EBK BIOLOGY
11th Edition
ISBN: 8220102797352
Author: Raven
Publisher: YUZU
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Chapter 12, Problem 4S
In mammals, a variety of genes affect coat color. One of these is a gene with mutant alleles that results in the complete loss of pigment, or albinism. Another controls the type of dark pigment with alleles that lead to black or brown colors. The albinistic trait is recessive, and black is dominant to brown. Two black mice are crossed and yield 9 black:4 albino:3 brown. How would you explain these results?
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Two different genes control the expression of kernel colour in Mexican black corn: black pigment gene B and dotted pigment gene D. Gene B influences the expression of gene D. The dotted phenotype appears only when gene B is in the homozygous recessive state. A colourless variation occurs when both genes are homozygous recessive.
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(Record your answer as a percentage - do not include a decimal).
In Labrador retrievers, two genes determine fur color: the E gene and the B gene. Black fur (B) is dominant to brown fur (b). However, the presence of (ee) will overshadow and create a puppy with yellow fur. Create a Punnett square crossing 2 Labs that are heterozygous for both genes. Then color code your Punnett Square based on the resulting phenotypes. Don’t forget to take epistasis into account!
Pink eye and albinism are two recessive traits found in the deer mouse, Peromyscus maniculatus. In mice with pink eye, the eye is devoid of color and appears pink from the blood vessels within it. Albino mice are completely lacking color both in their fur and in their eyes. F. H. Clark crossed pink‑eyed mice with albino mice; the resulting F1 had normal coloration in their fur and eyes. He then crossed these F1 mice with mice that were pink‑eyed and albino and obtained the mice shown in the table below. It is very hard to distinguish between mice that are albino and mice that are both pink‑eyed and albino, so he combined these two phenotypic classes (F. H. Clark, 1936, Journal of Heredity 27:259−260).
Match the expected numbers of progeny with each phenotype if the genes for pink‑eye and albinism assort independently.
Phenotype
Observed
Expected
wild type, wild type
12
wild type, pink eyes
62
albino, wild type, or pink eyes
78
Total
152
152
Answer…
Chapter 12 Solutions
EBK BIOLOGY
Ch. 12 - What property distinguished Mendels investigation...Ch. 12 - The F1 generation of the monohybrid cross purple...Ch. 12 - The F1 plants from the previous question are...Ch. 12 - In a cross of Aa Bb cc X Aa Bb Cc, what is the...Ch. 12 - An organisms __________ is/are determined by its...Ch. 12 - Phenotypes like height in humans, which show a...Ch. 12 - Japanese four oclocks that are red and tall are...Ch. 12 - If the two genes in the previous question showed...Ch. 12 - What is the probability of obtaining an individual...Ch. 12 - Prob. 4A
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- Coat color in mice is influenced by two genes, one for color (A) and one for the amount of pigment production (C). Mice with the wild type agouti coat color have a yellowish to brownish color. Mice also have a gene that determines the amount of pigment the hair produces. Mouse Coat Phenotype and Genotype Correlation Agouti coat AA, Aa Solid gray/black coat aa Pigment production CC, Cc Albinism cc Multiple crosses were made between male and female mice that were each heterozygous for both traits (AaCc). The data table shows the number of mice of each coat type. Calculate the average F1 generation coat color to answer the question. Coat Color Number of Mice Born in Each Trial Cross Mean Number of Mice 1 2 3 4 5 6 7 8 9 10 Agouti coat 11 8 9 9 10 8 10 7 10 9 Solid gray/black coat 5 2 1 3 4 3 4 3 3 2 Albinism 3 3 6 4 4 3 3 7 4 3 Which…arrow_forwardPink-eye and albino are two recessive traits found in the deer mouse Peromyscus maniculatus. In pink-eyed mice, the eye is devoid of color and appears pink because of the blood vessels within it. Albino mice are completely lacking color, both in their fur and in their eyes. F. H. Clark crossed pink-eyed mice with albino mice; the resulting F1 had normal coloration in their fur and eyes. He then crossed these F1 mice with mice that were pink eyed and albino and obtained the following progeny. It is hard to distinguish between mice that are albino and mice that are both pink eyed and albino, so he combined these two phenotypes (F. H. Clark. 1936. Journal of Heredity 27:259–260). a. Give the expected numbers of progeny with each phenotype if the genes for pink-eye and albino assort independently. b. Use a chi-square test to determine if the observed numbers of progeny fit the number expected with independent assortment.arrow_forwardTwo unlinked loci effect mouse hair color. AA or Aa mice are agouti. Mice with genotype aa are albino because all pigment production and deposition of pigment in hair is blocked. At the second locus, the B allele (black agouti coat) is dominant to the b allele (brown agouti coat). A mouse with an unknown genotype is mated with an albino mouse of genotype bbaa. Half of the offspring are albino, one quarter are black agouti, and one quarter are brown agouti. What is the genotype of the unknown parent?arrow_forward
