Chapter 12.10, Problem 6IP

To determine

To calculate: Lateral and surface area of given pyramid.

Answer to Problem 6IP

Lateral area $=432y{d}^2$ , surface area $=692y{d}^2$

Explanation of Solution

Given information:

The given information is, Rectangular pyramid with width of base 10 yd, area of base $260y{d}^2$ and height of face 12 yd.

Formula used:

Lateral area $=heightofface(length+breadth).$

Surface area $=lateralarea+areaofbase.$

Calculation:

  $\begin{array}{l}givenareaofbase=260yd\\ \therefore length\times 10=260\\ \therefore lengthofbase=26yd\\ \therefore \text{Lateral }area=12(10+26)\\ =432y{d}^2\\ \therefore surfacearea=432+260\\ =692y{d}^2\end{array}$