Elementary Statistics ( 3rd International Edition ) Isbn:9781260092561
3rd Edition
ISBN: 9781259969454
Author: William Navidi Prof.; Barry Monk Professor
Publisher: McGraw-Hill Education
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Chapter 11.5, Problem 9E
To determine
Why the conclusion made by sociologist is not justified.
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A researcher is interested in studying the difference in the average level of anxiety among college students who are in their first semester of college compared to students who are in their final semester of college. The researcher has a sample of 62 students in their first semester and 60 students in their final semester and conducts a two-sample t-test (two-tailed, alpha = .05). The researcher finds the following:
1. Students in their first semester of college (group 1) have an average anxiety score of 1.8.
2. Students in their final semester of college (group 2) have an average anxiety score of 2.8.
3. The standard error of the mean difference between students in their first semester and final semester (i.e., the se) is .20.
What are the degrees of freedom for this test? Enter your answer as a whole number with no decimal places (i.e., 10, not 10.1, not 10.10).
How many hours of sleep do people get by listening to music? I record 10 subjects’ hours of sleep after they listen to 4 types of music: White noise, Rock, Pop, and Classical. For each music condition, they provide an average amount of hours of sleep they got for 1 week. Using the following data, test whether there is a significant difference in hours of sleep between types of music at an alpha of 0.01.
Subject
White noise
Rock
Pop
Classical
1
5
5
7.5
9
2
9.5
6.5
7
9
3
7.5
6
7
10
4
8
6
7
8
5
8.5
5
6
8
6
6
5.5
7
10
7
7
6.5
9
9
8
8
5
5
9.5
9
8
6
7
8
10
8
7
7.5
7
Complete the ANOVA summary table:
Source of Variation
Sums of Squares
df
MS (Variance)
F
Between-groups
Within-groups (error)
Total
What do we conclude?
Using a bonferroni correction, run a post-hoc test on the type of music and…
Researchers interested in lead exposure due to car exhaust sampled the blood of 52 police officers subjected to constant inhalation of automobile exhaust fumes while working traffic enforcement in a primarily urban environment. The blood samples of these officers had an average lead concentration of 124.32 µg/l and a SD of 37.74 µg/l; a previous study of individuals from a nearby suburb, with no history of exposure, found an average blood level concentration of 35 µg/l.
Test the hypothesis that the downtown police officers have a higher lead exposure than the group in the previous study. Interpret your results in context.
Based on your preceding result, without performing a calculation, would a 99% confidence interval for the average blood concentration level of police officers contain 35 µg/l?
Based on your preceding result, without performing a calculation, would a 99% confidence interval for this difference contain 0? Explain why or why not.
Chapter 11 Solutions
Elementary Statistics ( 3rd International Edition ) Isbn:9781260092561
Ch. 11.1 - In Exercises 3 and 4, fill in each blank with the...Ch. 11.1 - Prob. 4ECh. 11.1 - Prob. 5ECh. 11.1 - Prob. 6ECh. 11.1 - A test was made of H0:1=2 versus H1:12. The sample...Ch. 11.1 - A test was made of H0:1=2 versus H1:12. The sample...Ch. 11.1 - More time on the Internet: The General Social...Ch. 11.1 - Low-fat or low-carb? Are low-fat diets or low-carb...Ch. 11.1 - Are you smarter than your older brother? In a...Ch. 11.1 - Recovering from surgery: A new postsurgical...
