Atkins' Physical Chemistry
Atkins' Physical Chemistry
11th Edition
ISBN: 9780198769866
Author: ATKINS, P. W. (peter William), De Paula, Julio, Keeler, JAMES
Publisher: Oxford University Press
Question
Book Icon
Chapter 13, Problem 13A.2P
Interpretation Introduction

Interpretation:

A table for configurations N=9 for total energy 9ε has to be drawn.  The most probable configuration has to be estimated without evaluating weights.  The weights have to be calculated and the most probable configuration have to be identified.

Concept introduction:

The population of the state is the average number of all the molecules occupying the distribution energy level.  The configuration is the number of ways a molecule can be distributed over the available energy state.  Weight of the configuration is the number of ways a configuration can be achieved.  The configuration with the highest value of weight is the most probable configuration.

Expert Solution & Answer
Check Mark

Answer to Problem 13A.2P

A table for configurations N=9 for total energy 9ε is drawn below.

0ε1ε2ε3ε4ε5ε6ε7ε8ε9ε
8000000001
7100000010
7010000100
7001001000
7000110000
6200000100
6020010000
6003000000
6100200000
6110001000
6101010000
6011100000
5300001000
5031000000
5210010000
5201100000
5112000000
5120100000
4400010000
4310100000
4302000000
4221000000
3500100000
3411000000
2601000000
2520000000
1710000000
0900000000

The most probable configuration estimated without evaluating weights is shown below.

0ε1ε2ε3ε4ε5ε6ε7ε8ε9ε
4221000000

The weights of the various configurations are calculated in the table shown below.

0ε1ε2ε3ε4ε5ε6ε7ε8ε9εW=N!N0!N1!N2!N3!N4!N5!N6!N7!N8!N9!
 8  0 0 0  0 0  0 0 0 1W=9!8!0!0!0!0!0!0!0!0!1!=9×8!8!×1×1×1×1×1×1×1×1×1=9
7  1 00000010W=9!7!1!0!0!0!0!0!0!1!0!=9×8×7!7!×1×1×1×1×1×1×1×1×1=72
7010000100W=9!7!0!0!0!0!0!0!1!0!0!=9×8×7!7!×1×1×1×1×1×1×1×1×1=72
7001001000W=9!7!0!0!1!0!0!1!0!0!0!=9×8×7!7!×1×1×1×1×1×1×1×1×1=72
7  000110000W=9!7!0!0!0!1!1!0!0!0!0!=9×8×7!7!×1×1×1×1×1×1×1×1×1=72
6 200000100W=9!6!2!0!0!0!0!0!1!0!0!=9×8×7×6!6!×2×1×1×1×1×1×1×1×1×1=252
6 020010000W=9!6!0!2!0!0!1!0!0!0!0!=9×8×7×6!6!×1×2×1×1×1×1×1×1×1×1=252
6 003000000W=9!6!0!0!3!0!0!0!1!0!0!=9×8×7×6!6!×1×1×3×2×1×1×1×1×1×1×1=84
6 100200000W=9!6!1!0!0!2!0!0!0!0!0!=9×8×7×6!6!×1×1×1×2×1×1×1×1×1×1×1=252
6 110001000W=9!6!1!1!0!0!0!1!0!0!0!=9×8×7×6!6!×1×1×1×1×1×1×1×1×1=504
6 101010000W=9!6!1!0!1!0!1!0!0!0!0!=9×8×7×6!6!×1×1×1×1×1×1×1×1×1=504
6 011100000W=9!6!0!1!1!1!0!0!0!0!0!=9×8×7×6!6!×1×1×1×1×1×1×1×1×1=504
5 300001000W=9!5!3!0!0!0!0!1!0!0!0!=9×8×7×6×5!5!×3×2×1×1×1×1×1×1×1×1×1=504
5 031000000W=9!5!0!3!1!0!0!0!0!0!0!=9×8×7×6×5!5!×1×3×2×1×1×1×1×1×1×1×1=504
5 210010000W=9!5!2!1!0!0!1!0!0!0!0!=9×8×7×6×5!5!×2×1×1×1×1×1×1×1×1×1=1512
5 201100000W=9!5!2!0!1!1!0!0!0!0!0!=9×8×7×6×5!5!×2×1×1×1×1×1×1×1×1×1=1512
5 112000000W=9!5!1!1!2!0!0!0!0!0!0!=9×8×7×6×5!5!×1×1×2×1×1×1×1×1×1×1=1512
5 120100000W=9!5!1!2!0!1!0!0!0!0!0!=9×8×7×6×5!5!×2×1×1×1×1×1×1×1×1×1=1512
4 400010000W=9!4!4!0!0!0!1!0!0!0!0!=9×8×7×6×5×4!4!×4×3×2×1×1×1×1×1×1×1×1×1=630
4 310100000W=9!4!3!1!0!1!0!0!0!0!0!=9×8×7×6×5×4!4!×3×2×1×1×1×1×1×1×1×1×1=2520
4 302000000W=9!4!3!0!2!0!0!0!0!0!0!=9×8×7×6×5×4!4!×3×2×1×2×1×1×1×1×1×1×1=1260
4 221000000W=9!4!2!2!1!0!0!0!0!0!0!=9×8×7×6×5×4!4!×2×2×1×1×1×1×1×1×1=3780
3 500100000W=9!3!5!0!0!1!0!0!0!0!0!=9×8×7×6×5!3×2×5!×1×1×1×1×1×1×1×1=504
3 411000000W=9!3!4!1!1!0!0!0!0!0!0!=9×8×7×6×5×4!3×2×4!×1×1×1×1×1×1×1×1=2520
2 601000000W=9!2!6!0!1!0!0!0!0!0!0!=9×8×7×6!2×1×6!×1×1×1×1×1×1×1×1=252
2 520000000W=9!2!5!2!1!0!0!0!0!0!0!=9×8×7×6×5!2×1×5!×2×1×1×1×1×1×1×1=756
1 710000000W=9!1!7!1!0!0!0!0!0!0!0!=9×8×7!1×7!×1×1×1×1×1×1×1×1=72
0 900000000W=9!0!9!0!0!0!0!0!0!0!0!=9!1×9!×1×1×1×1×1×1×1×1=1

