Campbell Biology In Focus
Campbell Biology In Focus
2nd Edition
ISBN: 9780134203072
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece
Publisher: PEARSON
Question
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Chapter 11, Problem 6TYU

(a)

Summary Introduction

To determine:

If both the parents are carriers of the hemochromatosis and have three children then what is the probability that; (a) All three children are of normal phenotype. (b) One or more of the three children have the disease, (c) All three children have the disease, (d) Atleast one child is phenotypically normal.

Introduction:

Hemochromatosis is a hereditary disease in which the iron from the blood gets deposited into the tissues. This causes the accumulation of the iron in the tissues that causes damage to the liver.

To determine:

If both the parents are carriers of the hemochromatosis and have three children then what is the probability that all three children are of normal phenotype.

(b)

Summary Introduction

To determine:

If both the parents are carriers of the hemochromatosis and have three children then what is the probability thatone or more of the three children have the disease.

(c)

Summary Introduction

To determine:

If both the parents are carriers of the hemochromatosis and have three children then what is the probability thatall three children have the disease.

(d)

Summary Introduction

To determine:

If both the parents are carriers of the hemochromatosis and have three children then what is the probability thatatleast one child is phenotypically normal.

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Students have asked these similar questions
An individual who is a carrier for a sex-linked trait such as hemophilia Select one: A. is always female. B. is homozygous for the recessive condition. C. cannot pass the gene on to his or her daughters. D. shows the dominant phenotype.
Hemophilia is a disease caused by a gene found on the X chromosome. Therefore, it is referred to as a sex-linked disease. The recessive allele causes the disease. A man with hemophilia (xhy) marries a woman who is homozygous dominant (XHXH. A. Illustrate using a Punnett square the probability that their children will have the disease. B. Will any of their children have the disease? C. Predict the probabilities of their children having the disease.
Hemophilia is a disease caused by a gene found on the X chromosome. Therefore, it is a sex-linked disease which is caused by the recessive allele. Suppose, a man with hemophilia marries a woman who is homozygous dominant for the trait, what is the chance of having children who are hemophiliacs? (XH = normal; Xh= hemophiliac) *       a. 0%   b. 75%   c. 100%   d. 25%
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