Chapter 12.7, Problem 22IP

To determine

To find : Volume of given figure.

Answer to Problem 22IP

  $9,24,000f{t}^3$

Explanation of Solution

Given information :

  

The given information is,

h₁ = height of cone = $15$ ft; h₂ = height of cylinder = $55$ ft;

radius of cone = radius of cylinder = $70$ ft.

Formula Used:

Volume of cone = $\frac{1}{3}\pi r^2{h}_1$

Volume of cylinder = $\pi r^2{h}_2$

Calculation :

Volume of given figure = $\frac{1}{3}\times \frac{22}{7}\times {(70)}^2\cdot (15+165)$

  $\begin{array}{l}=\frac{22\times 10\times 70}{3}\times 180\\ =22\times 10\times 70\times 60\\ =9,24,000f{t}^3\end{array}$

Hence, volume of given figure = $9,24,000f{t}^3$