Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card
Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card
9th Edition
ISBN: 9781305780170
Author: John E. McMurry
Publisher: Cengage Learning
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Chapter 13.SE, Problem 47AP

How many absorptions would you expect to observe in the 13C NMR spectra of the following compounds?

(a) 1,1-Dimethylcyclohexane

(b) CH3CH2OCH3

(c) tert-Butylcyclohexane

(d) 3-Methyl-l-pentyne

(e) cis-1,2-Dimethylcyclohexane

(f) Cyclohexanone

Expert Solution
Check Mark
Interpretation Introduction

a)

Interpretation:

The structure of an given molecular formula C8H16 to be predicted using 13CNMR spectra.

Concept introduction:

The 13CNMR spectrum gives information on the different electronic environments of carbon. As like 1HNMR, the number of signals generated in 13CNMR are predicted by performing symmetry operations (rotation or reflection symmetry). Only chemical shift values are reported in the spectrum but not the multiplicity and integration values because the coupling between two neighboring 13C - 13C nuclei are weakly involved due to the low abundance of 13C isotopes of carbon atom.

Broadband-decoupled 13CNMR spectrum: The spectra provide information regarding the total number of carbon environments.

DEPT (Distortionless enhancement by polarization transfer):

i) DEPT -90: The spectrum exhibits signal only from CH group and no signals from CH3, CH2, CH and quaternary carbon (carbon with no protons).

ii) DEPT -135: The spectrum exhibits CH3 groups and CH groups as positive signals (pointing up); CH2 groups appear as negative signals (pointing down) and quaternary carbon does not appear.

The signals appear in each type of spectrum:

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  1

To identify:

The structure of given molecular formula C8H16.

Answer to Problem 47AP

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  2

Explanation of Solution

Calculate HDI value:

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  3

The HDI calculation led to confirm about the presence of a double bond or a ring.

Interpret the given 13CNMR spectrum:

Broadband - decoupled spectrum:

The spectrum shows five signals whereas the given molecular formula also has eight carbon atoms. Thus all the eight carbons have chemically different electronic environments showing signals.

i) The five signals in the region of 0-50ppm indicate the sp3 hybridized carbon atoms which can be methyl / methylene or Methine groups.

DEPT -90: Spectrum has no signals led to confirmation of no CH group in the structure.

DEPT -135 (gives signals of CH2, CH3 and C groups):

ii) The two positive signals indicate the presence of two methyl groups as no signals appear in the DEPT -90 spectrum.

iii) The three negative signals indicate the presence of four methylene groups; only methylene groups appear negative in the spectrum.

iv) So far the group of fragments obtained is

Two -CH3, -C-, four -CH2

From the fragments (CH3 + CH3 + (CH2)5 + C = 16 protons) sixteen protons are obtained whereas the total number of protons from the molecular formula is also sixteen.

The possible structures are:

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  4

The first structure possesses rotational symmetry and exhibits fewer signals in the spectrum and gets cancelled out.

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  5

Conclusion

The structure of a given molecular formula C8H16 is predicted using 13CNMR spectra.

Expert Solution
Check Mark
Interpretation Introduction

b)

Interpretation:

The structure of an given molecular formula C8H16 to be predicted using 13CNMR spectra.

Concept introduction:

The 13CNMR spectrum gives information on the different electronic environments of carbon. As like 1HNMR, the number of signals generated in 13CNMR are predicted by performing symmetry operations (rotation or reflection symmetry). Only chemical shift values are reported in the spectrum but not the multiplicity and integration values because the coupling between two neighboring 13C - 13C nuclei are weakly involved due to the low abundance of 13C isotopes of carbon atom.

Broadband-decoupled 13CNMR spectrum: The spectra provide information regarding the total number of carbon environments.

DEPT (Distortionless enhancement by polarization transfer):

i) DEPT -90: The spectrum exhibits signal only from CH group and no signals from CH3, CH2, CH and quaternary carbon (carbon with no protons).

ii) DEPT -135: The spectrum exhibits CH3 groups and CH groups as positive signals (pointing up); CH2 groups appear as negative signals (pointing down) and quaternary carbon does not appear.

The signals appear in each type of spectrum:

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  6

To identify:

The structure of given molecular formula C3H8O.

Answer to Problem 47AP

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  7

Explanation of Solution

Calculate HDI:

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  8

The HDI calculation led to confirm about the absence of a double bond or a ring.

Interpret the given 13CNMR spectrum:

Broadband - decoupled spectrum:

The spectrum shows three signals whereas the given molecular formula also has three carbon atoms. Thus all the three carbons have chemically different electronic environments showing signals.

i) The five signals in the region of 0-50ppm indicate the sp3 hybridized carbon atoms which can be methyl / methylene groups.