The most probable configuration is shown below.

0ε1ε2ε3ε4ε5ε6ε7ε8ε9ε
4221000000

Explanation of Solution

The total energy of the sample is 9ε.

The total number of molecules in the sample is 9.

A table for configurations for total energy 9ε is drawn below.

0ε1ε2ε3ε4ε5ε6ε7ε8ε9ε
8000000001
7100000010
7010000100
7001001000
7000110000
6200000100
6020010000
6003000000
6100200000
6110001000
6101010000
6011100000
5300001000
5031000000
5210010000
5201100000
5112000000
5120100000
4400010000
4310100000
4302000000
4221000000
3500100000
3411000000
2601000000
2520000000
1710000000
0900000000

The most probable configuration can be estimated to be the one in which the population of the higher states is not more than the population of the previous state.  This criterion is fulfilled by the configuration given below.

0ε1ε2ε3ε4ε5ε6ε7ε8ε9ε
4221000000

The expression to determine the weight of the configuration (W) is shown below.

  W=N!N0!N1!N2!N3!N4!N5!N6!N7!N8!N9!        (1)

Where,

  • N is the total number of objects in the system.
  • N0,N1,N2... are the number of objects in the ground state, in state 1 and so on.

The value of N is 9.

The value of N0 is 8.

The value of N1 is 0.

The value of N2 is 0.

The value of N3 is 0.

The value of N4 is 0.

The value of N5 is 0.

The value of N6 is 0.

The value of N7 is 0.

The value of N8 is 0.

The value of N9 is 1.

Substitute the value of N and N0,N1,N2,N3,N4,N5,N6,N7,N8,N9 in equation (1) as shown below.

  W=9!8!0!0!0!0!0!0!0!0!1!=9×8!8!×1×1×1×1×1×1×1×1×1=9_

Similarly, the weights of the various configurations are calculated in the table shown below.

