Elementary Statistics ( 3rd International Edition ) Isbn:9781260092561
3rd Edition
ISBN: 9781259969454
Author: William Navidi Prof.; Barry Monk Professor
Publisher: McGraw-Hill Education
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Chapter 11.5, Problem 10E
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Why the conclusion drawn by quality engineer is justified.
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If the proportion of the population in City A that is over 65 years old is p1 and the proportion of the population in City B that is over 65 years old is p2, what is the null hypothesis for a test to determine if the proportion of the population that is over 65 years old is greater in City A?
Select the correct answer below:
H0: p1−p2=0
H0: p1−p2>0
H0: p1−p2<0
H0: p1−p2≠0
The proportion of mango trees on an island that produce only dwarf fruit is p1. The proportion of mango trees on a different island that produce only dwarf fruit is p2. What is the null hypothesis for a test to determine if the proportions are different between the two islands?
Select the correct answer below:
H0: p1−p2≠0
H0: p1−p2=0
H0: p1−p2>0
H0: p1−p2<0
Test the claim that the proportion of people who own cats is smaller than 50% at the 0.01 significance level.The null and alternative hypothesis would be:
H0:p≥0.5H0:p≥0.5Ha:p<0.5Ha:p<0.5
H0:μ=0.5H0:μ=0.5Ha:μ≠0.5Ha:μ≠0.5
H0:μ≤0.5H0:μ≤0.5Ha:μ>0.5Ha:μ>0.5
H0:p≤0.5H0:p≤0.5Ha:p>0.5Ha:p>0.5
H0:p=0.5H0:p=0.5Ha:p≠0.5Ha:p≠0.5
H0:μ≥0.5H0:μ≥0.5Ha:μ<0.5Ha:μ<0.5
The test is:
left-tailed
two-tailed
right-tailed
Based on a sample of 100 people, 49% owned catsThe test statistic is: (Round to 2 decimals)The p-value is: (Round to 2 decimals)Based on this we:
Chapter 11 Solutions
Elementary Statistics ( 3rd International Edition ) Isbn:9781260092561
Ch. 11.1 - In Exercises 3 and 4, fill in each blank with the...Ch. 11.1 - Prob. 4ECh. 11.1 - Prob. 5ECh. 11.1 - Prob. 6ECh. 11.1 - A test was made of H0:1=2 versus H1:12. The sample...Ch. 11.1 - A test was made of H0:1=2 versus H1:12. The sample...Ch. 11.1 - More time on the Internet: The General Social...Ch. 11.1 - Low-fat or low-carb? Are low-fat diets or low-carb...Ch. 11.1 - Are you smarter than your older brother? In a...Ch. 11.1 - Recovering from surgery: A new postsurgical...
Ch. 11.1 - Contaminated water: The concentration of benzene...Ch. 11.1 - Exercise: Medical researchers conducted a study to...Ch. 11.1 - Mummys curse: King Tut was an ancient Egyptian...Ch. 11.1 - Baby weights: Following are weights in pounds for...Ch. 11.1 - Empathy: The Interpersonal Reactivity Index is a...Ch. 11.1 - Prob. 18ECh. 11.1 - Prob. 19ECh. 11.1 - Prob. 20ECh. 11.1 - Interpret calculator display: The following TI-84...Ch. 11.1 - Prob. 22ECh. 11.1 - Prob. 23ECh. 11.1 - Prob. 24ECh. 11.1 - Prob. 25ECh. 11.2 - In Exercises 3 and 4, fill in each blank with the...Ch. 11.2 - Prob. 4ECh. 11.2 - Prob. 5ECh. 11.2 - Prob. 6ECh. 11.2 - In a test for the difference between two...Ch. 11.2 - In a test for the difference between two...Ch. 11.2 - Childhood obesity: The National Health and...Ch. 11.2 - Pollution and altitude: In a random sample of 340...Ch. 11.2 - Preventing heart attacks: Medical researchers...Ch. 11.2 - Cholesterol: An article in the Archives of...Ch. 11.2 - Treating circulatory disease: Angioplasty is a...Ch. 11.2 - Hurricane damage: In