Ch. 11.1 - Contaminated water: The concentration of benzene...Ch. 11.1 - Exercise: Medical researchers conducted a study to...Ch. 11.1 - Mummys curse: King Tut was an ancient Egyptian...Ch. 11.1 - Baby weights: Following are weights in pounds for...Ch. 11.1 - Empathy: The Interpersonal Reactivity Index is a...Ch. 11.1 - Prob. 18ECh. 11.1 - Prob. 19ECh. 11.1 - Prob. 20ECh. 11.1 - Interpret calculator display: The following TI-84...Ch. 11.1 - Prob. 22ECh. 11.1 - Prob. 23ECh. 11.1 - Prob. 24ECh. 11.1 - Prob. 25ECh. 11.2 - In Exercises 3 and 4, fill in each blank with the...Ch. 11.2 - Prob. 4ECh. 11.2 - Prob. 5ECh. 11.2 - Prob. 6ECh. 11.2 - In a test for the difference between two...Ch. 11.2 - In a test for the difference between two...Ch. 11.2 - Childhood obesity: The National Health and...Ch. 11.2 - Pollution and altitude: In a random sample of 340...Ch. 11.2 - Preventing heart attacks: Medical researchers...Ch. 11.2 - Cholesterol: An article in the Archives of...Ch. 11.2 - Treating circulatory disease: Angioplasty is a...Ch. 11.2 - Hurricane damage: In August and September 2005,...Ch. 11.2 - Prob. 15ECh. 11.2 - Prob. 16ECh. 11.2 - Prob. 17ECh. 11.2 - Interpret calculator display: The following TI-84...Ch. 11.2 - Prob. 19ECh. 11.2 - Prob. 20ECh. 11.2 - Prob. 21ECh. 11.3 - In Exercises 3 and 4, fill in each blank with the...Ch. 11.3 - In Exercises 3 and 4, fill in each blank with the...Ch. 11.3 - Prob. 5ECh. 11.3 - Prob. 6ECh. 11.3 - Prob. 7ECh. 11.3 - Prob. 8ECh. 11.3 - Crossover trial: A crossover trial is a type of...Ch. 11.3 - Comparing scales: In an experiment to determine...Ch. 11.3 - Strength of concrete: The compressive strength. in...Ch. 11.3 - Truck pollution: In an experiment to determine the...Ch. 11.3 - Growth spurt: It is generally known that boys grow...Ch. 11.3 - Prob. 14ECh. 11.3 - Prob. 15ECh. 11.3 - Interpret calculator display: The following TI-84...Ch. 11.3 - Interpret computer output: The following MINITAB...Ch. 11.3 - Prob. 18ECh. 11.3 - Prob. 19ECh. 11.4 - In Exercises 5 and 6, fill in each blank with the...Ch. 11.4 - Prob. 6ECh. 11.4 - Prob. 7ECh. 11.4 - Prob. 8ECh. 11.4 - Find the critical value f0.05 for F7,20.Ch. 11.4 - Prob. 10ECh. 11.4 - An F-test with 12 degrees of freedom in the...Ch. 11.4 - Prob. 12ECh. 11.4 - Sugar content: A broth used to manufacture a...Ch. 11.4 - Hockey sticks: The breaking strength of hockey...Ch. 11.4 - Prob. 15ECh. 11.4 - Are you smarter than your older brother? In a...Ch. 11.4 - Prob. 17ECh. 11.5 - In Exercises 3 and 4, fill in each blank with the...Ch. 11.5 - Prob. 4ECh. 11.5 - Prob. 5ECh. 11.5 - Prob. 6ECh. 11.5 - Prob. 7ECh. 11.5 - Prob. 8ECh. 11.5 - Prob. 9ECh. 11.5 - Prob. 10ECh. 11.5 - Prob. 11ECh. 11.5 - Prob. 12ECh. 11.5 - Prob. 13ECh. 11 - Prob. 1CQCh. 11 - Prob. 2CQCh. 11 - Prob. 3CQCh. 11 - Prob. 4CQCh. 11 - Prob. 5CQCh. 11 - Prob. 6CQCh. 11 - Prob. 7CQCh. 11 - Prob. 8CQCh. 11 - Prob. 9CQCh. 11 - Prob. 10CQCh. 11 - Prob. 11CQCh. 11 - Prob. 12CQCh. 11 - Prob. 13CQCh. 11 - Refer to Exercise 12. Can you reject H0 at the...Ch. 11 - Prob. 15CQCh. 11 - Prob. 1RECh. 11 - Prob. 2RECh. 11 - Prob. 3RECh. 11 - Prob. 4RECh. 11 - Prob. 5RECh. 11 - Prob. 6RECh. 11 - Prob. 7RECh. 11 - Prob. 8RECh. 11 - Prob. 9RECh. 11 - Prob. 10RECh. 11 - Prob. 11RECh. 11 - Prob. 12RECh. 11 - Prob. 13RECh. 11 - Prob. 14RECh. 11 - Prob. 15RECh. 11 - Prob. 1WAICh. 11 - Prob. 2WAICh. 11 - Describe the differences between performing a...Ch. 11 - Prob. 4WAICh. 11 - Prob. 5WAICh. 11 - Prob. 1CSCh. 11 - Prob. 2CSCh. 11 - Prob. 3CSCh. 11 - Prob. 4CS
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- Population Genetics In the study of population genetics, an important measure of inbreeding is the proportion of homozygous genotypesthat is, instances in which the two alleles carried at a particular site on an individuals chromosomes are both the same. For population in which blood-related individual mate, them is a higher than expected frequency of homozygous individuals. Examples of such populations include endangered or rare species, selectively bred breeds, and isolated populations. in general. the frequency of homozygous children from mating of blood-related parents is greater than that for children from unrelated parents Measured over a large number of generations, the proportion of heterozygous genotypesthat is, nonhomozygous genotypeschanges by a constant factor 1 from generation to generation. The factor 1 is a number between 0 and 1. If 1=0.75, for example then the proportion of heterozygous individuals in the population decreases by 25 in each generation In this case, after 10 generations, the proportion of heterozygous individuals in the population decreases by 94.37, since 0.7510=0.0563, or 5.63. In other words, 94.37 of the population is homozygous. For specific types of matings, the proportion of heterozygous genotypes can be related to that of previous generations and is found from an equation. For mating between siblings 1 can be determined as the largest value of for which 2=12+14. This equation comes from carefully accounting for the genotypes for the present generation the 2 term in terms of those previous