0ε1ε2ε3ε4ε5ε6ε7ε8ε9εW=N!N0!N1!N2!N3!N4!N5!N6!N7!N8!N9!
 8  0 0 0  0 0  0 0 0 1W=9!8!0!0!0!0!0!0!0!0!1!=9×8!8!×1×1×1×1×1×1×1×1×1=9
7  1 00000010W=9!7!1!0!0!0!0!0!0!1!0!=9×8×7!7!×1×1×1×1×1×1×1×1×1=72
7010000100W=9!7!0!0!0!0!0!0!1!0!0!=9×8×7!7!×1×1×1×1×1×1×1×1×1=72
7001001000W=9!7!0!0!1!0!0!1!0!0!0!=9×8×7!7!×1×1×1×1×1×1×1×1×1=72
7  000110000W=9!7!0!0!0!1!1!0!0!0!0!=9×8×7!7!×1×1×1×1×1×1×1×1×1=72
6 200000100W=9!6!2!0!0!0!0!0!1!0!0!=9×8×7×6!6!×2×1×1×1×1×1×1×1×1×1=252
6 020010000W=9!6!0!2!0!0!1!0!0!0!0!=9×8×7×6!6!×1×2×1×1×1×1×1×1×1×1=252
6 003000000W=9!6!0!0!3!0!0!0!1!0!0!=9×8×7×6!6!×1×1×3×2×1×1×1×1×1×1×1=84
6 100200000W=9!6!1!0!0!2!0!0!0!0!0!=9×8×7×6!6!×1×1×1×2×1×1×1×1×1×1×1=252
6 110001000W=9!6!1!1!0!0!0!1!0!0!0!=9×8×7×6!6!×1×1×1×1×1×1×1×1×1=504
6 101010000W=9!6!1!0!1!0!1!0!0!0!0!=9×8×7×6!6!×1×1×1×1×1×1×1×1×1=504
6 011100000W=9!6!0!1!1!1!0!0!0!0!0!=9×8×7×6!6!×1×1×1×1×1×1×1×1×1=504
5 300001000W=9!5!3!0!0!0!0!1!0!0!0!=9×8×7×6×5!5!×3×2×1×1×1×1×1×1×1×1×1=504
5 031000000W=9!5!0!3!1!0!0!0!0!0!0!=9×8×7×6×5!5!×1×3×2×1×1×1×1×1×1×1×1=504
5 210010000W=9!5!2!1!0!0!1!0!0!0!0!=9×8×7×6×5!5!×2×1×1×1×1×1×1×1×1×1=1512
5 201100000W=9!5!2!0!1!1!0!0!0!0!0!=9×8×7×6×5!5!×2×1×1×1×1×1×1×1×1×1=1512
5 112000000W=9!5!1!1!2!0!0!0!0!0!0!=9×8×7×6×5!5!×1×1×2×1×1×1×1×1×1×1=1512
5 120100000W=9!5!1!2!0!1!0!0!0!0!0!=9×8×7×6×5!5!×2×1×1×1×1×1×1×1×1×1=1512
4 400010000W=9!4!4!0!0!0!1!0!0!0!0!=9×8×7×6×5×4!4!×4×3×2×1×1×1×1×1×1×1×1×1=630
4 310100000W=9!4!3!1!0!1!0!0!0!0!0!=9×8×7×6×5×4!4!×3×2×1×1×1×1×1×1×1×1×1=2520
4 302000000W=9!4!3!0!2!0!0!0!0!0!0!=9×8×7×6×5×4!4!×3×2×1×2×1×1×1×1×1×1×1=1260
4 221000000W=9!4!2!2!1!0!0!0!0!0!0!=9×8×7×6×5×4!4!×2×2×1×1×1×1×1×1×1=3780
3 500100000W=9!3!5!0!0!1!0!0!0!0!0!=9×8×7×6×5!3×2×5!×1×1×1×1×1×1×1×1=504
3 411000000W=9!3!4!1!1!0!0!0!0!0!0!=9×8×7×6×5×4!3×2×4!×1×1×1×1×1×1×1×1=2520
2 601000000W=9!2!6!0!1!0!0!0!0!0!0!=9×8×7×6!2×1×6!×1×1×1×1×1×1×1×1=252
2 520000000W=9!2!5!2!1!0!0!0!0!0!0!=9×8×7×6×5!2×1×5!×2×1×1×1×1×1×1×1=756
1 710000000W=9!1!7!1!0!0!0!0!0!0!0!=9×8×7!1×7!×1×1×1×1×1×1×1×1=72
0 900000000W=9!0!9!0!0!0!0!0!0!0!0!=9!1×9!×1×1×1×1×1×1×1×1=1

The most probable configuration is the one which has the highest weight.

Therefore, the most probable configurations are tabulated below.

