prob. 30SRCh. 1.5 - Prob. 31SRCh. 1.5 - Prob. 32SCh. 1.5 - Prob. 33SCh. 1.5 - Prob. 34SCh. 1.5 - Prob. 35SCh. 1.6 - Prob. 1CYPCh. 1.6 - Prob. 2CYPCh. 1.6 - Prob. 3ACYPCh. 1.6 - Prob. 3BCYPCh. 1.6 - Prob. 3CCYPCh. 1.6 - Prob. 1CYUCh. 1.6 - Prob. 2PPSCh. 1.6 - Prob. 3PPSCh. 1.6 - Prob. 4PPSCh. 1.6 - Prob. 5PPSCh. 1.6 - Prob. 6PPSCh. 1.6 - Prob. 7PPSCh. 1.6 - Prob. 8PPSCh. 1.6 - Prob. 9PPSCh. 1.6 - Prob. 10PPSCh. 1.6 - Prob. 11PPSCh. 1.6 - Prob. 12PPSCh. 1.6 - Prob. 13PPSCh. 1.6 - Prob. 14PPSCh. 1.6 - Prob. 15PPSCh. 1.6 - Prob. 16HPCh. 1.6 - Prob. 17HPCh. 1.6 - Prob. 18HPCh. 1.6 - Prob. 19HPCh. 1.6 - Prob. 20HPCh. 1.6 - Prob. 21HPCh. 1.6 - Prob. 22HPCh. 1.6 - Prob. 23STPCh. 1.6 - Prob. 24STPCh. 1.6 - Prob. 25STPCh. 1.6 - Prob. 26STPCh. 1.6 - Prob. 27SRCh. 1.6 - Prob. 28SRCh. 1.6 - Prob. 29SRCh. 1.6 - Prob. 30SRCh. 1.6 - Prob. 31SRCh. 1.6 - Prob. 32SRCh. 1.6 - Prob. 33SRCh. 1.6 - Prob. 34SCh. 1.6 - Prob. 35SCh. 1.6 - Prob. 36SCh. 1.6 - Prob. 37SCh. 1.6 - Prob. 38SCh. 1.6 - Prob. 39SCh. 1 - Prob. 1QCCh. 1 - Prob. 2QCCh. 1 - Prob. 3QCCh. 1 - Prob. 4QCCh. 1 - Prob. 5QCCh. 1 - Prob. 6QCCh. 1 - Prob. 7QCCh. 1 - Prob. 8QCCh. 1 - Prob. 9QCCh. 1 - Prob. 10QCCh. 1 - Prob. 11QCCh. 1 - Prob. 12QCCh. 1 - Prob. 13QCCh. 1 - Prob. 14QCCh. 1 - Prob. 15QCCh. 1 - Prob. 16QCCh. 1 - Prob. 17QCCh. 1 - Prob. 18QCCh. 1 - Prob. 19QCCh. 1 - Prob. 1MCQCh. 1 - Prob. 2MCQCh. 1 - Prob. 3MCQCh. 1 - Prob. 4MCQCh. 1 - Prob. 5MCQCh. 1 - Prob. 6MCQCh. 1 - Prob. 7MCQCh. 1 - Prob. 8MCQCh. 1 - Prob. 9MCQCh. 1 - Prob. 10MCQCh. 1 - Prob. 11MCQCh. 1 - Prob. 12MCQCh. 1 - Prob. 13MCQCh. 1 - Prob. 14MCQCh. 1 - Prob. 15MCQCh. 1 - Prob. 16MCQCh. 1 - Prob. 17MCQCh. 1 - Prob. 18MCQCh. 1 - Prob. 19MCQCh. 1 - Prob. 20MCQCh. 1 - Prob. 21MCQCh. 1 - Prob. 22MCQCh. 1 - Prob. 23MCQCh. 1 - Prob. 24MCQCh. 1 - Prob. 25MCQCh. 1 - Prob. 1SGRCh. 1 - Prob. 2SGRCh. 1 - Prob. 3SGRCh. 1 - Prob. 4SGRCh. 1 - Prob. 5SGRCh. 1 - Prob. 6SGRCh. 1 - Prob. 7SGRCh. 1 - Prob. 8SGRCh. 1 - Prob. 9SGRCh. 1 - Prob. 10SGRCh. 1 - Prob. 11SGRCh. 1 - Prob. 12SGRCh. 1 - Prob. 13SGRCh. 1 - Prob. 14SGRCh. 1 - Prob. 15SGRCh. 1 - Prob. 16SGRCh. 1 - Prob. 17SGRCh. 1 - Prob. 18SGRCh. 1 - Prob. 19SGRCh. 1 - Prob. 20SGRCh. 1 - Prob. 21SGRCh. 1 - Prob. 22SGRCh. 1 - Prob. 23SGRCh. 1 - Prob. 24SGRCh. 1 - Prob. 25SGRCh. 1 - Prob. 26SGRCh. 1 - Prob. 27SGRCh. 1 - Prob. 28SGRCh. 1 - Prob. 29SGRCh. 1 - Prob. 30SGRCh. 1 - Prob. 1PTCh. 1 - Prob. 2PTCh. 1 - Prob. 3PTCh. 1 - Prob. 4PTCh. 1 - Prob. 5PTCh. 1 - Prob. 6PTCh. 1 - Prob. 7PTCh. 1 - Prob. 8PTCh. 1 - Prob. 9PTCh. 1 - Prob. 10PTCh. 1 - Prob. 11PTCh. 1 - Prob. 12PTCh. 1 - Prob. 13PTCh. 1 - Prob. 14PTCh. 1 - Prob. 15PTCh. 1 - Prob. 16PTCh. 1 - Prob. 17PTCh. 1 - Prob. 18PTCh. 1 - Prob. 19PTCh. 1 - Prob. 20PTCh. 1 - Prob. 21PTCh. 1 - Prob. 22PTCh. 1 - Prob. 23PTCh. 1 - Prob. 24PTCh. 1 - Prob. 25PTCh. 1 - Prob. 1ECh. 1 - Prob. 2ECh. 1 - Prob. 3ECh. 1 - Prob. 4ECh. 1 - Prob. 1STPCh. 1 - Prob. 2STPCh. 1 - Prob. 3STPCh. 1 - Prob. 4STPCh. 1 - Prob. 5STPCh. 1 - Prob. 6STPCh. 1 - Prob. 7STPCh. 1 - Prob. 8STPCh. 1 - Prob. 9STPCh. 1 - Prob. 10STPCh. 1 - Prob. 11STP

