General Chemistry
General Chemistry
7th Edition
ISBN: 9780073402758
Author: Chang, Raymond/ Goldsby
Publisher: McGraw-Hill College
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Chapter 14, Problem 14.17QP

(a)

Interpretation Introduction

Interpretation:

The overall order for the reaction to which the following rate law applies has to be determined.

rate=k[NO2]2

Concept introduction:

Rate equation for the general reaction A+BProduct is,

Rate=krateconstat[A][B]

The rate of the reaction is proportinal to the concentration of A to the power of x, is [A]x

The rate of the reaction is proportional to the concentration of B to the power of y is [B]y

Then the rate equation becomes,

Rate=k[A]x[B]y

Order of this reaction is the sum of the powers to which all reactant concentrations appearing in the rate law are  raised.

Orderx+y

Rate law: It is an equation that related to the rate of reaction to the concentrations or pressures of substrates (reactants).  It is also said to be as rate equation.

(a)

Expert Solution
Check Mark

Answer to Problem 14.17QP

rate = k[NO2]2 The order of reaction is 2

Explanation of Solution

Given,

rate = k[NO2]2

Order of this reaction is the sum of the powers to which all reactant concentrations appearing in the rate law are raised.

Orderx+y

Therefore the order for the reaction with the above rate equation is 2

(b)

Interpretation Introduction

Interpretation:

The overall order for the reaction to which the following rate law applies has to be determined.

rate =k 

Concept introduction:

Rate equation for the general reaction A+BProduct is,

Rate=krateconstat[A][B]

The rate of the reaction is proportinal to the concentration of A to the power of x, is [A]x

The rate of the reaction is proportional to the concentration of B to the power of y is [B]y

Then the rate equation becomes,

Rate=k[A]x[B]y

Order of this reaction is the sum of the powers to which all reactant concentrations appearing in the rate law are  raised.

Orderx+y

Rate law: It is an equation that related to the rate of reaction to the concentrations or pressures of substrates (reactants).  It is also said to be as rate equation.

(b)

Expert Solution
Check Mark

Answer to Problem 14.17QP

rate =k  , The order of reaction is 0

Explanation of Solution

Given,

rate =k 

Order of this reaction is the sum of the powers to which all reactant concentrations appearing in the rate law are raised.

Therefore the order for the reaction with the above rate equation is 0

(c)

Interpretation Introduction

Interpretation:

The overall order for the reaction to which the following rate law applies has to be determined.

rate = k[H2]

Concept introduction:

Rate equation for the general reaction A+BProduct is,

Rate=krateconstat[A][B]

The rate of the reaction is proportinal to the concentration of A to the power of x, is [A]x

The rate of the reaction is proportional to the concentration of B to the power of y is [B]y

Then the rate equation becomes,

Rate=k[A]x[B]y

Order of this reaction is the sum of the powers to which all reactant concentrations appearing in the rate law are  raised.

Orderx+y

Rate law: It is an equation that related to the rate of reaction to the concentrations or pressures of substrates (reactants).  It is also said to be as rate equation.

(c)

Expert Solution
Check Mark

Answer to Problem 14.17QP

rate = k[H2]  The order of reaction is 1

Explanation of Solution

Given,

rate = k[H2]

Order of this reaction is the sum of the powers to which all reactant concentrations appearing in the rate law are  raised.

Orderx+y

Therefore the order for the reaction with the above rate equation is 1

(d)

Interpretation Introduction

Interpretation:

The overall order for the reaction to which the following rate law applies has to be determined.

rate = k[NO]2[O2]

Concept introduction:

Rate equation for the general reaction A+BProduct is,

Rate=krateconstat[A][B]

The rate of the reaction is proportinal to the concentration of A to the power of x, is [A]x

The rate of the reaction is proportional to the concentration of B to the power of y is [B]y

Then the rate equation becomes,

Rate=k[A]x[B]y

Order of this reaction is the sum of the powers to which all reactant concentrations appearing in the rate law are  raised.

Orderx+y

Rate law: It is an equation that related to the rate of reaction to the concentrations or pressures of substrates (reactants).  It is also said to be as rate equation.

(d)

Expert Solution
Check Mark

Answer to Problem 14.17QP

The given reaction follows is third order kinetics.

Explanation of Solution

Given,

rate = k[NO]2[O2]

Order of this reaction is the sum of the powers to which all reactant concentrations appearing in the rate law are  raised.

Orderx+y

Here,

Order=2+1=3

Therefore the given reaction follows is third order kinetics.