0ε1ε2ε3ε4ε5ε6ε7ε8ε9ε
4221000000

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Chapter 13 Solutions

Atkins' Physical Chemistry

Ch. 13 - Prob. 13A.1AECh. 13 - Prob. 13A.1BECh. 13 - Prob. 13A.2AECh. 13 - Prob. 13A.2BECh. 13 - Prob. 13A.3AECh. 13 - Prob. 13A.3BECh. 13 - Prob. 13A.4AECh. 13 - Prob. 13A.4BECh. 13 - Prob. 13A.5AECh. 13 - Prob. 13A.5BECh. 13 - Prob. 13A.6AECh. 13 - Prob. 13A.6BECh. 13 - Prob. 13A.1PCh. 13 - Prob. 13A.2PCh. 13 - Prob. 13A.4PCh. 13 - Prob. 13A.5PCh. 13 - Prob. 13A.6PCh. 13 - Prob. 13A.7PCh. 13 - Prob. 13B.1DQCh. 13 - Prob. 13B.2DQCh. 13 - Prob. 13B.3DQCh. 13 - Prob. 13B.1AECh. 13 - Prob. 13B.1BECh. 13 - Prob. 13B.2AECh. 13 - Prob. 13B.2BECh. 13 - Prob. 13B.3AECh. 13 - Prob. 13B.3BECh. 13 - Prob. 13B.4AECh. 13 - Prob. 13B.4BECh. 13 - Prob. 13B.7AECh. 13 - Prob. 13B.7BECh. 13 - Prob. 13B.8AECh. 13 - Prob. 13B.8BECh. 13 - Prob. 13B.9AECh. 13 - Prob. 13B.9BECh. 13 - Prob. 13B.10AECh. 13 - Prob. 13B.10BECh. 13 - Prob. 13B.11AECh. 13 - Prob. 13B.11BECh. 13 - Prob. 13B.12AECh. 13 - Prob. 13B.12BECh. 13 - Prob. 13B.4PCh. 13 - Prob. 13B.5PCh. 13 - Prob. 13B.6PCh. 13 - Prob. 13B.7PCh. 13 - Prob. 13B.8PCh. 13 - Prob. 13B.10PCh. 13 - Prob. 13C.1DQCh. 13 - Prob. 13C.2DQCh. 13 - Prob. 13C.1AECh. 13 - Prob. 13C.1BECh. 13 - Prob. 13C.6AECh. 13 - Prob. 13C.6BECh. 13 - Prob. 13C.7AECh. 13 - Prob. 13C.7BECh. 13 - Prob. 13C.3PCh. 13 - Prob. 13C.7PCh. 13 - Prob. 13C.8PCh. 13 - Prob. 13C.9PCh. 13 - Prob. 13D.1DQCh. 13 - Prob. 13D.2DQCh. 13 - Prob. 13D.3DQCh. 13 - Prob. 13D.4DQCh. 13 - Prob. 13D.1AECh. 13 - Prob. 13D.1BECh. 13 - Prob. 13D.1PCh. 13 - Prob. 13D.2PCh. 13 - Prob. 13E.1DQCh. 13 - Prob. 13E.2DQCh. 13 - Prob. 13E.3DQCh. 13 - Prob. 13E.4DQCh. 13 - Prob. 13E.5DQCh. 13 - Prob. 13E.6DQCh. 13 - Prob. 13E.1AECh. 13 - Prob. 13E.1BECh. 13 - Prob. 13E.2AECh. 13 - Prob. 13E.2BECh. 13 - Prob. 13E.3AECh. 13 - Prob. 13E.3BECh. 13 - Prob. 13E.4AECh. 13 - Prob. 13E.4BECh. 13 - Prob. 13E.5AECh. 13 - Prob. 13E.5BECh. 13 - Prob. 13E.6AECh. 13 - Prob. 13E.6BECh. 13 - Prob. 13E.7AECh. 13 - Prob. 13E.7BECh. 13 - Prob. 13E.8AECh. 13 - Prob. 13E.8BECh. 13 - Prob. 13E.9AECh. 13 - Prob. 13E.9BECh. 13 - Prob. 13E.1PCh. 13 - Prob. 13E.2PCh. 13 - Prob. 13E.3PCh. 13 - Prob. 13E.4PCh. 13 - Prob. 13E.7PCh. 13 - Prob. 13E.9PCh. 13 - Prob. 13E.10PCh. 13 - Prob. 13E.11PCh. 13 - Prob. 13E.14PCh. 13 - Prob. 13E.15PCh. 13 - Prob. 13E.16PCh. 13 - Prob. 13E.17PCh. 13 - Prob. 13F.1DQCh. 13 - Prob. 13F.2DQCh. 13 - Prob. 13F.3DQCh. 13 - Prob. 13F.1AECh. 13 - Prob. 13F.1BECh. 13 - Prob. 13F.2AECh. 13 - Prob. 13F.2BECh. 13 - Prob. 13F.3AECh. 13 - Prob. 13F.3BECh. 13 - Prob. 13F.3PCh. 13 - Prob. 13F.4PCh. 13 - Prob. 13F.5PCh. 13 - Prob. 13F.6PCh. 13 - Prob. 13.1IA
Knowledge Booster
Background pattern image
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY