Chapter 12.4, Problem 4CCYP

To determine

Tofind: the probability of $P\left(5\text{or}11\right)$ .

Answer to Problem 4CCYP

  $\begin{array}{l}P\left(5\right)=\frac{1}{3}\\ P\left(11\right)=\frac{1}{6}\end{array}$

Explanation of Solution

Given:

Two six-sided dices are rolled are their sum is recorded.

Calculation:

From previous question, the frequency table is:

Sum	Frequency
2	1
3	2
4	3
5	4
6	5
7	6
8	5
9	4
10	3
11	2
12	1

From the frequency table, the probability is

  $\begin{array}{l}P\left(5\right)=\frac{4}{12}=\frac{1}{3}\\ P\left(11\right)=\frac{2}{12}=\frac{1}{6}\end{array}$