ORGANIC CHEMISTRY (LL)-W/SOLN.>CUSTOM<
ORGANIC CHEMISTRY (LL)-W/SOLN.>CUSTOM<
10th Edition
ISBN: 9781259972348
Author: Carey
Publisher: MCG CUSTOM
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Chapter 11.12, Problem 20P

Methyl acrylate ( H 2 C = CHCO 2 CH 3 ) reacts with 1,3-cyclopentadiene to give a mixture of twoproducts. Write structural formulas for both and predict which one predominates.

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Chapter 11 Solutions

ORGANIC CHEMISTRY (LL)-W/SOLN.>CUSTOM<

Ch. 11.5 - Prob. 11PCh. 11.6 - Prob. 12PCh. 11.8 - Prob. 13PCh. 11.9 - What dienes containing isolated double bonds are...Ch. 11.10 - Prob. 15PCh. 11.10 - Prob. 16PCh. 11.11 - Prob. 17PCh. 11.12 - Dicarbonyl compounds such as quinones are reactive...Ch. 11.12 - 2,3-Di-tert-butyl-1,3-butadiene is extremely...Ch. 11.12 - Methyl acrylate (H2C=CHCO2CH3) reacts with...Ch. 11.13 - Prob. 21PCh. 11.14 - What diene and dienophile could you use to prepare...Ch. 11.14 - Write equations in the synthetic direction for the...Ch. 11.16 - Prob. 24PCh. 11.16 - Prob. 25PCh. 11 - Write structural formulas for each of the...Ch. 11 - Give an acceptable IUPAC name for each of the...Ch. 11 - A certain species of grasshopper secretes an...Ch. 11 - Which of the following are chiral?...Ch. 11 - Describe the molecular geometry expected for...Ch. 11 - Prob. 31PCh. 11 - What compound of molecular formula C6H10 gives...Ch. 11 - Prob. 33PCh. 11 - Prob. 34PCh. 11 - Prob. 35PCh. 11 - Prob. 36PCh. 11 - Identify the more reactive dienophile in each of...Ch. 11 - Prob. 38PCh. 11 - Prob. 39PCh. 11 - Prob. 40PCh. 11 - Prob. 41PCh. 11 - Prob. 42PCh. 11 - Prob. 43PCh. 11 - Prob. 44PCh. 11 - Prob. 45PCh. 11 - Prob. 46PCh. 11 - Show how to prepare each of the following...Ch. 11 - Prob. 48PCh. 11 - Prob. 49PCh. 11 - Prob. 50PCh. 11 - Compound A was converted to compound B by the...Ch. 11 - Suggest reasonable explanations for each of the...Ch. 11 - Prob. 53PCh. 11 - Prob. 54PCh. 11 - Prob. 55DSPCh. 11 - Prob. 56DSPCh. 11 - Prob. 57DSPCh. 11 - Prob. 58DSPCh. 11 - Prob. 59DSP
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How to Design a Total Synthesis; Author: Chemistry Unleashed;https://www.youtube.com/watch?v=9jRfAJJO7mM;License: Standard YouTube License, CC-BY