Additional Math Textbook Solutions

Find more solutions based on key concepts
EXTENSIONS If a whole number is not a natural number, what must the number be?

College Algebra

Explain why the columns of an n n; matrix A are linearly independent when A is invertible.

Linear Algebra and Its Applications (5th Edition)

Fill in each blanks so that the resulting statement is true. Any set of ordered pairs is called a/an _______. T...

College Algebra

Solve (c2)(c+8)=7 by completing the square.

Elementary Algebra

Fill in each blanks so that the resulting statement is true. Any set of ordered pairs is called a/an _______. T...

College Algebra (7th Edition)

Simplify: 11y2+8y+y2+7y

PREALGEBRA

Knowledge Booster
Background pattern image
Algebra
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Algebra and Trigonometry (6th Edition)
Algebra
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:PEARSON
Text book image
Contemporary Abstract Algebra
Algebra
ISBN:9781305657960
Author:Joseph Gallian
Publisher:Cengage Learning
Text book image
Linear Algebra: A Modern Introduction
Algebra
ISBN:9781285463247
Author:David Poole
Publisher:Cengage Learning
Text book image
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:9780135163078
Author:Michael Sullivan
Publisher:PEARSON
Text book image
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:9780980232776
Author:Gilbert Strang
Publisher:Wellesley-Cambridge Press
Text book image
College Algebra (Collegiate Math)
Algebra
ISBN:9780077836344
Author:Julie Miller, Donna Gerken
Publisher:McGraw-Hill Education
SEE MORE TEXTBOOKS
Mod-01 Lec-01 Discrete probability distributions (Part 1); Author: nptelhrd;https://www.youtube.com/watch?v=6x1pL9Yov1k;License: Standard YouTube License, CC-BY
Discrete Probability Distributions; Author: Learn Something;https://www.youtube.com/watch?v=m9U4UelWLFs;License: Standard YouTube License, CC-BY
Probability Distribution Functions (PMF, PDF, CDF); Author: zedstatistics;https://www.youtube.com/watch?v=YXLVjCKVP7U;License: Standard YouTube License, CC-BY
Discrete Distributions: Binomial, Poisson and Hypergeometric | Statistics for Data Science; Author: Dr. Bharatendra Rai;https://www.youtube.com/watch?v=lHhyy4JMigg;License: Standard Youtube License