Chapter 11.1, Problem 11LC

(a)

Interpretation Introduction

Interpretation: To determine the balanced chemical reaction of the given reaction.

Concept Introduction: A chemical equation is said to be balanced if it has the same number of atoms within each type on either the reactant or product sides of the reaction.

Answer to Problem 11LC

The balanced chemical equation will be ${\text{2Fe+3Cl}}_{\text{2}}\to {\text{2FeCl}}_{\text{3}}$

Explanation of Solution

Iron metal and chlorine gas react to form solid iron (III) chloride. It can be written as:

  ${\text{Fe+Cl}}_{\text{2}}\to {\text{FeCl}}_{\text{3}}$

In the above reaction, iron is balanced but chlorine is unbalanced. So, by multiplying 2 on the product side and by 3 in ${\text{Cl}}_{\text{2}}$ on the reactant side then 6 chlorine atoms on both sides reaction but now iron is unbalanced.

To balance the iron, if multiply 2 as a coefficient of iron on the reactant side, we get 2 atoms of iron on both sides of the reaction. So, now the balanced equation is:

  ${\text{2Fe+3Cl}}_{\text{2}}\to {\text{2FeCl}}_{\text{3}}$

(b)

Interpretation Introduction

Interpretation: To determine the balanced chemical reaction of the given reaction.

Concept Introduction: A chemical equation is said to be balanced if it has the same number of atoms within each type on either the reactant or product sides of the reaction.

Answer to Problem 11LC

The balanced chemical equation will be ${\text{Al}}_{\text{2}}{{\text{(CO}}_{\text{3}}\text{)}}_{\text{3}}\to {\text{Al}}_{\text{2}}{\text{O}}_{\text{3}}{\text{+3CO}}_{\text{2}}$

Explanation of Solution

Solid aluminum carbonate decomposes to form solid aluminum oxide and carbon dioxide gas.

  ${\text{Al}}_{\text{2}}{{\text{(CO}}_{\text{3}}\text{)}}_{\text{3}}\to {\text{Al}}_{\text{2}}{\text{O}}_{\text{3}}{\text{+CO}}_{\text{2}}$

In the above reaction, carbon and oxygen are not balanced. So, by multiplying 3 in ${\text{CO}}_{\text{2}}$ it will be balanced ( ${\text{3CO}}_{\text{2}}$ ). So, there are 2 aluminum atoms, 3 carbon atoms, and 9 oxygen atoms on the reactant side. Also, on the product side, there are 2 aluminum atoms, 3 carbon atoms, and 9 oxygen atoms. So, the reaction will be balanced.

The balanced chemical reaction is:

  ${\text{Al}}_{\text{2}}{{\text{(CO}}_{\text{3}}\text{)}}_{\text{3}}\to {\text{Al}}_{\text{2}}{\text{O}}_{\text{3}}{\text{+3CO}}_{\text{2}}$

(c)

Interpretation Introduction

Interpretation: To determine the balanced chemical reaction of the given reaction.

Concept Introduction: A chemical equation is said to be balanced if it has the same number of atoms within each type on either the reactant or product sides of the reaction.

Answer to Problem 11LC

  ${\text{Mg+2AgNO}}_{\text{3}}\to {\text{Mg(NO}}_{\text{3}}{\text{)}}_{\text{2}}\text{+Ag}$

Explanation of Solution

Solid magnesium reacts with aqueous silver nitrate to form solid silver and aqueous magnesium nitrate.

  ${\text{Mg+AgNO}}_{\text{3}}\to {\text{Mg(NO}}_{\text{3}}{\text{)}}_{\text{2}}\text{+Ag}$

In above reaction ${\text{NO}}_{\text{3}}$ is not balanced. By multiplying 2 in ${\text{AgNO}}_{\text{3}}$ in reactant side, the reaction will be balanced.

  ${\text{Mg+2AgNO}}_{\text{3}}\to {\text{Mg(NO}}_{\text{3}}{\text{)}}_{\text{2}}\text{+Ag}$