DEPT -90: Spectrum has no signals led to confirmation of no CH group in the structure.

DEPT -135 (gives signals of CH2, CH3 groups):

ii) The two positive signals indicate the presence of two methyl groups as no signals appear in the DEPT -90 spectrum.

iii) The spectrum shows three signals whereas the given molecular formula also has three carbon atoms. Thus all the three carbons have chemically different electronic environments showing signals.

iv) So far the group of fragments obtained is

Two -CH3, -CH2

From the fragments (CH3 + CH3 + CH2 = 8 protons) eight protons are obtained whereas the total number of protons from the molecular formula is also eight.

Conclusion

The structure of a given molecular formula C3H8O is predicted using 13CNMR spectra.

Expert Solution
Check Mark
Interpretation Introduction

c)

Interpretation:

The structure of an given molecular formula C8H16 to be predicted using 13CNMR spectra.

Concept introduction:

The 13CNMR spectrum gives information on the different electronic environments of carbon. As like 1HNMR, the number of signals generated in 13CNMR are predicted by performing symmetry operations (rotation or reflection symmetry). Only chemical shift values are reported in the spectrum but not the multiplicity and integration values because the coupling between two neighboring 13C - 13C nuclei are weakly involved due to the low abundance of 13C isotopes of carbon atom.

Broadband-decoupled 13CNMR spectrum: The spectra provide information regarding the total number of carbon environments.

DEPT (Distortionless enhancement by polarization transfer):

i) DEPT -90: The spectrum exhibits signal only from CH group and no signals from CH3, CH2, CH and quaternary carbon (carbon with no protons).

ii) DEPT -135: The spectrum exhibits CH3 groups and CH groups as positive signals (pointing up); CH2 groups appear as negative signals (pointing down) and quaternary carbon does not appear.

The signals appear in each type of spectrum:

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  9

To identify:

The structure of given molecular formula C10H20.

Answer to Problem 47AP

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  10

Explanation of Solution

Calculate HDI:

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  11

The HDI calculation led to confirm about the presence of a double bond or a ring.

Interpret the given 13CNMR spectrum:

Broadband - decoupled spectrum:

The spectrum shows six signals whereas the given molecular formula also has ten carbon atoms. Thus all the ten carbons have chemically different electronic environments showing signals.

i) The two signals in the region of 0-50ppm indicate the sp3 hybridized carbon atoms which can be methyl / methylene groups.

DEPT -90: Spectrum has signals led to confirmation of CH group in the structure.

DEPT -135 (gives signals of CH2, C, CH3 groups):

ii) The two positive signals indicate the presence of three methyl groups as no signals appear in the DEPT -90 spectrum.

iii) The three negative signals indicate the presence of five methylene groups; only methylene groups appear negative in the spectrum.

iv) So far the group of fragments obtained is

Two -CH3, -CH2

From the fragments (CH3)3 + (CH2)5 + CH + C = 20 protons) twenty protons are obtained whereas the total number of protons from the molecular formula is also twenty.

Conclusion

The structure of a given molecular formula C10H20 is predicted using 13CNMR spectra.

Expert Solution
Check Mark
Interpretation Introduction

d)

Interpretation:

The structure of an given molecular formula C8H16 to be predicted using 13CNMR spectra.

Concept introduction:

The 13CNMR spectrum gives information on the different electronic environments of carbon. As like 1HNMR, the number of signals generated in 13CNMR are predicted by performing symmetry operations (rotation or reflection symmetry). Only chemical shift values are reported in the spectrum but not the multiplicity and integration values because the coupling between two neighboring 13C - 13C nuclei are weakly involved due to the low abundance of 13C isotopes of carbon atom.

Broadband-decoupled 13CNMR spectrum: The spectra provide information regarding the total number of carbon environments.

DEPT (Distortionless enhancement by polarization transfer):

i) DEPT -90: The spectrum exhibits signal only from CH group and no signals from CH3, CH2, CH and quaternary carbon (carbon with no protons).

ii) DEPT -135: The spectrum exhibits CH3 groups and CH groups as positive signals (pointing up); CH2 groups appear as negative signals (pointing down) and quaternary carbon does not appear.

The signals appear in each type of spectrum:

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  12

To identify:

The structure of given molecular formula C6H10.

Answer to Problem 47AP

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  13

Explanation of Solution

Calculate HDI:

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  14

The HDI calculation led to confirm about the presence of a double bond or a ring. (two unsaturated degree).

