Chapter 1.6, Problem 27SR

a.

To determine

To write: An expression to find the monthly cost of a cable service.

Answer to Problem 27SR

The algebraic equation that can be used to find monthly cost of a cable service is $\text{number of days in a month}*\left(\$32.50\right)$ .

Explanation of Solution

Given information:

The charges of a cable is $\$32.50$ .

Formula:

Cost of a cornet cable charges for a month.

Consider the statement monthly cost of a cable service.

Recall that cost of a cornet cable charges for a month and the charges of a cable is $\$32.50$ .

Therefore the expression of monthly cost will be $\text{number of days in a month}*\left(\$32.50\right)$ .

b.

To determine

To complete: The function table for monthly cost of premium channels.

Answer to Problem 27SR

The function table formonthly cost of premium channels is mentioned below.

  $\begin{array}{cc} \text{premium channels}& \text{monthly cost}\\ 0& 0\\ 1& \$4.95\\ 2& \$9.90\\ 3& \$14.85\\ 4& \$19.80\end{array}$

Explanation of Solution

Given information:

The premium channels is mentioned in the problem $0,1,2,3,4$ .

Formula:

Monthly cost of premium channels = $\left(\text{number of premium channels}\right)*\left(\$4.95\right)$ .

Calculation:

Consider the statement the premium channels is mentioned in the problem $0,1,2,3,4$ .

Recall that monthly cost of premium channels = $\left(\text{number of premium channels}\right)*\left(\$4.95\right)$ .

Therefore if no. of premium channels is $0$ then monthly cost is $0*\$4.95=0$ .

Ifno. of premium channels is $1$ then monthly cost is $1*\$4.95=\$4.95$ .

Ifno. of premium channels is $2$ then monthly cost is $2*\$4.95=\$9.90$ .

Ifno. of premium channels is $3$ then monthly cost is $3*\$4.95=\$14.85$ .

Ifno. of premium channels is $4$ then monthly cost is $4*\$4.95=\$19.80$ .

Therefore the monthly cost table is mentioned below.

  $\begin{array}{cc} \text{premium channels}& \text{monthly cost}\\ 0& 0\\ 1& \$4.95\\ 2& \$9.90\\ 3& \$14.85\\ 4& \$19.80\end{array}$

c.

To determine

To graph: The ordered pairs of the function table mentioned below.

  $\begin{array}{cc} \text{premium channels}& \text{monthly cost}\\ 0& 0\\ 1& \$4.95\\ 2& \$9.90\\ 3& \$14.85\\ 4& \$19.80\end{array}$

Answer to Problem 27SR

The graph mentioned below represents x axis as premium channels and y axis as monthly cost.

  

Explanation of Solution

Given information:

The function table is mentioned below.

  $\begin{array}{cc} \text{premium channels}& \text{monthly cost}\\ 0& 0\\ 1& \$4.95\\ 2& \$9.90\\ 3& \$14.85\\ 4& \$19.80\end{array}$

Graph:

The graph plotted below represents x axis as premium channels and y axis as monthly cost.

  

Interpretation:

Consider the statement to graph the function table as mentioned below.

Recall that the function table is

  $\begin{array}{cc} \text{premium channels}& \text{monthly cost}\\ 0& 0\\ 1& \$4.95\\ 2& \$9.90\\ 3& \$14.85\\ 4& \$19.80\end{array}$ .

Here we consider premium channels as x axis and monthly cost as y axis.

Therefore the graph we observed above is the graph of function table.

d.

To determine

Given information:

Let Malik age be $x$ .

Answer to Problem 27SR

Formula:

Luz age is three times than Malik age.

Explanation of Solution

Consider the statement let Malik age be $x$ .

Recall that Luz age is three times than Malik age.

Therefore if we consider the Malik age be $x$ then the Luz age is $3x$ .

e.

To determine

To complete: The function table for Luz age and Malik age.

Answer to Problem 27SR

The function table for Luz age and Malik age is mentioned below.

  $\begin{array}{cc}\text{Malik's age}\left(x\right)& \text{Luz's age}\left(3x\right)\\ 1& 3\\ 2& 6\\ 3& 9\\ 4& 12\\ 5& 15\end{array}$

Explanation of Solution

Given information:

The Malik age is mentioned in the problem $1,2,3,4or5$ .

Formula:

Let Malik age be $x$ then the Luz age is $3x$ .

Calculation:

Consider the statement the Malik age is mentioned in the problem $1,2,3,4or5$ .

Recall that if Malik age be $x$ then the Luz age is $3x$ .

Therefore if Malik age is $1$ then Luz age is $3*1=3$ .

If Malik age is $2$ then Luz age is $3*2=6$ .

If Malik age is $3$ then Luz age is $3*3=9$ .

If Malik age is $4$ then Luz age is $3*4=12$ .

If Malik age is $5$ then Luz age is $3*5=15$ .

Therefore the age table is mentioned below.

  $\begin{array}{cc}\text{Malik's age}\left(x\right)& \text{Luz's age}\left(3x\right)\\ 1& 3\\ 2& 6\\ 3& 9\\ 4& 12\\ 5& 15\end{array}$

f.

To determine

To graph: The ordered pairs of the function table mentioned below.

  $\begin{array}{cc}\text{Malik's age}\left(x\right)& \text{Luz's age}\left(3x\right)\\ 1& 3\\ 2& 6\\ 3& 9\\ 4& 12\\ 5& 15\end{array}$

Answer to Problem 27SR

The graph mentioned below represents x axis as Malik’s age and y axis as Luz’ age.

  

Explanation of Solution

Given information:

The function table is mentioned below.

  $\begin{array}{cc}\text{Malik's age}\left(x\right)& \text{Luz's age}\left(3x\right)\\ 1& 3\\ 2& 6\\ 3& 9\\ 4& 12\\ 5& 15\end{array}$

Graph:

The graph plotted below represents x axis as Malik age and y axis as Luz age.

  

Interpretation:

Consider the statement to graph the function table as mentioned below.

Recall that the function table is

  $\begin{array}{cc}\text{Malik's age}\left(x\right)& \text{Luz's age}\left(3x\right)\\ 1& 3\\ 2& 6\\ 3& 9\\ 4& 12\\ 5& 15\end{array}$ .

Here we consider Malik age as x axis and Luz age as y axis.

Therefore the graph we observed above is the graph of function table.