Concept explainers
A sample of aluminum sulfate 18-hydrate, Al2(SO4)3. 18H2O, containing 125.0 mg is dissolved in 1.000 L of solution. Calculate the following for the solution:
- a The molarity of Al2(SO4)3.
- b The molarity of SO42−.
- c The molality of Al2(SO4)3, assuming that the density of the solution is 1.00 g/mL.
Interpretation:
From a sample of
Concept Introduction:
Molality is one of the parameters in expressing the concentration of a solution. It is expressed as,
Molarity is one of the in expressing the concentration of a solution. It is expressed as,
Answer to Problem 12.96QP
Molarity of
Molarity of
Molality of
Explanation of Solution
Given that volume of solution is
Mass and molar mass of
Calculate the number of moles of
One mole of
One mole of
Given that density of solution is
Hence molality of
Number of moles of the solute
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Chapter 12 Solutions
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