Interpret the given 13CNMR spectrum:

Broadband - decoupled spectrum:

The spectrum shows six signals whereas the given molecular formula also has six carbon atoms. Thus all the six carbons have chemically different electronic environments showing signals.

i) The two signals in the region of 0-50ppm indicate the sp3 hybridized carbon atoms which can be methyl / methylene groups.

DEPT -90: Spectrum has signals led to confirmation of CH group in the structure.

DEPT -135 (gives signals of CH2, C, CH3 groups):

ii) The four positive signals indicate the presence of two methyl groups as no signals appear in the DEPT -90 spectrum.

iii) The negative signals indicate the presence of methylene groups; only methylene groups appear negative in the spectrum.

iv) So far the group of fragments obtained is

Two -CH3, -CH2

From the fragments (CH3)2 + CH2 + (CH)2 + C = 10 protons) ten protons are obtained whereas the total number of protons from the molecular formula is also ten.

Conclusion

The structure of a given molecular formula C6H10 is predicted using 13CNMR spectra.

Expert Solution
Check Mark
Interpretation Introduction

e)

Interpretation:

The structure of an given molecular formula C8H16 to be predicted using 13CNMR spectra.

Concept introduction:

The 13CNMR spectrum gives information on the different electronic environments of carbon. As like 1HNMR, the number of signals generated in 13CNMR are predicted by performing symmetry operations (rotation or reflection symmetry). Only chemical shift values are reported in the spectrum but not the multiplicity and integration values because the coupling between two neighboring 13C - 13C nuclei are weakly involved due to the low abundance of 13C isotopes of carbon atom.

Broadband-decoupled 13CNMR spectrum: The spectra provide information regarding the total number of carbon environments.

DEPT (Distortionless enhancement by polarization transfer):

i) DEPT -90: The spectrum exhibits signal only from CH group and no signals from CH3, CH2, CH and quaternary carbon (carbon with no protons).

ii) DEPT -135: The spectrum exhibits CH3 groups and CH groups as positive signals (pointing up); CH2 groups appear as negative signals (pointing down) and quaternary carbon does not appear.

The signals appear in each type of spectrum:

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  15

To identify:

The structure of given molecular formula C8H16.

Answer to Problem 47AP

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  16

Explanation of Solution

Calculate HDI:

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  17

The HDI calculation led to confirm about the presence of a double bond or a ring.

Interpret the given 13CNMR spectrum:

Broadband - decoupled spectrum:

The spectrum shows four signals whereas the given molecular formula also has eight carbon atoms. Thus all the eight carbons have chemically different electronic environments showing signals.

i) The four signals in the region of 0-50ppm indicate the sp3 hybridized carbon atoms which can be methyl / methylene or Methine groups.

DEPT -90: Spectrum has no signals led to confirmation of CH group in the structure.

DEPT -135 (gives signals of CH2, CH3 and CH groups):

ii) The two positive signals indicate the presence of two methyl groups as no signals appear in the DEPT -90 spectrum.

iii) The two negative signals indicate the presence of four methylene groups; only methylene groups appear negative in the spectrum.

iv) So far the group of fragments obtained is

Two -CH3, -CH-, four -CH2

From the fragments (CH3 + CH3 + (CH2)4 + (CH)2 = 16 protons) sixteen protons are obtained whereas the total number of protons from the molecular formula is also sixteen.

Conclusion

The structure of a given molecular formula C8H16 is predicted using 13CNMR spectra.

Expert Solution
Check Mark
Interpretation Introduction

f)

Interpretation:

The structure of an given molecular formula C8H16 to be predicted using 13CNMR spectra.

Concept introduction:

The 13CNMR spectrum gives information on the different electronic environments of carbon. As like 1HNMR, the number of signals generated in 13CNMR are predicted by performing symmetry operations (rotation or reflection symmetry). Only chemical shift values are reported in the spectrum but not the multiplicity and integration values because the coupling between two neighboring 13C - 13C nuclei are weakly involved due to the low abundance of 13C isotopes of carbon atom.

Broadband-decoupled 13CNMR spectrum: The spectra provide information regarding the total number of carbon environments.

DEPT (Distortionless enhancement by polarization transfer):

i) DEPT -90: The spectrum exhibits signal only from CH group and no signals from CH3, CH2, CH and quaternary carbon (carbon with no protons).

ii) DEPT -135: The spectrum exhibits CH3 groups and CH groups as positive signals (pointing up); CH2 groups appear as negative signals (pointing down) and quaternary carbon does not appear.

The signals appear in each type of spectrum:

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  18

To identify:

The structure of given molecular formula C6H10O.

Answer to Problem 47AP

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  19

Explanation of Solution

Calculate HDI:

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 13.SE, Problem 47AP , additional homework tip  20

The HDI calculation led to confirm about the presence of a double bond or a ring.

