Organic Chemistry As a Second Language: First Semester Topics
Organic Chemistry As a Second Language: First Semester Topics
4th Edition
ISBN: 9781119110668
Author: David R. Klein
Publisher: WILEY
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Chapter 11.8B, Problem 11.82P
Interpretation Introduction

Interpretation:

The reagent used to accomplish the given transformation has to be identified.

Concept Introduction:

Elimination reactions are the one in which the groups are lost and the saturated bonds are converted to unsaturated bonds.  Usually the substitution reaction compete with elimination reaction.

Organic Chemistry As a Second Language: First Semester Topics, Chapter 11.8B, Problem 11.82P , additional homework tip  1

In elimination reaction, the beta proton is removed together with the leaving group to form a double bond.

E2 reaction proceeds through a single step without any formation of intermediates.  The base abstracts a proton form the substrate and the loss of leaving group also happens resulting in the formation of double bond.  E2 stands for bimolecular elimination.

The proton can be abstracted by the base in two different ways leading to a regiochemical outcome.  In the given reaction below, two alkenes are formed as products due to regiochemistry.

Organic Chemistry As a Second Language: First Semester Topics, Chapter 11.8B, Problem 11.82P , additional homework tip  2

The two alkenes that are formed can be given different names.  If the alkene is more substituted means it is known as Zaitsev product, and if the alkene formed is less substituted means it is known as Hofmann product.  Generally more substituted product is the major product (Zaitsev product).

If the reaction is performed with a sterically hindered base, the major product will be less substituted alkene (Hofmann product).  The regiochemical outcome can be decided by choosing the base.  Some of the sterically hindered bases are,

Organic Chemistry As a Second Language: First Semester Topics, Chapter 11.8B, Problem 11.82P , additional homework tip  3

Addition reactions are the one in which the groups are added to an unsaturated double bond.  The double bond is destroyed because the groups are added across the double bond.  If the considered alkene is a symmetrical one, then there is no difference in the product obtained but if the alkene is an unsymmetrical one, then regiochemistry decides the products that are obtained.

When two similar groups are added across a double bond, regiochemistry is irrelevant.  When adding two different groups across the double bond of an unsymmetrical alkene, the regiochemistry becomes relevant.  In simple words, it can be said that, when two different groups are added across a double bond, then regiochemistry becomes relevant.

Markovnikov Addition

    In the vinylic bond, if the bulky group gets substituted in the carbon atom that is more substituted means, it is known as Markovnikov’s addition.

Organic Chemistry As a Second Language: First Semester Topics, Chapter 11.8B, Problem 11.82P , additional homework tip  4

anti-Markovnikov Addition

    In the vinylic bond, if the bulky group gets substituted in the carbon atom that is less substituted means, it is known as anti-Markovnikov’s addition.

Organic Chemistry As a Second Language: First Semester Topics, Chapter 11.8B, Problem 11.82P , additional homework tip  5

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Chapter 11 Solutions

Organic Chemistry As a Second Language: First Semester Topics

Ch. 11.2 - Prob. 11.14PCh. 11.2 - Prob. 11.15PCh. 11.2 - Prob. 11.17PCh. 11.2 - Prob. 11.18PCh. 11.2 - Prob. 11.19PCh. 11.2 - Prob. 11.20PCh. 11.2 - PROBLEMS For each of the following, predict the...Ch. 11.2 - Prob. 11.23PCh. 11.2 - PROBLEMS For each of the following, predict the...Ch. 11.2 - Prob. 11.25PCh. 11.3 - Prob. 11.27PCh. 11.3 - Prob. 11.28PCh. 11.3 - Prob. 11.29PCh. 11.3 - PROBLEMS Predict the products for each of the...Ch. 11.3 - Prob. 11.31PCh. 11.3 - Prob. 11.32PCh. 11.4 - Prob. 11.34PCh. 11.4 - Prob. 11.35PCh. 11.4 - Prob. 11.36PCh. 11.4 - Prob. 11.37PCh. 11.4 - Prob. 11.39PCh. 11.4 - Prob. 11.40PCh. 11.4 - Prob. 11.41PCh. 11.4 - Prob. 11.42PCh. 11.4 - Prob. 11.44PCh. 11.4 - Prob. 11.45PCh. 11.4 - Prob. 11.46PCh. 11.4 - Prob. 11.47PCh. 11.5 - Prob. 11.49PCh. 11.5 - Prob. 11.50PCh. 11.5 - Prob. 11.51PCh. 11.5 - Prob. 11.52PCh. 11.5 - Prob. 11.54PCh. 11.5 - Prob. 11.55PCh. 11.5 - Prob. 11.56PCh. 11.5 - Prob. 11.57PCh. 11.6 - Prob. 11.59PCh. 11.6 - Prob. 11.60PCh. 11.6 - Prob. 11.61PCh. 11.6 - Prob. 11.62PCh. 11.7 - Prob. 11.64PCh. 11.7 - Prob. 11.65PCh. 11.7 - Prob. 11.66PCh. 11.7 - Prob. 11.67PCh. 11.7 - Prob. 11.68PCh. 11.7 - Prob. 11.69PCh. 11.8A - Prob. 11.71PCh. 11.8A - Prob. 11.72PCh. 11.8A - Prob. 11.73PCh. 11.8A - Prob. 11.74PCh. 11.8A - Prob. 11.75PCh. 11.8A - Prob. 11.76PCh. 11.8A - Prob. 11.77PCh. 11.8A - Prob. 11.78PCh. 11.8B - Prob. 11.80PCh. 11.8B - Prob. 11.81PCh. 11.8B - Prob. 11.82PCh. 11.8B - Prob. 11.83PCh. 11.8B - Prob. 11.84PCh. 11.8B - Prob. 11.85PCh. 11.8C - Prob. 11.87PCh. 11.8C - Prob. 11.88PCh. 11.8C - Prob. 11.89PCh. 11.8C - Prob. 11.90PCh. 11.8D - Prob. 11.92PCh. 11.8D - Prob. 11.93PCh. 11.8D - Prob. 11.94PCh. 11.8D - Prob. 11.95PCh. 11.8D - Prob. 11.96PCh. 11.8D - Prob. 11.97PCh. 11.9 - Prob. 11.99PCh. 11.9 - Prob. 11.100PCh. 11.9 - Prob. 11.101PCh. 11.9 - Prob. 11.102PCh. 11.9 - Prob. 11.103PCh. 11.9 - Prob. 11.104PCh. 11.10 - Prob. 11.106PCh. 11.10 - Prob. 11.107PCh. 11.10 - Prob. 11.108PCh. 11.10 - Prob. 11.109PCh. 11.11 - Prob. 11.111PCh. 11.11 - Prob. 11.112PCh. 11.11 - Prob. 11.113PCh. 11.11 - Prob. 11.114PCh. 11.11 - Prob. 11.115PCh. 11.11 - Prob. 11.116PCh. 11.12 - Prob. 11.118PCh. 11.12 - Prob. 11.119PCh. 11.12 - Prob. 11.120PCh. 11.12 - Prob. 11.121PCh. 11.12 - Prob. 11.122PCh. 11.12 - PROBLEMS Predict the products for each of the...
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