August and September 2005,...Ch. 11.2 - Prob. 15ECh. 11.2 - Prob. 16ECh. 11.2 - Prob. 17ECh. 11.2 - Interpret calculator display: The following TI-84...Ch. 11.2 - Prob. 19ECh. 11.2 - Prob. 20ECh. 11.2 - Prob. 21ECh. 11.3 - In Exercises 3 and 4, fill in each blank with the...Ch. 11.3 - In Exercises 3 and 4, fill in each blank with the...Ch. 11.3 - Prob. 5ECh. 11.3 - Prob. 6ECh. 11.3 - Prob. 7ECh. 11.3 - Prob. 8ECh. 11.3 - Crossover trial: A crossover trial is a type of...Ch. 11.3 - Comparing scales: In an experiment to determine...Ch. 11.3 - Strength of concrete: The compressive strength. in...Ch. 11.3 - Truck pollution: In an experiment to determine the...Ch. 11.3 - Growth spurt: It is generally known that boys grow...Ch. 11.3 - Prob. 14ECh. 11.3 - Prob. 15ECh. 11.3 - Interpret calculator display: The following TI-84...Ch. 11.3 - Interpret computer output: The following MINITAB...Ch. 11.3 - Prob. 18ECh. 11.3 - Prob. 19ECh. 11.4 - In Exercises 5 and 6, fill in each blank with the...Ch. 11.4 - Prob. 6ECh. 11.4 - Prob. 7ECh. 11.4 - Prob. 8ECh. 11.4 - Find the critical value f0.05 for F7,20.Ch. 11.4 - Prob. 10ECh. 11.4 - An F-test with 12 degrees of freedom in the...Ch. 11.4 - Prob. 12ECh. 11.4 - Sugar content: A broth used to manufacture a...Ch. 11.4 - Hockey sticks: The breaking strength of hockey...Ch. 11.4 - Prob. 15ECh. 11.4 - Are you smarter than your older brother? In a...Ch. 11.4 - Prob. 17ECh. 11.5 - In Exercises 3 and 4, fill in each blank with the...Ch. 11.5 - Prob. 4ECh. 11.5 - Prob. 5ECh. 11.5 - Prob. 6ECh. 11.5 - Prob. 7ECh. 11.5 - Prob. 8ECh. 11.5 - Prob. 9ECh. 11.5 - Prob. 10ECh. 11.5 - Prob. 11ECh. 11.5 - Prob. 12ECh. 11.5 - Prob. 13ECh. 11 - Prob. 1CQCh. 11 - Prob. 2CQCh. 11 - Prob. 3CQCh. 11 - Prob. 4CQCh. 11 - Prob. 5CQCh. 11 - Prob. 6CQCh. 11 - Prob. 7CQCh. 11 - Prob. 8CQCh. 11 - Prob. 9CQCh. 11 - Prob. 10CQCh. 11 - Prob. 11CQCh. 11 - Prob. 12CQCh. 11 - Prob. 13CQCh. 11 - Refer to Exercise 12. Can you reject H0 at the...Ch. 11 - Prob. 15CQCh. 11 - Prob. 1RECh. 11 - Prob. 2RECh. 11 - Prob. 3RECh. 11 - Prob. 4RECh. 11 - Prob. 5RECh. 11 - Prob. 6RECh. 11 - Prob. 7RECh. 11 - Prob. 8RECh. 11 - Prob. 9RECh. 11 - Prob. 10RECh. 11 - Prob. 11RECh. 11 - Prob. 12RECh. 11 - Prob. 13RECh. 11 - Prob. 14RECh. 11 - Prob. 15RECh. 11 - Prob. 1WAICh. 11 - Prob. 2WAICh. 11 - Describe the differences between performing a...Ch. 11 - Prob. 4WAICh. 11 - Prob. 5WAICh. 11 - Prob. 1CSCh. 11 - Prob. 2CSCh. 11 - Prob. 3CSCh. 11 - Prob. 4CS
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- A dental assistant is interested in the proportion of patients that need a root canal. Let the proportion of patients that need a root canal be p. If the dental assistant wanted to know if the proportion of patients that need a root canal is more than 20%, what are the null and alternative hypotheses? Select the correct answer below: H0: p=0.20; Ha: p<0.20 H0: p>0.20; Ha: p=0.20 H0: p=0.20; Ha: p>0.20 H0: μ=0.20; Ha: μ>0.20arrow_forwardTest the claim that the proportion of people who own cats is smaller than 10% at the 0.025 significance level.The null and alternative hypothesis would be: H0:μ≥0.1H0:μ≥0.1Ha:μ<0.1Ha:μ<0.1 H0:p≤0.1H0:p≤0.1Ha:p>0.1Ha:p>0.1 H0:μ≤0.1H0:μ≤0.1Ha:μ>0.1Ha:μ>0.1 H0:μ=0.1H0:μ=0.1Ha:μ≠0.1Ha:μ≠0.1 H0:p=0.1H0:p=0.1Ha:p≠0.1Ha:p≠0.1 H0:p≥0.1H0:p≥0.1Ha:p<0.1Ha:p<0.1 The test is: right-tailed left-tailed