BASIC CHEMISTRY (LL) W/MODIFIED MASTERI
BASIC CHEMISTRY (LL) W/MODIFIED MASTERI
17th Edition
ISBN: 9780135232965
Author: Timberlake
Publisher: PEARSON
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Chapter 11.6, Problem 11.53QAP
Interpretation Introduction

(a)

Interpretation:

The number of moles of O2 in 44.8 L of O2 gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0°C (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

Interpretation Introduction

(b)

Interpretation:

The volume in liters occupied by 2.50 mol of N2 gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0°C (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

Interpretation Introduction

(c)

Interpretation:

The volume in liters occupied by 50.0 g of Ar gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0°C (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

Interpretation Introduction

(d)

Interpretation:

The number of grams of H2 present in 1620 mL H2 gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0°C (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

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Chapter 11 Solutions

BASIC CHEMISTRY (LL) W/MODIFIED MASTERI

Ch. 11.2 - Prob. 11.11QAPCh. 11.2 - Prob. 11.12QAPCh. 11.2 - Prob. 11.13QAPCh. 11.2 - Prob. 11.14QAPCh. 11.2 - Prob. 11.15QAPCh. 11.2 - Prob. 11.16QAPCh. 11.2 - Prob. 11.17QAPCh. 11.2 - Prob. 11.18QAPCh. 11.2 - Prob. 11.19QAPCh. 11.2 - Prob. 11.20QAPCh. 11.2 - Prob. 11.21QAPCh. 11.2 - Prob. 11.22QAPCh. 11.2 - Prob. 11.23QAPCh. 11.2 - Prob. 11.24QAPCh. 11.3 - Prob. 11.25QAPCh. 11.3 - Prob. 11.26QAPCh. 11.3 - Prob. 11.27QAPCh. 11.3 - Prob. 11.28QAPCh. 11.3 - Prob. 11.29QAPCh. 11.3 - Prob. 11.30QAPCh. 11.3 - Prob. 11.31QAPCh. 11.3 - Prob. 11.32QAPCh. 11.4 - Prob. 11.33QAPCh. 11.4 - Prob. 11.34QAPCh. 11.4 - Prob. 11.35QAPCh. 11.4 - Prob. 11.36QAPCh. 11.4 - Prob. 11.37QAPCh. 11.4 - Prob. 11.38QAPCh. 11.4 - Prob. 11.39QAPCh. 11.4 - Prob. 11.40QAPCh. 11.4 - Prob. 11.41QAPCh. 11.4 - Prob. 11.42QAPCh. 11.5 - Prob. 11.43QAPCh. 11.5 - Prob. 11.44QAPCh. 11.5 - Prob. 11.45QAPCh. 11.5 - Prob. 11.46QAPCh. 11.5 - Prob. 11.47QAPCh. 11.5 - Prob. 11.48QAPCh. 11.6 - Prob. 11.49QAPCh. 11.6 - Prob. 11.50QAPCh. 11.6 - Prob. 11.51QAPCh. 11.6 - Prob. 11.52QAPCh. 11.6 - Prob. 11.53QAPCh. 11.6 - Prob. 11.54QAPCh. 11.7 - Prob. 11.55QAPCh. 11.7 - Prob. 11.56QAPCh. 11.7 - Prob. 11.57QAPCh. 11.7 - Prob. 11.58QAPCh. 11.7 - Prob. 11.59QAPCh. 11.7 - Prob. 11.60QAPCh. 11.7 - Prob. 11.61QAPCh. 11.7 - Prob. 11.62QAPCh. 11.7 - Prob. 11.63QAPCh. 11.7 - Prob. 11.64QAPCh. 11.8 - Prob. 11.65QAPCh. 11.8 - Prob. 11.66QAPCh. 11.8 - Prob. 11.67QAPCh. 11.8 - Prob. 11.68QAPCh. 11.8 - Prob. 11.69QAPCh. 11.8 - Prob. 11.70QAPCh. 11.9 - Prob. 11.71QAPCh. 11.9 - Prob. 11.72QAPCh. 11.9 - Prob. 11.73QAPCh. 11.9 - Prob. 11.74QAPCh. 11.9 - Prob. 11.75QAPCh. 11.9 - Prob. 11.76QAPCh. 11.9 - Prob. 11.77QAPCh. 11.9 - Prob. 11.78QAPCh. 11 - Prob. 11.79FUCh. 11 - Prob. 11.80FUCh. 11 - Prob. 11.81UTCCh. 11 - Prob. 11.82UTCCh. 11 - Prob. 11.83UTCCh. 11 - Prob. 11.84UTCCh. 11 - Prob. 11.85UTCCh. 11 - Prob. 11.86UTCCh. 11 - Prob. 11.87UTCCh. 11 - Prob. 11.88UTCCh. 11 - Prob. 11.89AQAPCh. 11 - Your spaceship has docked at a space station above...Ch. 11 - Prob. 11.91AQAPCh. 11 - Prob. 11.92AQAPCh. 11 - Prob. 11.93AQAPCh. 11 - Prob. 11.94AQAPCh. 11 - Prob. 11.95AQAPCh. 11 - Prob. 11.96AQAPCh. 11 - Prob. 11.97AQAPCh. 11 - Prob. 11.98AQAPCh. 11 - Prob. 11.99AQAPCh. 11 - Prob. 11.100AQAPCh. 11 - Prob. 11.101AQAPCh. 11 - Prob. 11.102AQAPCh. 11 - Prob. 11.103AQAPCh. 11 - Prob. 11.104AQAPCh. 11 - Prob. 11.105AQAPCh. 11 - Prob. 11.106AQAPCh. 11 - Solid aluminum reacts with aqueous H2SO4 to form...Ch. 11 - Prob. 11.108CQCh. 11 - Prob. 11.109CQCh. 11 - Prob. 11.110CQCh. 11 - Prob. 11.111CQCh. 11 - Prob. 11.112CQCh. 11 - Prob. 11.113CQCh. 11 - Prob. 11.114CQ
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Step by Step Stoichiometry Practice Problems | How to Pass ChemistryMole Conversions Made Easy: How to Convert Between Grams and Moles; Author: Ketzbook;https://www.youtube.com/watch?v=b2raanVWU6c;License: Standard YouTube License, CC-BY