EBK DATA STRUCTURES AND ALGORITHMS IN C
4th Edition
ISBN: 9781285415017
Author: DROZDEK
Publisher: YUZU
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Write a Regular Expression (RE) for:
The set of strings over alphabet {0, 1} with 011 as a substring
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Write a Program that, given two strings like example and ampleex, can identify whether one of them is a cyclic rotation of the other.
Given two strings A and B, find the minimum number of times A has to be repeated such that B is a substring of it. If no such solution, return -1.For example, with A = "abcd" and B = "cdabcdab".Return 3, because by repeating A three times (“abcdabcdabcd”), B is a substring of it; and B is not a substring of A repeated two times ("abcdabcd").Note:The length of A and B will be between 1 and 10000.Reference: https://leetcode.com/problems/repeated-string-match/description/"""def repeat_string(A, B): count = 1 tmp = A max_count = (len(B) / len(A)) + 1 while not(B in tmp): tmp = tmp + A if (count > max_count): count = -1 break.
Chapter 13 Solutions
EBK DATA STRUCTURES AND ALGORITHMS IN C
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- Write a program in elixir to iterate over the enum of strings and print all the elementsarrow_forwardPrint all permutation of string in JAVA with repeat alsoarrow_forwardNow add the-dflag, and change the number of loops (-l) from 1 to highernumbers. What happens? Does the code (always) deadlock?arrow_forward
- Write down the algorithm (not code) to search a string in a BST?arrow_forwardUse JFLAP to create a standard TM that does not use transitions from final states, which takes genetic strings as input, and accepts L = { w | w starts with C, ends with T, and #A(w) % 3 = #G(w) % 2}. For example, CAGGGT ∈ L; w = CAAAT ∈ L (note that the number of G's in w = 0, and 0 % 2 = 0); w = CAGGT ∉ L because the number of A's in w % 3 = 1, but the # of G's in w % 2 = 0; and AGGGT ∉ L because it does not start with C.arrow_forwardGiven a string S, determine whether it can be split into two non-empty palindrome strings. If yes, then output two palindrome strings A and B where the concatenation of A and B is S, i.e. S = A + B.If the answer is no, output NOarrow_forward
- For the definition of x ∈ EXPR , na(x) denotes the number of a’s in the string, and we will use nop(x) to stand for the number of operators in x (the number of occurrences of + or ∗). Show that for every x ∈ EXPR, na(x)= 1 + nop(x).arrow_forwardList all strings in L whose length is less than 5, where L is defined by the regular expression (a + b)* ba (a + ab)*arrow_forwardFind all strings in L ((ab + b)∗ b (a + ab)∗) of length less than four.arrow_forward
- How would you extend the Rabin-Karp method to the problem of searching a text string for an occurrence of any one of a given set of k patterns? Start by assuming that all k patterns have the same length. Then generalize your solution to allow the patterns to have different lengths?arrow_forwardRefine the is_palindrome function to work with arbitrary strings, by ignoring non-letter characters and the distinction between upper- and lowercase letters. For example, if the input string is "Madam, I’m Adam!" then you’d first strip off the last character because it isn’t a letter, and recursively check whether the shorter string "Madam, I’m Adam" is a palindrome. c++arrow_forwardDraw the BST that results when these words are inserted in the order given.public, exit, while, bool, else, private, switcharrow_forward
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