two-tailed Based on a sample of 600 people, 2% owned catsThe test statistic is: (Round to 2 decimals)The p-value is: (Round to 2 decimals)Based on this we: Do not reject the null hypothesis Reject the null hypothesisarrow_forwardIn doing a hypothesis test of the population proportion at α=0.02 level of significance, we got the p-value to be 0.006. What would our conclusion to the test be? Why? A. Do NOT Reject H0 since the p-value > α B. Reject H1 since the p-value < α C. Reject H0 since the p-value < α D. Do NOT Reject H0 since the p-value < αarrow_forward
- Test the claim that the proportion of people who own cats is smaller than 50% at the 0.025 significance level.The null and alternative hypothesis would be: H0:p≤0.5H0:p≤0.5Ha:p>0.5Ha:p>0.5 H0:μ≥0.5H0:μ≥0.5Ha:μ<0.5Ha:μ<0.5 H0:p=0.5H0:p=0.5Ha:p≠0.5Ha:p≠0.5 H0:p≥0.5H0:p≥0.5Ha:p<0.5Ha:p<0.5 H0:μ=0.5H0:μ=0.5Ha:μ≠0.5Ha:μ≠0.5 H0:μ≤0.5H0:μ≤0.5Ha:μ>0.5Ha:μ>0.5 The test is: right-tailed two-tailed left-tailed Based on a sample of 700 people, 43% owned catsThe test statistic is: (Round to 2 decimals)The p-value is: (Round to 2 decimals)Based on this we: Reject the null hypothesis Do not reject the null hypothesisarrow_forwardA manufacturer of hand-held calculators receives large shipments of printed circuits from a supplier. It is too costly and time-consuming to inspect all incoming circuits, so when each shipment arrives, a sample is selected for inspection. Information from the sample is then used to test H0: p = 0.01 versus Ha: p > 0.01, where p is the actual proportion of defective circuits in the shipment. If the null hypothesis is not rejected, the shipment is accepted, and the circuits are used in the production of calculators. If the null hypothesis is rejected, the entire shipment is returned to the supplier because of inferior quality. (A shipment is defined to be of inferior quality if it contains more than 1% defective circuits.) In this context, define Type I and Type II errors. (Select all that apply.) a. A Type I error is obtaining convincing evidence that more than 1% of a shipment is defective when in fact (at most) 1% of the shipment is defective. b. A Type I error is not…arrow_forwardAt many college bookstores, students can decide whether to purchase or to rent a textbook for a class. A study was conducted to investigate whether the percent of rented textbooks for all science classes in the state was greater than the percent of rented textbooks for all literature classes in the state. The following hypothesis test was done at the significance level of α=0.05α=0.05. H0:pS=pLHa:pS>pLH0:pS=pLHa:pS>pL In the hypotheses, pSpS represents the proportion of all science textbooks that are rented, and pLpL represents the proportion of all literature textbooks that are rented. All conditions for inference were met, and the resulting pp-value was 0.035. Which of the following is the correct decision for the test? The pp-value is less than αα. Since 0.035<0.050.035<0.05, the null hypothesis is rejected, and the claim is supported. There is convincing statistical evidence that the proportion of all science textbooks that are rented is greater…arrow_forward
