Precalculus with Limits: A Graphing Approach
Precalculus with Limits: A Graphing Approach
7th Edition
ISBN: 9781305071711
Author: Ron Larson
Publisher: Brooks/Cole
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Chapter 11.1, Problem 80E

a.

To determine

To find: To find the function f(0) exists in the given graph.

a.

Expert Solution
Check Mark

Answer to Problem 80E

The function f(0) exists in the given graph.

Explanation of Solution

Given:

  Precalculus with Limits: A Graphing Approach, Chapter 11.1, Problem 80E , additional homework tip  1

From the graph we can observe that there is a hole and a solid dot at x=0 .

The solid dot means f(0) is been defined.

  f(0)=1

Therefore we can conclude that the function f(0) is defined and exists.

b.

To determine

To find: To find the function limx0f(x) exists in the given graph.

b.

Expert Solution
Check Mark

Answer to Problem 80E

The function limx0f(x) does not exist in the given graph.

Explanation of Solution

Given:

  Precalculus with Limits: A Graphing Approach, Chapter 11.1, Problem 80E , additional homework tip  2

From the observation of the graph,

From the left hand side, limx0f(x) approaches f(x)4 at x0 .

From the right hand side, limx0f(x) approaches f(x)1 at x0 .

The function f(x) approaches two different values at x0 .

Therefore the function limx0f(x) does not exist.

c.

To determine

To find: To find the function f(2) exists in the given graph.

c.

Expert Solution
Check Mark

Answer to Problem 80E

The function f(2) is undefined in the given graph.

Explanation of Solution

Given:

  Precalculus with Limits: A Graphing Approach, Chapter 11.1, Problem 80E , additional homework tip  3

From the graph we can observe that there is a hole at x=2 .

The hole at x=2 means f(2) is been undefined.

Therefore we can conclude that the function f(2) is undefined.

d.

To determine

To find: To find the function limx2f(x) exists in the given graph.

d.

Expert Solution
Check Mark

Answer to Problem 80E

The function limx2f(x) exists in the given graph.

Explanation of Solution

Given:

  Precalculus with Limits: A Graphing Approach, Chapter 11.1, Problem 80E , additional homework tip  4

From the graph we can observe that,

From the left hand side and right hand side x2 .

Therefore we can conclude that the function limx2f(x) exists.

Chapter 11 Solutions

Precalculus with Limits: A Graphing Approach

Ch. 11.1 - Prob. 11ECh. 11.1 - Prob. 12ECh. 11.1 - Prob. 13ECh. 11.1 - Prob. 14ECh. 11.1 - Prob. 15ECh. 11.1 - Prob. 16ECh. 11.1 - Prob. 17ECh. 11.1 - Prob. 18ECh. 11.1 - Prob. 19ECh. 11.1 - Prob. 20ECh. 11.1 - Prob. 21ECh. 11.1 - Prob. 22ECh. 11.1 - Prob. 23ECh. 11.1 - Prob. 24ECh. 11.1 - Prob. 25ECh. 11.1 - Prob. 26ECh. 11.1 - Prob. 27ECh. 11.1 - Prob. 28ECh. 11.1 - Prob. 29ECh. 11.1 - Prob. 30ECh. 11.1 - Prob. 31ECh. 11.1 - Prob. 32ECh. 11.1 - Prob. 33ECh. 11.1 - Prob. 34ECh. 11.1 - Prob. 35ECh. 11.1 - Prob. 36ECh. 11.1 - Prob. 37ECh. 11.1 - Prob. 38ECh. 11.1 - Prob. 39ECh. 11.1 - Prob. 40ECh. 11.1 - Prob. 41ECh. 11.1 - Prob. 42ECh. 11.1 - Prob. 43ECh. 11.1 - Prob. 44ECh. 11.1 - Prob. 45ECh. 11.1 - Prob. 46ECh. 11.1 - Prob. 47ECh. 11.1 - Prob. 48ECh. 11.1 - Prob. 49ECh. 11.1 - Prob. 50ECh. 11.1 - Prob. 51ECh. 11.1 - Prob. 52ECh. 11.1 - Prob. 53ECh. 11.1 - Prob. 54ECh. 11.1 - Prob. 55ECh. 11.1 - Prob. 56ECh. 11.1 - Prob. 57ECh. 11.1 - Prob. 58ECh. 11.1 - Prob. 59ECh. 11.1 - Prob. 60ECh. 11.1 - 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Prob. 30ECh. 11.5 - Prob. 31ECh. 11.5 - Prob. 32ECh. 11.5 - Prob. 33ECh. 11.5 - Prob. 34ECh. 11.5 - Prob. 35ECh. 11.5 - Prob. 36ECh. 11.5 - Prob. 37ECh. 11.5 - Prob. 38ECh. 11.5 - Prob. 39ECh. 11.5 - Prob. 40ECh. 11.5 - Prob. 41ECh. 11.5 - Prob. 42ECh. 11.5 - Prob. 43ECh. 11.5 - Prob. 44ECh. 11.5 - Prob. 45ECh. 11.5 - Prob. 46ECh. 11.5 - Prob. 47ECh. 11.5 - Prob. 48ECh. 11.5 - Prob. 49ECh. 11.5 - Prob. 50ECh. 11 - Prob. 1RECh. 11 - Prob. 2RECh. 11 - Prob. 3RECh. 11 - Prob. 4RECh. 11 - Prob. 5RECh. 11 - Prob. 6RECh. 11 - Prob. 7RECh. 11 - Prob. 8RECh. 11 - Prob. 9RECh. 11 - Prob. 10RECh. 11 - Prob. 11RECh. 11 - Prob. 12RECh. 11 - Prob. 13RECh. 11 - Prob. 14RECh. 11 - Prob. 15RECh. 11 - Prob. 16RECh. 11 - Prob. 17RECh. 11 - Prob. 18RECh. 11 - Prob. 19RECh. 11 - Prob. 20RECh. 11 - Prob. 21RECh. 11 - Prob. 22RECh. 11 - Prob. 23RECh. 11 - Prob. 24RECh. 11 - Prob. 25RECh. 11 - Prob. 26RECh. 11 - Prob. 27RECh. 11 - Prob. 28RECh. 11 - Prob. 29RECh. 11 - Prob. 30RECh. 11 - Prob. 31RECh. 11 - Prob. 32RECh. 11 - 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Limits and Continuity; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=9brk313DjV8;License: Standard YouTube License, CC-BY