Interpret the given 13CNMR spectrum:

Broadband - decoupled spectrum:

The spectrum shows four signals whereas the given molecular formula also has six carbon atoms. Thus all the six carbons have chemically different electronic environments showing signals.

i) The four signals in the region of 0-50ppm indicate the sp3 hybridized carbon atoms which can be methyl / methylene or Methine groups.

DEPT -135 (gives signals of CH2, C groups):

ii) The two negative signals indicate the presence of four methylene groups; only methylene groups appear negative in the spectrum.

iii) So far the group of fragments obtained is

C=O, -C-, four -ch2

From the fragments (CH2)5 + C = 10 protons) ten protons are obtained whereas the total number of protons from the molecular formula is also ten.

Conclusion

The structure of a given molecular formula C6H10O is predicted using 13CNMR spectra.

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Chapter 13 Solutions

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card

Ch. 13.6 - The integrated 1H NMR spectrum of a compound of...Ch. 13.7 - Identify the indicated sets of protons as...Ch. 13.7 - How many kinds of electronically nonequivalent...Ch. 13.7 - How many absorptions would you expect (S)-malate,...Ch. 13.8 - 3-Bromo-1-phenyl-1-propene shows a complex NMR...Ch. 13.9 - How could you use 1H NMR to determine the...Ch. 13.11 - Prob. 17PCh. 13.11 - Propose structures for compounds that fit the...Ch. 13.11 - Prob. 19PCh. 13.12 - Prob. 20PCh. 13.12 - Prob. 21PCh. 13.12 - Prob. 22PCh. 13.13 - Prob. 23PCh. 13.SE - Into how many peaks would you expect the 1H NMR...Ch. 13.SE - How many absorptions would you expect the...Ch. 13.SE - Sketch what you might expect the 1H and 13C NMR...Ch. 13.SE - How many electronically nonequivalent kinds of...Ch. 13.SE - Identify the indicated protons in the following...Ch. 13.SE - Prob. 29APCh. 13.SE - Prob. 30APCh. 13.SE - When measured on a spectrometer operating at 200...Ch. 13.SE - Prob. 32APCh. 13.SE - Prob. 33APCh. 13.SE - How many types of nonequivalent protons are...Ch. 13.SE - The following compounds all show a single line in...Ch. 13.SE - Prob. 36APCh. 13.SE - Propose structures for compounds with the...Ch. 13.SE - Predict the splitting pattern for each kind of...Ch. 13.SE - Predict the splitting pattern for each kind of...Ch. 13.SE - Identify the indicated sets of protons as...Ch. 13.SE - Identify the indicated sets of protons as...Ch. 13.SE - The acid-catalyzed dehydration of...Ch. 13.SE - How could you use 1H NMR to distinguish between...Ch. 13.SE - Propose structures for compounds that fit the...Ch. 13.SE - Propose structures for the two compounds whose 1H...Ch. 13.SE - Prob. 46APCh. 13.SE - How many absorptions would you expect to observe...Ch. 13.SE - Prob. 48APCh. 13.SE - How could you use 1H and 13C NMR to help...Ch. 13.SE - How could you use 1H NMR, 13C NMR, and IR...Ch. 13.SE - Assign as many resonances as you can to specific...Ch. 13.SE - Assume that you have a compound with the formula...Ch. 13.SE - The compound whose 1H NMR spectrum is shown has...Ch. 13.SE - The compound whose 1H NMR spectrum is shown has...Ch. 13.SE - Propose structures for compounds that fit the...Ch. 13.SE - Long-range coupling between protons more than two...Ch. 13.SE - The 1H and 13C NMR spectra of compound A, C8H9Br,...Ch. 13.SE - Propose structures for the three compounds whose...Ch. 13.SE - The mass spectrum and 13C NMR spectrum of a...Ch. 13.SE - Compound A, a hydrocarbon with M+=96 in its mass...Ch. 13.SE - Propose a structure for compound C, which has...Ch. 13.SE - Prob. 62GPCh. 13.SE - Propose a structure for compound E, C7H12O2, which...Ch. 13.SE - Compound F, a hydrocarbon with M+=96 in its mass...Ch. 13.SE - 3-Methyl-2-butanol has five signals in its 13C NMR...Ch. 13.SE - A 13C NMR spectrum of commercially available...Ch. 13.SE - Carboxylic acids (RCO2H) react with alcohols (ROH)...Ch. 13.SE - Prob. 68GPCh. 13.SE - The proton NMR spectrum is shown for a compound...Ch. 13.SE - The proton NMR spectrum of a compound with the...Ch. 13.SE - The proton NMR spectrum is shown for a compound...
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