Precalculus with Limits: A Graphing Approach
Precalculus with Limits: A Graphing Approach
7th Edition
ISBN: 9781305071711
Author: Ron Larson
Publisher: Brooks/Cole
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Question
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Chapter 11.4, Problem 72E

a.

To determine

To estimate: limxf(x) for the given two graphs.

a.

Expert Solution
Check Mark

Answer to Problem 72E

For graph (i) the value of the limits is limxf(x)=0

For graph (ii) the value of the limits is limxf(x)=2

Explanation of Solution

Given:

The graphs are:-

  Precalculus with Limits: A Graphing Approach, Chapter 11.4, Problem 72E , additional homework tip  1

Concept used:

The value of f(x) is equal to the value of y .

Calculation:

The graph (i) is

  Precalculus with Limits: A Graphing Approach, Chapter 11.4, Problem 72E , additional homework tip  2

From the graph it can be seen that when the value of x tends to then the value of y approaches to 0.

So,

  limxf(x)=0

The graph (ii) is

  Precalculus with Limits: A Graphing Approach, Chapter 11.4, Problem 72E , additional homework tip  3

From the graph it can be seen that when the value of x tends to , then the value of y approaches to 2. So the value of f approaches to 2.

So,

  limxf(x)=2

b.

To determine

To estimate: limxf(x) for the given two graphs.

b.

Expert Solution
Check Mark

Answer to Problem 72E

For graph (i) the value of the limits is limxf(x)=0

For graph (ii) the value of the limits is limxf(x)=2

Explanation of Solution

Given:

The graphs are

  Precalculus with Limits: A Graphing Approach, Chapter 11.4, Problem 72E , additional homework tip  4

Concept used:

The value of f(x) is equal to y .

Calculation:

The graph (i) is

  Precalculus with Limits: A Graphing Approach, Chapter 11.4, Problem 72E , additional homework tip  5

From the graph it can be seen that when the value of x tends to , then the value of y approaches to 0.

So,

  limxf(x)=0

The graph (ii) is

  Precalculus with Limits: A Graphing Approach, Chapter 11.4, Problem 72E , additional homework tip  6

From the graph it can be seen that when the value of x tends to , then the value of y approaches to 2.

So,

  limxf(x)=2

c.

To determine

To find: The horizontal asymptote of the graph of f .

c.

Expert Solution
Check Mark

Answer to Problem 72E

For graph (i) the horizontal asymptote is y=0 .

For graph (ii) the horizontal asymptote is y=2 .

Explanation of Solution

Given:

The graphs are

  Precalculus with Limits: A Graphing Approach, Chapter 11.4, Problem 72E , additional homework tip  7

Concept used:

Horizontal asymptote: in the graph of f , y=c is called horizontal asymptote if limxf(x)=c or limxf(x)=c .

Calculation:

The graph (i) is

  Precalculus with Limits: A Graphing Approach, Chapter 11.4, Problem 72E , additional homework tip  8

From the graph it can be seen that when the value of x tends to ± then the value of y approaches to 0.

So the value of f approaches to 0.

Here limxf(x)=0 and limxf(x)=0

Hence according to the definition, the horizontal asymptote of the graph (i) is y=0 .

The graph (ii) is

  Precalculus with Limits: A Graphing Approach, Chapter 11.4, Problem 72E , additional homework tip  9

From the graph it can be seen that when the value of x tends to ± the value of y approaches to 2. So the value of f approaches to 2.

Here limxf(x)=2 and limxf(x)=2

Hence according to the definition, the horizontal asymptote of the graph (ii) is y=2 .

Chapter 11 Solutions

Precalculus with Limits: A Graphing Approach

Ch. 11.1 - Prob. 11ECh. 11.1 - Prob. 12ECh. 11.1 - Prob. 13ECh. 11.1 - Prob. 14ECh. 11.1 - Prob. 15ECh. 11.1 - Prob. 16ECh. 11.1 - Prob. 17ECh. 11.1 - Prob. 18ECh. 11.1 - Prob. 19ECh. 11.1 - Prob. 20ECh. 11.1 - Prob. 21ECh. 11.1 - Prob. 22ECh. 11.1 - Prob. 23ECh. 11.1 - Prob. 24ECh. 11.1 - Prob. 25ECh. 11.1 - Prob. 26ECh. 11.1 - Prob. 27ECh. 11.1 - Prob. 28ECh. 11.1 - Prob. 29ECh. 11.1 - Prob. 30ECh. 11.1 - Prob. 31ECh. 11.1 - Prob. 32ECh. 11.1 - Prob. 33ECh. 11.1 - Prob. 34ECh. 11.1 - Prob. 35ECh. 11.1 - Prob. 36ECh. 11.1 - Prob. 37ECh. 11.1 - Prob. 38ECh. 11.1 - Prob. 39ECh. 11.1 - Prob. 40ECh. 11.1 - Prob. 41ECh. 11.1 - Prob. 42ECh. 11.1 - Prob. 43ECh. 11.1 - Prob. 44ECh. 11.1 - Prob. 45ECh. 11.1 - Prob. 46ECh. 11.1 - Prob. 47ECh. 11.1 - Prob. 48ECh. 11.1 - Prob. 49ECh. 11.1 - Prob. 50ECh. 11.1 - Prob. 51ECh. 11.1 - Prob. 52ECh. 11.1 - Prob. 53ECh. 11.1 - Prob. 54ECh. 11.1 - Prob. 55ECh. 11.1 - Prob. 56ECh. 11.1 - Prob. 57ECh. 11.1 - Prob. 58ECh. 11.1 - Prob. 59ECh. 11.1 - Prob. 60ECh. 11.1 - 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