Chemistry For Changing Times (14th Edition)
Chemistry For Changing Times (14th Edition)
14th Edition
ISBN: 9780321972026
Author: John W. Hill, Terry W. McCreary
Publisher: PEARSON
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Chapter 11, Problem 71AP

(a)

Interpretation Introduction

Interpretation:

Percentage of potassium-40 remaining after a decay of 3.6 billion years has to be calculated, considering the half-life of potassium-40 is 1.2 billion years.

Concept introduction:

As per the data given, the age of rocks and the other matter can be determined using several different radio tapes such as carbon − 14. When it comes to geosciences, potassium-40 is used to determine the age of rocks and it decays into argon-40 with a half-life of 1.2 years.

All radioactive reactions follow first order kinetics thus, the rate equation will be:

  Chemistry For Changing Times (14th Edition), Chapter 11, Problem 71AP , additional homework tip  1

Here, k is rate constant, t is time taken by a reaction, Chemistry For Changing Times (14th Edition), Chapter 11, Problem 71AP , additional homework tip  2is initial concentration of A and Chemistry For Changing Times (14th Edition), Chapter 11, Problem 71AP , additional homework tip  3is concentration of reactant A at time t.

Also, the relation between rate constant and half-life time is:

  Chemistry For Changing Times (14th Edition), Chapter 11, Problem 71AP , additional homework tip  4

(b)

Interpretation Introduction

Interpretation:

A reason should be provided to support the statement that uranium-238 is more useful for confirming the age than carbon-14.

Concept introduction:

As per the given data, the age of rocks and other matter can be determined using several different radio tapes like carbon − 14 and the half-life of uranium-238 is mentioned as 4.6 billion years.

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Chapter 11 Solutions

Chemistry For Changing Times (14th Edition)

Ch. 11 - Prob. 11RQCh. 11 - Prob. 12RQCh. 11 - Prob. 13RQCh. 11 - Prob. 14RQCh. 11 - Prob. 15RQCh. 11 - Prob. 16RQCh. 11 - Prob. 17RQCh. 11 - Prob. 18PCh. 11 - Prob. 19PCh. 11 - Prob. 20PCh. 11 - Prob. 21PCh. 11 - Prob. 22PCh. 11 - Prob. 23PCh. 11 - Prob. 24PCh. 11 - Prob. 25PCh. 11 - Prob. 26PCh. 11 - Prob. 27PCh. 11 - Prob. 28PCh. 11 - Prob. 29PCh. 11 - Prob. 30PCh. 11 - Prob. 31PCh. 11 - Prob. 32PCh. 11 - Prob. 33PCh. 11 - Prob. 34PCh. 11 - Prob. 35PCh. 11 - Prob. 36PCh. 11 - Prob. 37PCh. 11 - Prob. 38PCh. 11 - Prob. 39PCh. 11 - Prob. 40PCh. 11 - Prob. 41PCh. 11 - Prob. 42PCh. 11 - Prob. 43PCh. 11 - Prob. 44PCh. 11 - Prob. 45PCh. 11 - Prob. 46PCh. 11 - Prob. 47PCh. 11 - Prob. 48PCh. 11 - Prob. 49PCh. 11 - Prob. 50PCh. 11 - Prob. 51PCh. 11 - Prob. 52PCh. 11 - Prob. 53PCh. 11 - Prob. 54PCh. 11 - Prob. 55PCh. 11 - Prob. 56PCh. 11 - Prob. 57PCh. 11 - Prob. 58APCh. 11 - Prob. 59APCh. 11 - Prob. 60APCh. 11 - Prob. 61APCh. 11 - Prob. 62APCh. 11 - Prob. 63APCh. 11 - Prob. 64APCh. 11 - Prob. 65APCh. 11 - Prob. 66APCh. 11 - Prob. 67APCh. 11 - Prob. 68APCh. 11 - Prob. 69APCh. 11 - Prob. 70APCh. 11 - Prob. 71APCh. 11 - Prob. 72APCh. 11 - Prob. 73APCh. 11 - Prob. 74APCh. 11 - Prob. 75APCh. 11 - Prob. 76APCh. 11 - Prob. 77APCh. 11 - Prob. 78APCh. 11 - Prob. 11.1CTECh. 11 - Prob. 11.2CTECh. 11 - Prob. 11.3CTECh. 11 - Prob. 11.4CTECh. 11 - Prob. 11.5CTECh. 11 - Prob. 11.6CTECh. 11 - Prob. 1CGPCh. 11 - Prob. 2CGPCh. 11 - Prob. 3CGPCh. 11 - Prob. 4CGPCh. 11 - Prob. 5CGPCh. 11 - Prob. 6CGPCh. 11 - Prob. 7CGPCh. 11 - Prob. 8CGPCh. 11 - Prob. 1CHQCh. 11 - Prob. 2CHQCh. 11 - Prob. 3CHQCh. 11 - Prob. 4CHQ
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