Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 11, Problem 85P
To determine
To Calculate: Theperiod of Pluto’s orbital motion.
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The International Space Station (ISS) is a space station orbiting the earth above the ground. If the radius of the earth is 3,958.8 miles, mass of earth is 5.972 x 10 24 kg, the period of the ISS at the orbit around the earth is 14.137 hours, can you calculate what is the distance from the ISS to the surface of the earth, in unit of miles? Use G=6.674 x 10 -11 Nm2/kg2. Write your answer in pure numbers, for example, 4567.8. Please keep at least on digit after the decimal point.
The International Space Station (ISS) is a space station orbiting the earth above the ground. If the radius of the earth is 3,958.8 miles, mass of earth is 5.972 x 1024 kg, the period of the ISS at the orbit around the earth is 2.00 hours, can you calculate what is the distance from the ISS to the surface of the earth, in unit of miles? Use G=6.674 x 10-11 Nm2/kg2. Wirte answer in pure numbers.
The Magellan orbiter orbits Venus with a period of 3.26 hours. How far (in km) above the surface of the planet is it? (The mass of Venus is 4.87 ✕ 1024 kg, and the radius of Venus is 6.05 ✕ 103 km.)
Chapter 11 Solutions
Physics for Scientists and Engineers
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- Selected astronomical data for Jupiter's moon Adrastea is given in the table. From these data, calculate the mass of Jupiter (in kg). Moon Orbital Radius (km) Orbital Period (days) Adrastea 1.30 ✕ 105 0.30arrow_forwardThe International Space Station (ISS) is a space station orbiting the earth above the ground. If the radius of the earth is 3,958.8 miles, mass of earth is 5.972 x 10 24 kg, the period of the ISS at the orbit around the earth is 7.89 hours, can you calculate what is the distance from the ISS to the surface of the earth, in unit of miles? Use G-6.674 x 10-11 Nm2/kg2. Write your answer in pure numbers, for example, 4567.8. Please keep at least on digit after the decimal point.arrow_forwardA planet of mass 5.8 x 1024 kg orbits a star of mass 1.6 x 1030 kg in a circular orbit 10 x 1011 m from its center. Calculate the period of the orbit, in Earth years. Use G = 6.7 x 10-11 N m2/ kg2 and that one Earth year is 3.15 x 107 s. (Please answer to the fourth decimal place - i.e 14.3225)arrow_forward
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- Mars has an orbital radius of 1.523 AU and an orbital period of 687.0 days. What is its average speed v in SI units? (1 AU is the astronomical unit, the mean distance between the Sun and the Earth, which is 1.496×1011 m) a. 0.00221 AU/day b. 3838 m/s c. 0 d. 1.28×10−9 m/sarrow_forwardPlanet X orbits the star Omega with a "year" that is 492 days long. Planet Y circles Omega at four times the orbital distance of planet X. How many earth days is a year on planet Y? Enter units as d.arrow_forwardA synchronous satellite, which always remains above the same point on a planet's equator, is put in circular orbit around Neptune so that scientists can study a surface feature. Neptune rotates once every 16.1 h. Use the data of this table to find the altitude of the satellite. kmarrow_forward
- The Moon has a period of 27.3 days and a mean distance of 3.9x105 km from its center to the center of Earth. a)Use Kepler's laws to find the period of a satellite in orbit 6.70x 10 km from the center of Earth. b) How far above Earth's surface is this satellite?arrow_forwardThe orbit of a 1.5 x 1010 kg comet around the Sun is elliptical, with an aphelion distance of 11.0 AU and perihelion distance of 0.890 AU. (Note: 1 AU = one astronomical unit = the average distance from the Sun to the Earth = 1.496 x 101" m.) (a) What is its orbital eccentricity? (b) What is its period? (Enter your answer in yr.) yr (c) At aphelion what is the potential energy (in J) of the comet-Sun system?arrow_forwardThe mean distance of an asteroid from the Sun is 1.74 times that of Earth from the Sun. From Kepler's law of periods, calculate the number of years required for the asteroid to make one revolution around the Sun.arrow_forward
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