ORGANIC CHEMISTRY:PRIN...(PB)-W/ACCESS
ORGANIC CHEMISTRY:PRIN...(PB)-W/ACCESS
2nd Edition
ISBN: 9780393666151
Author: KARTY
Publisher: NORTON
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Chapter 12, Problem 12.56P
Interpretation Introduction

(a)

Interpretation:

The mechanism that accounts for the formation of the mixture of the products in a given reaction is to be drawn.

Concept introduction:

Electrophilic addition of the molecular chlorine into but-2-ene gives anti-addition of the molecular chlorine via the formation of the chloronium ion as an intermediate. Under similar conditions, molecular chlorine undergoes both syn and anti-addition to (E)-1-phenylprop-1-ene that produces the isomer plus enantiomers. In order to show both syn and anti-addition, the carbocation like intermediate must be generated. Hence, this electrophilic addition proceeds via formation of stable benzylic carbocation intermediate instead of the formation of chloronium ion. As this reaction leads to formation of two different benzylic carbocation intermediates, the reaction yields four different products which consists of two pairs of enantiomers.

Interpretation Introduction

(b)

Interpretation:

The mechanism for the electrophilic addition of the molecular chlorine to the 1-phenylprop-1-ene is different from the one for but-2-ene is to be explained.

Concept introduction:

Electrophilic addition of the molecular chlorine into but-2-ene gives anti-addition of the molecular chlorine via the formation of the chloronium ion as an intermediate. Under similar conditions, molecular chlorine undergoes both syn and anti-addition to (E)-1-phenylprop-1-ene that produces the isomer plus enantiomers. In order to show both syn and anti-addition, the carbocation like intermediate must be generated. Hence, this electrophilic addition proceeds via formation of stable benzylic carbocation intermediate instead of the formation of chloronium ion. As this reaction leads to formation of two different benzylic carbocation intermediates, the reaction yields four different products which consists of two pairs of enantiomers.

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(c) The following reaction shows the electrophilic addition reaction between an alkene compound with hydrogen chloride, HCI. Tindak balas berikut menunjukkan tindak balas penambahan elektrofilik antara sebatian alkena dengan hidrogen klorida, HCI. CI + HCI Major product Draw the mechanism for the formation of major product.
When treated with NaOH, the bromide below gives an alkene by the E2 mechanism, by elimination of the H atom indicated by the arrow: (a) Draw the Newman projection from which elimination takes place. (b) Draw the mechanism. (c) Draw the product with the proper stereochemistry. (d) Assign the proper stereochemical descriptor to the product. (e) Give the rate equation
(c) The following reaction shows the electrophilic addition reaction between an alkene compound with hydrogen chloride, HCI. Tindak balas berikut menunjukkan tindak balas penambahan elektrofilik antara sebatian alkena dengan hidrogen klorida, HCI. + HCI Major product Draw the mechanism for the formation of major product. Lukis mekanisma bagi pembentukan hasil utama berikut.

Chapter 12 Solutions

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