   Chapter 11.1, Problem 19E

Chapter
Section
Textbook Problem

# Calculate, to four decimal places, the first ten terms of the sequence and use them to plot the graph of the sequence by hand. Does the sequence appear to have a limit? If so, calculate it. If not, explain why.19. a n = 3 n 1 + 6 n

To determine

To calculate: The first ten terms of the sequence and plot them on the graph to obtain the limit.

Explanation

Given:

The sequence is an=3n1+6n . (1)

Calculation:

Obtain the first ten terms of the sequence.

Substitute 1 for n in equation (1).

a1=311+61   =37   =0.4286

Thus, the first term of the sequence is a1=0.4286_ .

Substitute 2 for n in equation (1).

a2=321+62   =613   =0.4615

Thus, the second term of the sequence is a2=0.4615_ .

Substitute 3 for n in equation (1).

a3=331+63   =919   =0.4737

Thus, the third term of the sequence is a3=0.4737_ .

Substitute 4 for n in equation (1).

a4=341+64   =1225   =0.4800

Thus, the fourth term of the sequence is a4=0.4800_ .

Substitute 5 for n in equation (1).

a5=351+65   =1531   =0.4839

Thus, the fifth term of the sequence is a5=0.4839_ .

Substitute 6 for n in equation (1).

a6=361+66   =1837   =0.4865

Thus, the sixth term of the sequence is a6=0.4865_ .

Substitute 7 for n in equation (1).

a7=371+67   =2143   =0.4884

Thus, the seventh term of the sequence is a7=0.4884_ .

Substitute 8 for n in equation (1).

a8=381+68   =2449   =0

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