EBK CHEMISTRY: THE MOLECULAR NATURE OF
EBK CHEMISTRY: THE MOLECULAR NATURE OF
8th Edition
ISBN: 9781259915505
Author: SILBERBERG
Publisher: MCGRAW HILL BOOK COMPANY
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Chapter 14, Problem 14.93P

(a)

Interpretation Introduction

Interpretation:

The complete and balanced reaction of Rb(s) with Br2(l) has to be written.

Concept Introduction:

Balanced equation:

In a chemical equation, the number of atoms or elements that present in both reactant and product sides are equal means this equation is known as balanced equation.

(a)

Expert Solution
Check Mark

Explanation of Solution

Reaction of Rb(s) with Br2(l) gives RbBr(s), equation for this reaction is,

  Rb(s) + Br2(l)RbBr(s)

Add 2 as a coefficient in front of Rb(s) and RbBr(s) to get the balanced equation,

  2Rb(s)+ Br2(l)2RbBr(s)

(b)

Interpretation Introduction

Interpretation:

The complete and balanced reaction of I2(s) with H2O(l) has to be written.

Concept Introduction:

Balanced equation:

In a chemical equation, the number of atoms or elements that present in both reactant and product sides are equal means this equation is known as balanced equation.

(b)

Expert Solution
Check Mark

Explanation of Solution

Reaction of I2(s) with H2O(l) gives HI(aq) and HIO(aq), the balanced equation for this reaction is,

  I2(s)+ H2O(l)HI(aq)+ HIO(aq)

(c)

Interpretation Introduction

Interpretation:

The complete and balanced reaction of Br2(l) with I(aq) has to be written.

Concept Introduction:

Balanced equation:

In a chemical equation, the number of atoms or elements that present in both reactant and product sides are equal means this equation is known as balanced equation.

(c)

Expert Solution
Check Mark

Explanation of Solution

Reaction of Br2(l) with I(aq) gives I2(s) and Br(aq)-, the balanced equation for this reaction is,

  Br2(l) + I(aq)I2(s) + Br(aq)-

Add 2 as a coefficient in front of I(aq) and Br(aq)- to get the balanced equation,

  Br2(l) + 2I(aq)I2(s) + 2Br(aq)-

(d)

Interpretation Introduction

Interpretation:

The complete and balanced reaction of CaF2(s)withH2SO4(l) has to be written.

Concept Introduction:

Balanced equation:

In a chemical equation, the number of atoms or elements that present in both reactant and product sides are equal means this equation is known as balanced equation.

(d)

Expert Solution
Check Mark

Explanation of Solution

Reaction of CaF2(s)withH2SO4(l) gives CaSO4(s) and HF(g), the balanced equation for this reaction is,

  CaF2(s)+H2SO4(l)CaSO4(s)+HF(g)

Add 2 as a coefficient in front of 2HF(g) to get the balanced equation,

  CaF2(s)+H2SO4(l)CaSO4(s)+2HF(g)

