Interpretation:
Consider a 100 mL of solution with 13.5% of NaCl by mass with a density of 1.12 . What among solute and solvent and how much we need to add to given solution to make the boiling point of solution104.4°C (take i=1.8).
Concept introduction:
a) The percentage by mass means that that amount of solute is dissolved in 100 g of solution.
b) The elevation in boiling point is a colligative property and is related to molality as
∆Tb = i.Kb.m
where,
∆Tb is change in boiling temperature
i is Van’t Hoff factor
Kb is molal boiling-point elevation constant
m is molality
Given:
The density of solution is 1.12
Volume of solution is 100 mL
Mass percentage of NaCl is 13.5 %
Van’t Hoff factor = i = 1.8
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Chapter 14 Solutions
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