Problem Solving with C++, Student Value Edition
10th Edition
ISBN: 9780134543680
Author: Walter Savitch
Publisher: PEARSON
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Chapter 12, Problem 4P
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Is there a special reason why the symbol or name used in the C++ inclusion guard on a library interface file has to be special? A helpful tactic in this situation is to use proof by contradiction: assume that the symbol doesn't need to be unique, and then show what happens when two libraries that are both #included in the same application use the same symbol.
To what end does it matter if the symbol or name used in the C++ inclusion guard on a library interface file be distinct? By assuming that the symbol doesn't need to be unique, and then showing what happens when two libraries that are to be #included in the same application both use the same symbol, we have a helpful proof by contradiction approach at our disposal.
Why must the symbol or name used in the C++ inclusion guard on a library interface file be unique? In this scenario, proof by contradiction is useful—presume that the symbol does not need to be unique and show what happens when two libraries to be #included in the same application share the same symbol?
Chapter 12 Solutions
Problem Solving with C++, Student Value Edition
Ch. 12.1 - Suppose that you are defining an ADT class and...Ch. 12.1 - Which of the following files has a name that ends...Ch. 12.1 - Prob. 3STECh. 12.1 - Suppose you define a class in separate files and...Ch. 12.1 - Suppose you want to change the implementation of...Ch. 12.1 - What is the difference between an ADT you define...Ch. 12.2 - Consider the program shown in Display 12.5. Could...Ch. 12.2 - In Self-Test Exercise 7, we saw that you could not...Ch. 12.2 - Prob. 9STECh. 12.2 - Prob. 10STE
Ch. 12.2 - Consider the following function declarations from...Ch. 12.2 - Would the program in Display 12.8 behave any...Ch. 12.2 - Prob. 13STECh. 12.2 - In Display 12.7 there are two groupings for the...Ch. 12 - Add the following member function to the ADT class...Ch. 12 - Prob. 3PCh. 12 - Redo Practice Programs 2 from Chapter 11, but this...Ch. 12 - This Practice Program explores how the unnamed...Ch. 12 - Prob. 1PPCh. 12 - Redo (or do for the first time) Programming...Ch. 12 - Prob. 3PP
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- When using a C++ inclusion guard on a library interface file, why is it essential that the symbol or name used in the guard not be identical to any other uses of the symbol or name in the guard? Assuming that the symbol does not need to be unique and then showing what occurs when two libraries that are to be #included in the same application share the same symbol is an effective use of the proof by contradiction technique in this circumstance. Here, we have an actual application.arrow_forwardWhy must the symbol or name used in the C++ inclusion guard on a library interface file be different from all other occurrences of that symbol or name? In this case, proof by contradiction may be used to postulate that the symbol does not need to be unique and then show what occurs when two libraries to be #included in the same application share the same symbol. Application in this case?arrow_forwardWhy is it essential that the symbol or name used in the C++ inclusion guard on a library interface file be distinct from all other instances of that symbol or name? Proof by contradiction is a useful strategy to employ in this situation because it allows one to presuppose that the symbol does not need to be unique and then demonstrate what happens when two libraries that are to be #included in the same application share the same symbol. In this case, the application.arrow_forward
- Why is it imperative that the symbol or name used in the C++ inclusion guard on a library interface file be distinct from every other instance of that symbol or name? In this situation, proof by contradiction is a reasonable approach to adopt; presuppose that the symbol does not need to be unique and show what happens when two libraries that are to be #included in the same application share the same symbol.arrow_forwardExplore the concept of versioning in object serialization. How can versioning be implemented to handle changes in object structures over time while maintaining compatibility with older serialized objects?arrow_forwardIs it possible to simultaneously extend two distinct interfaces? Obviously, this isn't the case without some kind of rationale.arrow_forward
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