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Chapter 14 Solutions

General Chemistry

Ch. 14.4 - Practice Exercise The first-order rate constant...Ch. 14.4 - Review of Concepts (a) What can you deduce about...Ch. 14.5 - Practice Exercise The reaction between NO2 and CO...Ch. 14.5 - Prob. 1RCCh. 14.6 - Prob. 1RCCh. 14 - Prob. 14.1QPCh. 14 - 15.2 Explain the difference between physical...Ch. 14 - Prob. 14.3QPCh. 14 - Prob. 14.4QPCh. 14 - Prob. 14.5QPCh. 14 - 14.6 Consider the reaction Suppose that at a...Ch. 14 - Prob. 14.7QPCh. 14 - 14.8 What are the units for the rate constants of...Ch. 14 - Prob. 14.9QPCh. 14 - Prob. 14.10QPCh. 14 - Prob. 14.11QPCh. 14 - Prob. 14.13QPCh. 14 - Prob. 14.14QPCh. 14 - Prob. 14.15QPCh. 14 - Prob. 14.16QPCh. 14 - Prob. 14.17QPCh. 14 - Prob. 14.18QPCh. 14 - Prob. 14.19QPCh. 14 - Prob. 14.20QPCh. 14 - 14.21 What is the half-life of a compound if 75...Ch. 14 - 14.22 The thermal decomposition of phosphine (PH3)...Ch. 14 - Prob. 14.23QPCh. 14 - Prob. 14.24QPCh. 14 - 14.25 Consider the first-order reaction A → B...Ch. 14 - Prob. 14.26QPCh. 14 - 14.27 Define activation energy. What role does...Ch. 14 - Prob. 14.28QPCh. 14 - Prob. 14.29QPCh. 14 - 14.30 As we know, methane burns readily in oxygen...Ch. 14 - Prob. 14.31QPCh. 14 - Prob. 14.32QPCh. 14 - Prob. 14.33QPCh. 14 - Prob. 14.34QPCh. 14 - Prob. 14.35QPCh. 14 - Prob. 14.36QPCh. 14 - Prob. 14.37QPCh. 14 - 14.38 The rate at which tree crickets chirp is 2.0...Ch. 14 - 14.39 The diagram here describes the initial state...Ch. 14 - Prob. 14.40QPCh. 14 - Prob. 14.41QPCh. 14 - Prob. 14.42QPCh. 14 - 14.43 Explain why termolecular reactions are...Ch. 14 - 14.44 What is the rate-determining step of a...Ch. 14 - Prob. 14.45QPCh. 14 - Prob. 14.46QPCh. 14 - Prob. 14.47QPCh. 14 - Prob. 14.48QPCh. 14 - Prob. 14.49QPCh. 14 - Prob. 14.50QPCh. 14 - Prob. 14.51QPCh. 14 - Prob. 14.52QPCh. 14 - Prob. 14.53QPCh. 14 - Prob. 14.54QPCh. 14 - Prob. 14.55QPCh. 14 - Prob. 14.56QPCh. 14 - Prob. 14.57QPCh. 14 - Prob. 14.58QPCh. 14 - Prob. 14.59QPCh. 14 - Prob. 14.60QPCh. 14 - Prob. 14.61QPCh. 14 - Prob. 14.62QPCh. 14 - Prob. 14.63QPCh. 14 - Prob. 14.64QPCh. 14 - Prob. 14.65QPCh. 14 - 14.66 The decomposition of N2O to N2 and O2 is a...Ch. 14 - Prob. 14.67QPCh. 14 - Prob. 14.68QPCh. 14 - 14.69 Consider the zero-order reaction a → B....Ch. 14 - Prob. 14.70QPCh. 14 - Prob. 14.72QPCh. 14 - Prob. 14.73QPCh. 14 - Prob. 14.74QPCh. 14 - Prob. 14.75QPCh. 14 - Prob. 14.76QPCh. 14 - Prob. 14.77QPCh. 14 - Prob. 14.78QPCh. 14 - Prob. 14.79QPCh. 14 - Prob. 14.80QPCh. 14 - Prob. 14.81QPCh. 14 - Prob. 14.82QPCh. 14 - 14.83 When a mixture of methane and bromine is...Ch. 14 - 14.84 Consider this elementary step: (a)...Ch. 14 - Prob. 14.85QPCh. 14 - Prob. 14.86QPCh. 14 - 14.87 In recent years ozone in the stratosphere...Ch. 14 - Prob. 14.88QPCh. 14 - Prob. 14.90QPCh. 14 - Prob. 14.91QPCh. 14 - Prob. 14.92QPCh. 14 - Prob. 14.93QPCh. 14 - Prob. 14.94QPCh. 14 - Prob. 14.95QPCh. 14 - Prob. 14.96QPCh. 14 - Prob. 14.97QPCh. 14 - Prob. 14.98QPCh. 14 - Prob. 14.100QPCh. 14 - Prob. 14.101QPCh. 14 - 14.102 Consider the potential energy profiles...Ch. 14 - Prob. 14.103QPCh. 14 - Prob. 14.104QPCh. 14 - 14.105 The activation energy for the...Ch. 14 - Prob. 14.106QPCh. 14 - Prob. 14.107SPCh. 14 - Prob. 14.108SPCh. 14 - Prob. 14.109SPCh. 14 - Prob. 14.110SPCh. 14 - Prob. 14.111SPCh. 14 - Prob. 14.112SPCh. 14 - Prob. 14.113SPCh. 14 - Prob. 14.114SPCh. 14 - Prob. 14.115SPCh. 14 - 14.116 To prevent brain damage, a drastic medical...Ch. 14 - Prob. 14.117SPCh. 14 - Prob. 14.118SP
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