two generations represented by for the parents generation and by the constant term of the grandparents generation. a Find both solutions to the quadratic equation above and identify which is 1 use a horizontal span of 1 to 1 in this exercise and the following exercise. b After 5 generations, what proportion of the population will be homozygous? c After 20 generations, what proportion of the population will be homozygous?arrow_forward(A) Diet has a significant effect on Concentration at the p < 0.05 level only (B)Diet has a significant effect on Concentration at the p < 0.05 and p < 0.01 levels (C)Diet has a significant effect on Concentration at the p < 0.01 level only (D)There is not enough information to determine the effect. (E)Diet does not have a significant effect on Concentration at either the p < 0.05 or p < 0.01 levelsarrow_forwardA researcher investigates whether cold medicine effects mental alertness. It is known that scores on a standardized test containing a variety of problem-solving tasks are normally distributed with M=64 and SD=8. A random sample of n=16 teenage and a sample of n=25 adults are given the drug and then tested. On average the teenagers scored an average of M=58 and the adults scored an average of M=65.5. a. Are the data sufficent to conclude that the medication significantly reduces metal alertness in teenagers? test with a signifigance level a= .01 b. Are the data sufficent to conclude that the medication signfigigantly increases the mental alertness in adults? test with a signfigance level of a=.01arrow_forward
- A group of six, obese adult men had their weights recorded both before and 10 months after having a diet treatment to help manage their weight. Observe the information presented in the table below: The weights of six obese adult men both before and 10-months after having a diet treatment Before Diet Treatment After Diet Treatment 250 240 225 215 220 198 311 300 326 298 205 205 Test at α = 0.05 the hypothesis that for the group, there was a statistically significant average decrease in weight from before diet treatment to 10 months after. Hint: This is hypothesis testing for paired samples. Here, you will use a paired t test.arrow_forwardQUESTION 12 Historically, the proportion of people who trade in their old car to a car dealer when purchasing a new car is 48%. Over the previous 6 months, in a sample of 115 new-car buyers, 46 have traded in their old car. To determine (at the 10% level of significance) whether the proportion of new-car buyers that trade in their old car has statistically significantly decreased, what can you conclude concerning the null hypothesis? Reject the null hypothesis Fail to reject the null hypothesisarrow_forwardSecond-Hand Smoke: Data Set 12 “Passive and Active Smoke” in Appendix B includes cotinine levels measured in a group of nonsmokers exposed to tobacco smoke (n = 40, Mean = 60.58 ng>mL, s = 138.08 ng>mL) and a group of nonsmokers not exposed to tobacco smoke (n = 40, Mean = 16.35 ng>mL, s = 62.53 ng>mL). Cotinine is a metabolite of nicotine, meaning that when nicotine is absorbed by the body, cotinine is produced. Use a 0.05 significance level to test the claim that nonsmokers exposed to tobacco smoke have a higher mean cotinine level than nonsmokers not exposed to tobacco smoke. Construct the confidence interval appropriate for the hypothesis test in part a. What do you conclude about the effects of second-hand smoke?arrow_forward
- Stock A has a beta of 1.2 and Stock B has a beta of 1. The returns of Stock A are ______ sensitive to changes in the market as the returns of Stock B.arrow_forward1 (part 1). Does When Food Is Eaten Affect Weight Gain?A study was introduced that examined the effect of light at night on weight gain in mice. In the full study of 27 mice over a four-week period, the mice who had a light on at night gained significantly more weight than the mice with darkness at night, despite eating the same number of calories and exercising the same amount. Researchers noticed that the mice with light at night ate a greater percentage of their calories during the day (when mice are supposed to be sleeping). The computer output shown below allows us to examine the relationship between percent of calories eaten during the day, DayPct, and body mass gain in grams, BMGain. A scatterplot with regression line is also shown below (attached image).Pearson correlation of BMGain and DayPct =0.740P-Value =0.000--------------------------------------------------------------The regression equation isBMGain=1.11+0.127DayPct Predictor Coef SE Coef T P Constant 1.113 1.382…arrow_forwardQUESTION 12 Historically, the proportion of people who trade in their old car to a car dealer when purchasing a new car is 48%. Over the previous 6 months, in a sample of 115 new-car buyers, 46 have traded in their old car. To determine (at the 10% level of significance) whether the proportion of new-car buyers that trade in their old car has statistically significantly decreased, what can you conclude concerning the null hypothesis?arrow_forward
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