Chapter 11.3, Problem 3PSA

To determine

To find : The median and the area of the given trapezoid

Answer to Problem 3PSA

The median is $m=10.5$ and the area is $A=73.5$

Explanation of Solution

Given information : The following information has been given

The base lengths are

  $a=6$ and $b=15$

The height between them is

  $h=7$

Formula used : The area of any trapezoid will be

  $A=\frac{a+b}{2}h$

Calculation : We know that the median of a trapezoid can be given as

  $m=\frac{a+b}{2}$

Hence, we substitute the given values, and we get

  $m=10.5$

We know that the area of a trapezoid can be given as

  $A=\frac{a+b}{2}h$

Hence, we substitute the given values, and we get

  $A=\frac{6+15}{2}(7)=73.5$