Interpretation : The liters of air required to burn the gasoline are to be calculated.
Concept Introduction : The coefficients of a balanced chemical equation that are transformed into moles are used to calculate the mole ratio, which is a conversion factor.
When converting between a certain number of moles of one reactant or product and moles of another reactant or product, mole ratios are utilized.
The formula to calculate the number of moles is given:
Answer to Problem 74A
The liters of air required to burn the gasoline is
Explanation of Solution
Given information:
A liter of gasoline goes
Gasoline is
The density of octane is
Air is
Distance covered by gasoline is
The amount of octane in
The formula of mass is given as
To calculate the mass of octane, substitute the values in the above formula:
Molar mass of
Molar mass of
Mass of
(octane) is given as follows:
To calculate the moles of
The chemical equation involving octane with oxygen is given as follows:
So,
Volume of
Volume of
Air is
The liters of air is
Chapter 12 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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