(a)
To use technology to find the cumulative probabilities of Xequals
(a)
Answer to Problem 12.18AYK
X | cumulative probabilities |
1 | 0.00394 |
2 | 0.017364 |
3 | 0.051819 |
4 | 0.118145 |
5 | 0.220287 |
6 | 0.351369 |
7 | 0.49556 |
8 | 0.634343 |
9 | 0.75308 |
10 | 0.844508 |
11 | 0.908507 |
12 | 0.949573 |
13 | 0.973897 |
14 | 0.987275 |
15 | 0.994143 |
Explanation of Solution
It is given in the question that the CDC receives reports of
In the cumulative, the FALSE gives the exact value and TRUE gives the less than value.
Thus, the calculation is as:
X | cumulative probabilities |
1 | =POISSON.DIST(AJ116,7.7,TRUE) |
2 | =POISSON.DIST(AJ117,7.7,TRUE) |
3 | =POISSON.DIST(AJ118,7.7,TRUE) |
4 | =POISSON.DIST(AJ119,7.7,TRUE) |
5 | =POISSON.DIST(AJ120,7.7,TRUE) |
6 | =POISSON.DIST(AJ121,7.7,TRUE) |
7 | =POISSON.DIST(AJ122,7.7,TRUE) |
8 | =POISSON.DIST(AJ123,7.7,TRUE) |
9 | =POISSON.DIST(AJ124,7.7,TRUE) |
10 | =POISSON.DIST(AJ125,7.7,TRUE) |
11 | =POISSON.DIST(AJ126,7.7,TRUE) |
12 | =POISSON.DIST(AJ127,7.7,TRUE) |
13 | =POISSON.DIST(AJ128,7.7,TRUE) |
14 | =POISSON.DIST(AJ129,7.7,TRUE) |
15 | =POISSON.DIST(AJ130,7.7,TRUE) |
The result will be as:
X | cumulative probabilities |
1 | 0.00394 |
2 | 0.017364 |
3 | 0.051819 |
4 | 0.118145 |
5 | 0.220287 |
6 | 0.351369 |
7 | 0.49556 |
8 | 0.634343 |
9 | 0.75308 |
10 | 0.844508 |
11 | 0.908507 |
12 | 0.949573 |
13 | 0.973897 |
14 | 0.987275 |
15 | 0.994143 |
(b)
To find out what is the
(b)
Answer to Problem 12.18AYK
Explanation of Solution
It is given in the question that the CDC receives reports of
In the cumulative, the FALSE gives the exact value and TRUE gives the less than value.
Thus, the calculation is as:
P(X>15)= | =1-POISSON.DIST(15,7.7,TRUE) |
The result is as:
P(X>15)= | 0.005857 |
Thus, the probability that the CDC receives reports of more than
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Chapter 12 Solutions
ACHIEVE F/PRACT OF STAT IN LIFE-ACCESS
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