Concept explainers
(a)
Interpretation:
The given molecule is to be identified as
Concept introduction:
Answer to Problem 14.11P
The given molecule is nonaromatic.
Explanation of Solution
The structure of the given molecule is
In the given compound, six carbon atoms are
Because of the
Therefore, this molecule is nonaromatic.
The presence of four
(b)
Interpretation:
The given molecule is to be identified as aromatic, antiaromatic, or nonaromatic.
Concept introduction:
Huckel’s rule for aromaticity states that if a species is planar and possesses a
Answer to Problem 14.11P
The given molecule is aromatic.
Explanation of Solution
Structure of the given molecule is
In this molecule, six carbon atoms are
Therefore, the given molecule is aromatic.
The presence of six
(c)
Interpretation:
The given molecule is to be identified as aromatic, antiaromatic, or nonaromatic.
Concept introduction:
Huckel’s rule for aromaticity states that if a species is planar and possesses a
Answer to Problem 14.11P
The given molecule is nonaromatic.
Explanation of Solution
Structure of the given molecule is
In the given compound, four carbon atoms are
Therefore, the given molecule is nonaromatic.
The presence of one
(d)
Interpretation:
The given molecule is to be identified as aromatic, antiaromatic, or nonaromatic.
Concept introduction:
Huckel’s rule for aromaticity states that if a species is planar and possesses a
Answer to Problem 14.11P
The given molecule is nonaromatic.
Explanation of Solution
Structure of the given molecule is
In the given compound, six carbon atoms are
Therefore, the given molecule is nonaromatic.
The presence of one
(e)
Interpretation:
The given molecule is to be identified as aromatic, antiaromatic, or nonaromatic.
Concept introduction:
Huckel’s rule for aromaticity states that if a species is planar and possesses a
Answer to Problem 14.11P
The given molecule is nonaromatic.
Explanation of Solution
Structure of the given molecule is
In the given compound, two carbon atoms are
Therefore, the given molecule is nonaromatic.
The presence of two
(f)
Interpretation:
The given molecule is to be identified as aromatic, antiaromatic, or nonaromatic.
Concept introduction:
Huckel’s rule for aromaticity states that if a species is planar and possesses a
Answer to Problem 14.11P
The given molecule is nonaromatic.
Explanation of Solution
Structure of the given molecule is
The molecule is not a cyclic system.
Therefore, the given molecule is nonaromatic.
Non-cyclic form of the given molecule indicates that the molecule is nonaromatic.
(g)
Interpretation:
The given molecule is to be identified as aromatic, antiaromatic, or nonaromatic.
Concept introduction:
Huckel’s rule for aromaticity states that if a species is planar and possesses a
Answer to Problem 14.11P
The given molecule is aromatic.
Explanation of Solution
The structure of the given molecule is
The molecule has a cyclic part with alternating single and double bonds. This means all ring atoms are
Therefore, this molecule is aromatic.
The presence of six
Want to see more full solutions like this?
Chapter 14 Solutions
EBK GET READY FOR ORGANIC CHEMISTRY
- Below are two sets of resonance structures. Where applicable provide the missing curved arrow notation, lone pair electrons, and nonzero formal charge. Do not delete or add any bonds or atoms.arrow_forwardGive a clear handwritten answer with explanationarrow_forwardPlease choose correct answer in photo.arrow_forward
- Solve correctly please. With explanation.arrow_forwardplease explain and answerarrow_forwardIn HF , neither H nor F holds a full formal charge of +1 or 1 . Organic chemists represent apartial charge using the Greek letter delta () . On the electron density map of the molecule HF above, add a + to one atom and a to the other to indicate which way the bond is polarized.arrow_forward
- Give correct detailed Solution with explanation needed...don't give Handwritten answer..explain also how to draw resonance structure.arrow_forwardIs this an aromatic, antiaromatic, or non aromatic molecule?arrow_forwardDraw the curved arrows to show the resonance structure for the following molecules. ( there are 3 molecules )arrow_forward
- Draw the resonance structures for the following compound and circle the one that contributes most to the resonance hybrid. Why?arrow_forwardShown below is a heterocylic aromatic compound. How many more aromatic aromatic res forms exist? [HINT: Copy the structure, use one or more curved arrow and assess all possible structures) H N H3Carrow_forward3) Draw all resonance structures of the following compound. Order the structures by increasing stability.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning