MindTap Engineering for Das/Sobhan's Principles of Geotechnical Engineering, SI Edition, 9th Edition, [Instant Access], 2 terms (12 months)
9th Edition
ISBN: 9781305971264
Author: Braja M. Das; Khaled Sobhan
Publisher: Cengage Learning US
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Chapter 12, Problem 12.23P
(a)
To determine
Find the undrained cohesion at a depth of
(b)
To determine
Find the design value of undrained shear strength by using Bjerrum’s correction factor.
(c)
To determine
Find the new undrained cohesion.
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The results of a consolidated drained triaxial shear test on a normally consolidated clay are shown in the figure. The angle of internal friction is:--
: A specimen of normally consolidated clay is consolidated to 722 kN/m² and
then failed by increasing o, while o, held constant. Find qr and Prif Ø= 26°.
A cylindrical sample of soil soil having a cohesion of 100 kN/m² and angle of
internal friction of 22° is subjected to cell pressure (63) of 80 kN/m².
Determine:
1) Maximum deviator stress at which the sample will failed.
2) Angle made by the failure plan with the axis of sample.
3) Normal and shear stress on failure plan.
A direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the minor principal stress in kPa. Pls include fbd.
Chapter 12 Solutions
MindTap Engineering for Das/Sobhan's Principles of Geotechnical Engineering, SI Edition, 9th Edition, [Instant Access], 2 terms (12 months)
Ch. 12 - Prob. 12.1PCh. 12 - Prob. 12.2PCh. 12 - Prob. 12.3PCh. 12 - Prob. 12.4PCh. 12 - Prob. 12.5PCh. 12 - Prob. 12.6PCh. 12 - Prob. 12.7PCh. 12 - Prob. 12.8PCh. 12 - Prob. 12.9PCh. 12 - Prob. 12.10P
Ch. 12 - Prob. 12.11PCh. 12 - Prob. 12.12PCh. 12 - Prob. 12.13PCh. 12 - Following are the results of...Ch. 12 - Prob. 12.15PCh. 12 - Prob. 12.16PCh. 12 - Prob. 12.17PCh. 12 - Prob. 12.18PCh. 12 - Prob. 12.19PCh. 12 - Prob. 12.20PCh. 12 - Prob. 12.21PCh. 12 - Prob. 12.22PCh. 12 - Prob. 12.23PCh. 12 - Prob. 12.24PCh. 12 - Prob. 12.1CTP
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- Solve this problem graphically and then analytically. A CU triaxial test was performed on a dense sand specimen at a confining pressure 03=40 kPa. The consolidated undrained friction angle of the sand is =39°, and the effective friction angle is d'=34°. Calculate: (a) the major principal stress at failure, o1, (b) the minor and the major effective principal stresses at failure, o'3f and oʻır, and (c) the excess pore water pressure at failure, (Aua)f.arrow_forwardA direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the minor principal stress in kPa. Show the free body diagram. a.53.5 b.136.5 c.36.9 d.64.5arrow_forwardhe following results were obtained from a direct shear test conducted on pure sand: Sample height and diameter = 30 mm and 75 mm respectively. Normal stress = 100 kN/m2 Shear force at failure = 185 N a) Determine the angle of friction for the soil. Round off to one decimal i.e. 99.5! b) What would be the shear force (in N) at failure if the normal stress is 175 kN/m2? Round off to the nearest figure i.e. 300.55 to 301! c) What would be the principal stress at failure? Consider a and barrow_forward
- A series of previous CD tests conducted on a NC clay has established that the ultimate effective friction angle of the clay is 300. Now a CU test is conducted on this soil with an effective cell pressure of 100 kPa. The specimen fails at a deviatoric stress of 100 kPa. Estimate the pore pressure at failure. Given: σ3f′=Kaσ1f′whereKa=1−sinϕ1+sinϕ Please do fast .... ASAP Fastarrow_forwardA direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the major principal stress in kPa. a.174.6 b.246.5 c.163.5 d.146.9arrow_forwardThe stresses on a failure plane in a drained test on a cohesionless soil are as given below: Normal stress, o = 100 kN/m2, Shear stress = 57.73 kN/m2 The failure plane makes an angle of B with the minor principle plane. The value of B will bearrow_forward
- A soil sample is having a cohesion value of 10 kN/m?. A normal stress of 150 kN / m² is applied on the sample and this causes it to fail at shear stress value of 100 kN / m². Calculate the internal friction angle.arrow_forward5. [Shear Strength] ( e). In a series of unconsolidated-undrained triaxial tests on speciments of a fully saturdated clay, the following results were obtained at failure. Minor Principal Stress (КРа) 200 400 600 Major Principal Stress 422 618 820 Calculate the following: a. Cohesion b. Angle of internal frictionarrow_forwardA direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the angle of internal friction in degrees. Include free body diagram. a.33 b.31 c.27 d.29arrow_forward
- A direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the minor principal stress in kPa.arrow_forward1.A dry sand is known to have an angle of internal friction of 29. A triaxial test is planned, where the confining pressure will be 41 kPa. What is the maximum axial stress, in kPa, (major principal stress) that can be applied? Calculate the value to 1 decimal place. Do not provide units in your answer. 2.A clay soil is subjected to a triaxial test under unconsolidated-undrained conditions. At failure, the major and minor principal stresses are 8401 psf and 4875 psf, respectively. What is the shear strength of this soil if the confining pressure is doubled? Provide your answer in psf with no decimals.arrow_forwardA consolidated-drained triaxial test was conducted on a normally consolidated clay.The results were as follows:σ3 = 276 kN/m2(Δσd)f = 276 kN/m2a. Find the angle of friction. ϕ'.b. What is the angle that the failure plane makes with the major principal stress?c. C. Determine the normal stress σ' and the shear stress τf on the failure plane.arrow_forward
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