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MindTap Engineering for Das/Sobhan's Principles of Geotechnical Engineering, SI Edition, 9th Edition, [Instant Access], 2 terms (12 months)
9th Edition
ISBN: 9781305971264
Author: Braja M. Das; Khaled Sobhan
Publisher: Cengage Learning US
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Chapter 12, Problem 12.10P
To determine
Find the soil friction angle
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A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as
follows:
O3 =
150 kN/m?
(Aoa)f= 130 kN/m?
Determine
a. Angle of friction, o'
b. Angle 0 that the failure plane makes with the major principal plane
c. Find the normal stress o' and the shear stress tf on the failure plane
d. Determine the effective normal stress on the plane of maximum shear stress
3- For a normally consolidated clay specimen, the results of a drained triaxial test are as follows: Chamber confining
pressure = 2,610 lb/ft², Deviator stress at failure = 3,655 lb/ft². Determine the soil friction angle, q'.
7.12 A sand specimen was subjected to a drained shear test using hollow cylin-
der test equipment. Failure was caused by increasing the inside pressure while
keeping the outside pressure constant. At failure, o, = 193 kN/m² and o; =
264 kN/m². The inside and outside radii of the specimen were 40 and 60 mm,
respectively.
(a) Calculate the soil friction angle.
(b) Calculate the axial stress on the specimen at failure.
Chapter 12 Solutions
MindTap Engineering for Das/Sobhan's Principles of Geotechnical Engineering, SI Edition, 9th Edition, [Instant Access], 2 terms (12 months)
Ch. 12 - Prob. 12.1PCh. 12 - Prob. 12.2PCh. 12 - Prob. 12.3PCh. 12 - Prob. 12.4PCh. 12 - Prob. 12.5PCh. 12 - Prob. 12.6PCh. 12 - Prob. 12.7PCh. 12 - Prob. 12.8PCh. 12 - Prob. 12.9PCh. 12 - Prob. 12.10P
Ch. 12 - Prob. 12.11PCh. 12 - Prob. 12.12PCh. 12 - Prob. 12.13PCh. 12 - Following are the results of...Ch. 12 - Prob. 12.15PCh. 12 - Prob. 12.16PCh. 12 - Prob. 12.17PCh. 12 - Prob. 12.18PCh. 12 - Prob. 12.19PCh. 12 - Prob. 12.20PCh. 12 - Prob. 12.21PCh. 12 - Prob. 12.22PCh. 12 - Prob. 12.23PCh. 12 - Prob. 12.24PCh. 12 - Prob. 12.1CTP
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- 5- The shear strength of a normally consolidated clay can be given by the equation tf o'tan 27°. Following are the results of a consolidated-undrained test on the clay. • Chamber-confining pressure = 3,130 lb/ft² Deviator stress at failure = 2,510 lb/ft² a) Determine the consolidated-undrained friction angle b) Pore-water pressure developed in the specimen at failurearrow_forwardA triaxial shear test was performed on a well-drained sand sample. The normal stress on the failure plane and the shear stress on the failure plane, at failure were determined to be 6100 psf and 4600 psf, respectively. a. Determine the angle of internal friction of the sand? b. Determine the angle of the failure plane? c. Determine the maximum principal stress? Please answer this asap. For upvote. Thank you very mucharrow_forward2. A triaxial shear test was performed on a well-drained sand sample. The normal stress on the failure plane and the shear stress on the failure plane, at failure was determined to be 6,300 psf and 4,200 psf, respectively. a. Determine the angle of internal friction of the sand. b. Determine the angle of failure plane. c. Determine the maximum principal stress.arrow_forward
- A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as follows: 03 = 276 kN/m? (Aoa)f = 276 kN/m² Determine a. Angle of friction, o' b. Angle 0 that the failure plane makes with the major principal plane c. Find the normal stress o' and the shear stress tf on the failure plane d. Determine the effective normal stress on the plane of maximum shear stress of Effective stress failure envelope ↑ B of 20 276 kN/m2 A oj = 552 kN/m² Normal stress Shear stress © Cengage Learning 2014arrow_forwardA consolidated drained tri-axial test was conducted on normally consolidated clay. The results were: the confining pressure is 300 kPa and the deviators stress is 300 kPa. Compute the angle that the failure plane makes with the major principal axis in degrees. show free body diagram. a.54.74 b.16.3 c.24.72 d.19.47arrow_forwardA consolidated drained tri-axial test was conducted on normally consolidated clay. The results were: the confining pressure is 300 kPa and the deviators stress is 300 kPa. Compute the angle that the failure plane makes with the major principal axis in degrees. show fbd a.16.3 b.24.72 c.54.74 d.19.47arrow_forward
- Problem 3: A consolidated-drained triaxial test is carried out on a sand specimen that is subjected to 80 kN/m? confining pressure. The vertical deviator stress was increased slowly such that there is no built-up of pore water pressure within the specimen. The specimen failed when the addition axial stress reached 240 kN/m?. Find the friction angle of the sand. If another identical sand specimen was subjected to 150 kN/m? confining pressure, what would be the deviator stress at failure.arrow_forwardA consolidated-drained triaxial test is carried out on a sandspecimen that is subjected to 100 kN/m2 confining pressure.The vertical deviator stress was increased slowly such thatthere is no build-up of pore water pressure within the specimen.The specimen failed when the additional axial stress reached 260 kN/m2.a. Find the friction angle of the sand.b. Another identical sand specimen is subjected to200 kN/m2 confining pressure. What would be the deviatorstress at failure?arrow_forward8. For a normally consolidated clay specimen, the results of a drained triaxial test are as follows: Chamber-confining pressure = 125 kN/m? Deviator stress at failure = 175 kN/m? %3D Determine the soil friction angle, o'arrow_forward
- Q-3: A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as follows: 03 = 276 kN/m² (Aod)f=276 kN/m² Determine a. Angle of friction, o' b. Angle that the failure plane makes with the major principal plane c. Find the normal stress o' and the shear stress ty on the failure plane d. Determine the effective normal stress on the plane of maximum shear stress Shear stress Š σí σí σ3 Effective stress failure envelope B σ3 = 276 kN/m² A Normal stress 20 σ = 552 kN/m² Ⓒ Cengage Learning 2014arrow_forward2. The shear strength of a normally consolidated clay can be given by the equation t = ơ' tan 28°. A consolidated-undrained test was conducted on the clay. Following are the results of the test. Chamber confining pressure = 105 KN/m? Deviator stress at failure = 97 KN/m² a. Compute the pore water pressure developed in the clay specimen at failure. b. Compute the consolidated-undrained friction angle 4. What would have been the deviator stress at failure if a drained test had been conducted with the same chamber confining pressure that is o3= 105 KN/m? C.arrow_forwardA consolidated drained tri-axial test was conducted on a normally consolidated clay. The results are as follows: Chamber confining presssure = 138 kPa Deviator stress = 258 kPa a. Compute the friction angle of the soil b. Compute the normal stress at failure c. Compute the shear stress at failurearrow_forward
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