- Test the claim that the proportion of people who own cats is larger than 60% at the 0.01 significance level.The null and alternative hypothesis would be: H0:μ=0.6H0:μ=0.6H1:μ≠0.6H1:μ≠0.6 H0:p≤0.6H0:p≤0.6H1:p>0.6H1:p>0.6 H0:μ≤0.6H0:μ≤0.6H1:μ>0.6H1:μ>0.6 H0:μ≥0.6H0:μ≥0.6H1:μ<0.6H1:μ<0.6 H0:p=0.6H0:p=0.6H1:p≠0.6H1:p≠0.6 H0:p≥0.6H0:p≥0.6H1:p<0.6H1:p<0.6 The test is: left-tailed right-tailed two-tailed Based on a sample of 100 people, 67% owned catsThe p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesisarrow_forwardTest the claim that the proportion of people who own cats is smaller than 20% at the 0.005 significance level.The null and alternative hypothesis would be: Select One ______ H0:p≤0.2H0:p≤0.2Ha:p>0.2Ha:p>0.2 _______H0:μ≥0.2H0:μ≥0.2Ha:μ<0.2Ha:μ<0.2 _____H0:μ=0.2H0:μ=0.2Ha:μ≠0.2Ha:μ≠0.2 ______H0:p=0.2H0:p=0.2Ha:p≠0.2Ha:p≠0.2 _______H0:p≥0.2H0:p≥0.2Ha:p<0.2Ha:p<0.2 ______H0:μ≤0.2H0:μ≤0.2Ha:μ>0.2Ha:μ>0.2 The test is: Select One ___two-tailed ___left-tailed ___right-tailed Based on a sample of 600 people, 19% owned catsThe test statistic is: __?__ (Round to 2 decimals)The p-value is: __?__ (Round to 2 decimals)arrow_forwardTest the claim that the proportion of people who own cats is larger than 10% at the 0.01 significance level.The null and alternative hypothesis would be: H0:μ≥0.1H0:μ≥0.1H1:μ<0.1H1:μ<0.1 H0:μ≤0.1H0:μ≤0.1H1:μ>0.1H1:μ>0.1 H0:μ=0.1H0:μ=0.1H1:μ≠0.1H1:μ≠0.1 H0:p≥0.1H0:p≥0.1H1:p<0.1H1:p<0.1 H0:p=0.1H0:p=0.1H1:p≠0.1H1:p≠0.1 H0:p≤0.1H0:p≤0.1H1:p>0.1H1:p>0.1 The test is: two-tailed left-tailed right-tailed Based on a sample of 800 people, 18% owned catsThe p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesisarrow_forward
- An automobile manufacturer is considering using robots for part of its assembly process. Converting to robots is an expensive process, so it will be undertaken only if there is strong evidence that the proportion of defective installations is less for the robots than for human assemblers. Let p denote the actual proportion of defective installations for the robots. It is known that the proportion of defective installations for human assemblers is 0.02. (a) Which of the following pairs of hypotheses should the manufacturer test? H0: p = 0.02 versus Ha: p < 0.02 or H0: p = 0.02 versus Ha: p > 0.02 Explain your answer. H0: p = 0.02 versus Ha: p < 0.02, as the conversion will only happen if the proportion of defective installations is higher for robots.H0: p = 0.02 versus Ha: p < 0.02, as the conversion will only happen if the proportion of defective installations is lower for robots. H0: p = 0.02 versus Ha: p > 0.02, as the conversion will only happen if the…arrow_forwardTest the claim that the proportion of men who own cats is smaller than 70% at the 0.01 significance level. The null and alternative hypothesis would be: H0:μ≥0.7H0:μ≥0.7H1:μ<0.7H1:μ<0.7 H0:p≥0.7H0:p≥0.7H1:p<0.7H1:p<0.7 H0:μ≤0.7H0:μ≤0.7H1:μ>0.7H1:μ>0.7 H0:μ=0.7H0:μ=0.7H1:μ≠0.7H1:μ≠0.7 H0:p≤0.7H0:p≤0.7H1:p>0.7H1:p>0.7 H0:p=0.7H0:p=0.7H1:p≠0.7H1:p≠0.7 Correct The test is: left-tailed right-tailed two-tailed Correct Based on a sample of 300 people, 69% owned cats The test statistic is: (to 2 decimals) The critical value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesisarrow_forwardWhen is a researcher at risk of making a Type II error? Group of answer choices: whenever H0 is rejected whenever H1 is rejected whenever H0 fails to be rejected The risk of a Type II error is independent of the decision from a hypothesis test.arrow_forward
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