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Chapter 14 Solutions

EBK CHEMISTRY: THE MOLECULAR NATURE OF

Ch. 14 - Prob. 14.11PCh. 14 - Prob. 14.12PCh. 14 - Prob. 14.13PCh. 14 - Prob. 14.14PCh. 14 - Prob. 14.15PCh. 14 - Prob. 14.16PCh. 14 - Prob. 14.17PCh. 14 - Prob. 14.18PCh. 14 - Prob. 14.19PCh. 14 - Prob. 14.20PCh. 14 - Prob. 14.21PCh. 14 - Prob. 14.22PCh. 14 - Prob. 14.23PCh. 14 - Prob. 14.24PCh. 14 - Prob. 14.25PCh. 14 - Prob. 14.26PCh. 14 - Prob. 14.27PCh. 14 - Prob. 14.28PCh. 14 - Prob. 14.29PCh. 14 - Prob. 14.30PCh. 14 - Prob. 14.31PCh. 14 - Prob. 14.32PCh. 14 - Prob. 14.33PCh. 14 - Prob. 14.34PCh. 14 - Prob. 14.35PCh. 14 - Prob. 14.36PCh. 14 - Prob. 14.37PCh. 14 - Prob. 14.38PCh. 14 - Prob. 14.39PCh. 14 - Prob. 14.40PCh. 14 - Prob. 14.41PCh. 14 - Prob. 14.42PCh. 14 - Prob. 14.43PCh. 14 - Prob. 14.44PCh. 14 - Prob. 14.45PCh. 14 - Prob. 14.46PCh. 14 - Give explanations for the large drops in melting...Ch. 14 - Prob. 14.48PCh. 14 - Prob. 14.49PCh. 14 - Prob. 14.50PCh. 14 - Prob. 14.51PCh. 14 - Prob. 14.52PCh. 14 - Prob. 14.53PCh. 14 - Prob. 14.54PCh. 14 - Prob. 14.55PCh. 14 - Prob. 14.56PCh. 14 - Prob. 14.57PCh. 14 - Prob. 14.58PCh. 14 - Prob. 14.59PCh. 14 - Prob. 14.60PCh. 14 - Prob. 14.61PCh. 14 - Prob. 14.62PCh. 14 - Prob. 14.63PCh. 14 - Prob. 14.64PCh. 14 - Prob. 14.65PCh. 14 - Prob. 14.66PCh. 14 - Prob. 14.67PCh. 14 - Prob. 14.68PCh. 14 - Prob. 14.69PCh. 14 - Prob. 14.70PCh. 14 - Prob. 14.71PCh. 14 - Prob. 14.72PCh. 14 - Prob. 14.73PCh. 14 - Prob. 14.74PCh. 14 - Prob. 14.75PCh. 14 - Prob. 14.76PCh. 14 - Prob. 14.77PCh. 14 - Prob. 14.78PCh. 14 - Prob. 14.79PCh. 14 - Prob. 14.80PCh. 14 - Prob. 14.81PCh. 14 - Prob. 14.82PCh. 14 - Prob. 14.83PCh. 14 - Prob. 14.84PCh. 14 - Prob. 14.85PCh. 14 - Prob. 14.86PCh. 14 - Prob. 14.87PCh. 14 - Prob. 14.88PCh. 14 - Prob. 14.89PCh. 14 - Prob. 14.90PCh. 14 - Prob. 14.91PCh. 14 - Prob. 14.92PCh. 14 - Prob. 14.93PCh. 14 - Prob. 14.94PCh. 14 - Prob. 14.95PCh. 14 - Prob. 14.96PCh. 14 - Prob. 14.97PCh. 14 - Prob. 14.98PCh. 14 - Prob. 14.99PCh. 14 - Prob. 14.100PCh. 14 - Prob. 14.101PCh. 14 - Prob. 14.102PCh. 14 - Prob. 14.103PCh. 14 - Prob. 14.104PCh. 14 - Xenon tetrafluoride reacts with antimony...Ch. 14 - Prob. 14.106PCh. 14 - Prob. 14.107PCh. 14 - Prob. 14.108PCh. 14 - Prob. 14.109PCh. 14 - Prob. 14.110PCh. 14 - Prob. 14.111PCh. 14 - Prob. 14.112PCh. 14 - Prob. 14.113PCh. 14 - Prob. 14.114PCh. 14 - Prob. 14.115PCh. 14 - Prob. 14.116PCh. 14 - Prob. 14.117PCh. 14 - Prob. 14.118PCh. 14 - Prob. 14.119PCh. 14 - Prob. 14.120PCh. 14 - Prob. 14.121PCh. 14 - Prob. 14.122PCh. 14 - Prob. 14.123PCh. 14 - Prob. 14.124PCh. 14 - Prob. 14.125PCh. 14 - Prob. 14.126PCh. 14 - Prob. 14.127PCh. 14 - Prob. 14.128PCh. 14 - Prob. 14.129PCh. 14 - Prob. 14.130PCh. 14 - Prob. 14.131PCh. 14 - Prob. 14.132PCh. 14 - Prob. 14.133PCh. 14 - Prob. 14.134PCh. 14 - Hydrogen peroxide can act as either an oxidizing...
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NEET Chemistry | Group 14 Carbon Family | Theory & Problem Solving | In English | Misostudy; Author: Misostudy;https://www.youtube.com/watch?v=enOGIrcHh54;License: Standard YouTube License, CC-BY