- Coat color in mice is influenced by two genes, one for color (A) and one for the amount of pigment production (C). Mice with the wild type agouti coat color have a yellowish to brownish color. Mice also have a gene that determines the amount of pigment the hair produces. Multiple crosses were made between male and female mice that were each heterozygous for both traits (AaCc). The data table shows the number of mice of each coat type. Calculate the average F1 generation coat color to answer the question. Which of the following is the most probable interaction between the two genetic loci, A and C, based on the average F1 ratio results? A - The two loci show an epistatic pattern with the loci C epistatic to loci A.B - The two loci show a codominant pattern with both loci affecting coat color.C - The two loci interact in a Mendelian pattern with A being completely dominant over C.D - The two loci show an incomplete dominance pattern with neither loci A nor C being dominant.arrow_forwardCoat color in mice is influenced by two genes, one for color (A) and one for the amount of pigment production (C). Mice with the wild type agouti coat color have a yellowish to brownish color. Mice also have a gene that determines the amount of pigment the hair produces. Multiple crosses were made between male and female mice that were each heterozygous for both traits (AaCc). The data table shows the number of mice of each coat type. Calculate the average F1 generation coat color to answer the question. Which of the following is the most probable interaction between the two genetic loci, A and C, based on the average F1 ratio results? A - The two loci show an epistatic pattern with the loci C epistatic to loci A. B - The two loci show a codominant pattern with both loci affecting coat color. C - The two loci interact in a Mendelian pattern with A being completely dominant over C. D - The two loci show an incomplete dominance pattern with neither loci A nor C being dominant.arrow_forwardIn Drosophila, the vermilion eye color is determined by a recessive allele, v, of an X-linked gene. The wildtype color is determined by the v+ allele and causes a brick red eye color. In a cross of a heterozygous female with a wild type male you observe 340 red eye females, 136 red eye males, and 90 vermillion males. Do these results follow your expectations?arrow_forward
- The production of eye-color pigment in Drosophila requires the dominant allele A. The dominant allele P of a second independent gene turns the pigment to purple, but its recessive allele leaves it red. A fly producing no pigment has white eyes. Two pure lines were crossed with the following results:P red-eyed female white-eyed maleF1 purple-eyed femalesred-eyed malesF1 F1purple eyed 38red eyed 38white eyed 28F both males and females: 2Explain this mode of inheritance, and show the genotypes of the parents, the F1, and the F2.arrow_forwardIn Drosophila, the sepia mutation (se, chromosome 3, position 26) results in dark brown eyes, while cinnabar (cn, chromosome 2, position 57.5) results in bright orange-red eyes. True breeding, wild type females are mated with true breeding males homozygous recessive for both traits. Using Drosophila notation, diagram the P1 and F1 crosses. P1 F1 Fill in the chart with phenotypic ratios that would be expected in the F2 generation. Use the space provided to show your work. Phenotype Females Males Overall (♀and ♂) =1 =1arrow_forwardThe color of Andalusian chickens results from the inheritance of alleles that exhibit incomplete dominance. Black chickens result when 2 alleles for melanin production are inherited (MM). White splashed chickens result from the inheritance of 2 copies of a different allele (mm). The heterozygous condition (Mm) results in their famous bluish color. Predict the genotypes and phenotypes from the following crosses: MM x mm x Mm x Mm.arrow_forward
- As seen in the photo, Labradors come in three colors-- black, brown and yellow. What is the genetic basis for these different coat colors? One gene produces melanin, a pigment which is deposited in the dog's fur and makes the color dark. With this gene, allele B (black) is dominant to allele b. Only in the case of a recessive homozygote (bb) will the dog's phenotype be brown. The regulatory gene is separate from the melanin gene but it acts as a switch, either turning the melanin gene on or turning it off. Allele E is dominant and allows for the melanin to be deposited in the dog's fur ("on" switch), but if the switch gene is a recessive homozygote, the melanin is blocked ("off" switch) and a yellow dog is the result! 1. Two other Labradors mate and produce puppies. Their genotypes are Bbee and BbEe. What color are each parent and what are the phenotypic rations of their offspring in the F1 Generation? Show your work with a Punnett square.arrow_forwardIn mice, an allele for apricot eyes (a) is recessive to an allele for brown eyes (a+). At an independently assorting locus, an allele for tan coat color (t) is recessive to an allele for black coat color (t+). A mouse that is homozygous for brown eyes and black coat color is crossed with a mouse having apricot eyes and a tan coat. The resulting F1 are intercrossed to produce the F2. In a litter of eight F2 mice, what is the probability that two will have apricot eyes and tan coats?arrow_forwardChoose one plsarrow_forward
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