Concept explainers
Make box-and-whisker plots to compare the data sets
Monthly sales:
Kiera’s: 17 50 26 39 6 49 62 40 3
Paul’s: 18 47 32 28 12 49 60 28 15
Draw the box-and-whisker plots to compare the given data sets.
Answer to Problem 19P
Explanation of Solution
Given:
Monthly sales :
K’s : 17 , 50 , 26 , 39 , 6 , 49 , 62 , 40 , 8
P’s : 18 , 47 , 32 , 28 , 12 , 49 , 60 , 28 , 15
Calculation: ,
K’s monthly sales:
Arrange the data in ascending order:
6 , 8 , 17 , 26 , 39 , 40 , 49 , 50 , 62
The minimum is 6.
The first quartile is the median of the lower half of the data set.
Since the total entries are 9, which is odd , So, the lower half is the first
So , the first quartile is
Median = The middle data value =
The third quartile is the median of the upper half of the data set.
Since the total entries are 9, which is odd , So, the upper half is the last
So , the third quartile is
The maximum is 62.
P’s monthly sales:
Arrange the data in ascending order:
12 , 15 , 18 , 28 , 28 , 32 , 47 , 49 , 60
The minimum is 12.
The first quartile is the median of the lower half of the data set.
Since the total entries are 8, which is even , So, the lower half is the first
So , the first quartile is
Median = The middle data value =
The third quartile is the median of the upper half of the data set.
Since the total entries are 9, which is odd , So, the upper half is the last
So , the third quartile is
The maximum is 60.
Represent the above details on the number line. Draw the box through the first and third quartile and make a vertical line through the median , and whisker from the minimum to the maximum data entry.
Since the box of K’s monthly sales is longer than that of P’s monthly sales . So, K has more interquartile range.That is the median of K’s monthly sales varies more widely than the median or middle monthly sales of P.
Chapter 12 Solutions
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