   Chapter 11.3, Problem 40ES ### Discrete Mathematics With Applicat...

5th Edition
EPP + 1 other
ISBN: 9781337694193

#### Solutions

Chapter
Section ### Discrete Mathematics With Applicat...

5th Edition
EPP + 1 other
ISBN: 9781337694193
Textbook Problem
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# Exercises 40—43 refer to another algorithm, known as Horner’s rule, for finding the value of a polynomial. Algorithm 11.3.4 Homer’s Rule [This algorithn computes the value of a polynomial a [ n ] x n + a [ n − 1 ] x n − 1 + ⋯ + a [ 2 ] x 2 + a [ 1 ] x + a [ 0 ] by nesting successive additions and multiplications as indicated in the following parenthesization:   ( ( ⋯ ( ( a [ n ] x + a [ n − 1 ] ) x + a [ n − 2 ] ) x + ⋯ + a [ 2 ] ) x + a [ 1 ] ) x + a [ 0 ] .At each stage, starting with a [ n ] , the current value of polyval is multiplied by x and the next lower coefficient of the polynomial is added to it.] Input: n[a nonnegative integer], a [ 0 ] ,   a [ 1 ] ,   a [ 2 ] ,   … , a [ n ] [an array of real numbers], x [a real number] Algorithm Body: p o l y v a l : = a [ n ] for i : = 1 to n p o l y v a l : = p o l y v a l ⋅ x + a [ n − i ] next i [ A t   t h i s   p o i n t   p o l y v a l = a [ n ] x n + a [ n − 1 ] x n − 1 + ⋯ + a [ 2 ] x 2 + a [ 1 ] x + a [ 0 ] . ] Output: polyval [a real number] 40. Trace Algorithm 11.3.4 for the input n = 3 ,   a [ 0 ] = 2 ,   a [ 1 ] = 1 ,   a [ 2 ] = − 1 ,   a [ 3 ] = 3 , and x = 2 .

To determine

To find:

The trace table of the given algorithm for the given information.

Explanation

Given information:

Following data is given.

n=3 x=2a=2 a=1a=1 a=3

The considered algorithm for Horner’s Rule is as follows.

Input:

n [a nonnegative integer], a,a,a....,a[n] [an array of real numbers], x [a real number] Algorithm Body:

polyval:=a[n]

for i:=1 tn

polyval:=polyval·x+a[n1]

next i

[at this point

polyval=a[n]xn+a[n1]xn1 +...+ax2+ax+a

Output:

polyval [a real number]

Calculation:

The algorithm starts with n=3, x=2 and i=1 taking a as the polyval

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