Chapter 11, Problem 4PEA

(a)

To determine

The nuclear equation for the beta emission decay for $\text{F}\text{e}$.

Answer to Problem 4PEA

The nuclear equation for the beta emission decay for $\text{F}\text{e}$ is $\text{F}\text{e}\to \text{C}\text{o}+e$.

Explanation of Solution

The nuclear equation for the beta emission decay for the given element is given as,

    $\text{X}\to \text{Y}+\text{e}$

Here, $\text{X}$ is the given element which has $p$ number of proton and has $q$ atomic mass and $\text{Y}$ is the element which has $\left(p+1\right)$ number of protons and has $q$ atomic mass after beta emission decay of the given element.

Thus the nuclear equation for the beta emission decay of $\text{F}\text{e}$ is given as,

    $\text{F}\text{e}\to \text{C}\text{o}+e$

(b)

To determine

The nuclear equation for the beta emission decay for $\text{B}\text{e}$.

Answer to Problem 4PEA

The nuclear equation for the beta emission decay for $\text{B}\text{e}$ is $\text{B}\text{e}\to \text{B}+\text{e}$.

Explanation of Solution

The nuclear equation for the beta emission decay for the given element is given as,

    $\text{X}\to \text{Y}+\text{e}$

Here, $\text{X}$ is the given element which has $p$ number of proton and has $q$ atomic mass and $\text{Y}$ is the element which has $\left(p+1\right)$ number of protons and has $q$ atomic mass after beta emission decay of the given element.

Thus the nuclear equation for the beta emission decay of $\text{B}\text{e}$ is given as,

    $\text{B}\text{e}\to \text{B}+\text{e}$

(c)

To determine

The nuclear equation for the beta emission decay for $\text{C}\text{u}$.

Answer to Problem 4PEA

The nuclear equation for the beta emission decay for $\text{C}\text{u}$ is $\text{C}\text{u}\to \text{Z}\text{n}+\text{e}$.

Explanation of Solution

The nuclear equation for the beta emission decay for the given element is given as,

    $\text{X}\to \text{Y}+\text{e}$

Here, $\text{X}$ is the given element which has $p$ number of proton and has $q$ atomic mass and $\text{Y}$ is the element which has $\left(p+1\right)$ number of protons and has $q$ atomic mass after beta emission decay of the given element.

Thus the nuclear equation for the beta emission decay of $\text{C}\text{u}$ is given as,

    $\text{C}\text{u}\to \text{Z}\text{n}+\text{e}$

(d)

To determine

The nuclear equation for the beta emission decay for $\text{N}\text{a}$.

Answer to Problem 4PEA

The nuclear equation for the beta emission decay for $\text{N}\text{a}$ is $\text{N}\text{a}\to \text{A}\text{m}+\text{e}$.

Explanation of Solution

The nuclear equation for the beta emission decay for the given element is given as,

    $\text{X}\to \text{Y}+\text{e}$

Here, $\text{X}$ is the given element which has $p$ number of proton and has $q$ atomic mass and $\text{Y}$ is the element which has $\left(p+1\right)$ number of protons and has $q$ atomic mass after beta emission decay of the given element.

Thus the nuclear equation for the beta emission decay of $\text{N}\text{a}$ is given as,

    $\text{N}\text{a}\to \text{A}\text{m}+\text{e}$

(e)

To determine

The nuclear equation for the beta emission decay for $\text{P}\text{b}$.

Answer to Problem 4PEA

The nuclear equation for the beta emission decay for $\text{P}\text{b}$ is $\text{P}\text{b}\to \text{B}\text{i}+\text{e}$.

Explanation of Solution

The nuclear equation for the beta emission decay for the given element is given as,

    $\text{X}\to \text{Y}+\text{e}$

Here, $\text{X}$ is the given element which has $p$ number of proton and has $q$ atomic mass and $\text{Y}$ is the element which has $\left(p+1\right)$ number of protons and has $q$ atomic mass after beta emission decay of the given element.

Thus the nuclear equation for the beta emission decay of $\text{P}\text{b}$ is given as,

    $\text{P}\text{b}\to \text{B}\text{i}+\text{e}$

(f)

To determine

The nuclear equation for the beta emission decay for $\text{P}$.

Answer to Problem 4PEA

The nuclear equation for the beta emission decay for $\text{P}$ is $\text{P}\to \text{S}+\text{e}$.

Explanation of Solution

The nuclear equation for the beta emission decay for the given element is given as,

    $\text{X}\to \text{Y}+\text{e}$

Here, $\text{X}$ is the given element which has $p$ number of proton and has $q$ atomic mass and $\text{Y}$ is the element which has $\left(p+1\right)$ number of protons and has $q$ atomic mass after beta emission decay of the given element.

Thus the nuclear equation for the beta emission decay of $\text{P}$ is given as,

    $\text{P}\to \text{S}+\text{e}$