STATISTICAL TECHNIQUES FOR BUSINESS AND
STATISTICAL TECHNIQUES FOR BUSINESS AND
17th Edition
ISBN: 9781307261158
Author: Lind
Publisher: MCG/CREATE
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Question
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Chapter 14, Problem 25CE

a.

To determine

Find the regression equation.

a.

Expert Solution
Check Mark

Answer to Problem 25CE

The regression equation is y^=652+13.42x16.71x2+205.6x333.5x4_.

Explanation of Solution

Calculation:

Multiple linear regression model:

A multiple linear regression model is given as y^=a+b1x1+b2x2+b3x3+...+bkxk where y is the response or dependent variable, and x1,x2,...,xk are the k quantitative independent variables where k is a positive integer.

Here, a is the intercept term of the regression model, that is, the value of predicted value of y when X’s are 0 and bi’s are the slopes, that is, the amount of change of the predicted value of y for one unit increase in xi when all other independent variables are constant.

In the given part the predicted dependent variable y is the monthly salary and the length of service (x1), the age (x2), the gender (x3) and the job (x4) are the independent variables.

Step by step procedure to obtain the regression equation using MINITAB software:

  • Choose Stat > Regression > Regression > Fit Regression Model.
  • Under Responses, enter the column of Salary.
  • Under Continuous predictors, enter the columns of Service, Age, Gender and Job.
  • Click OK.

Output using MINITAB software is given below:

STATISTICAL TECHNIQUES FOR BUSINESS AND, Chapter 14, Problem 25CE , additional homework tip  1

Thus, the regression equation is y^=652+13.42x16.71x2+205.6x333.5x4_.

b.

To determine

Find the value of R2.

Also explain about the R2.

b.

Expert Solution
Check Mark

Answer to Problem 25CE

The value of R2 is 43.27%.

Explanation of Solution

According to output in Part (a), the value of R2 is 43.27%.

Hence, it can be said that only 43.27% variability in the monthly salary is explained by the length of service, age, gender and the job designation of the employees, using the regression equation.

c.

To determine

Perform a global test to find whether any of the independent variables are different from 0.

c.

Expert Solution
Check Mark

Answer to Problem 25CE

There is enough evidence that any of the independent variables are different from 0 at 0.05 significance level.

Explanation of Solution

Calculation:

Consider that y is dependent variable and xi's are the independent variables where βi's are the corresponding population regression coefficient for all i=1,2,3,4.

State the hypotheses:

Null hypothesis:

H0:β1=β2=β3=β4=0.

That is, the model is not significant.

Alternative hypothesis:

H1:At least one βi is not equal to 0.

That is, the model is significant.

In case of global test the F test statistic is defined as,

F=SSRkSSEnk1, where SSR, SSE, n and k are the regression sum of square, error sum of square, sample size and the number of independent variables.

According to the output from Part (a) the value of F statistic is 4.77 with numerator degrees of freedom 4 and denominator degrees of freedom 25.

Consider that, the level of significance is α=0.05.

Decision rule:

  • If p-valueα, then reject the null hypothesis.
  • Otherwise failed to reject the null hypothesis.

Conclusion:

Here, p-value corresponding to the global test is 0.

Hence, p-value(=0)<α(=0.05).

That is, the p-value is less than the level of significance.

Therefore, reject the null hypothesis.

Hence, it can be concluded that any of the independent variables are different from 0 at 0.05 significance level.

d.

To determine

Perform an individual test to determine whether any of the independent variables can be dropped.

d.

Expert Solution
Check Mark

Answer to Problem 25CE

There is no significant relationship between the dependent variable “Salary” and the independent variables “Age” and “Job”, thus it is better to omit these two variables.

Explanation of Solution

Calculation:

For independent variable x1:

Consider that β1 is the population regression coefficient of independent variable x1.

State the hypotheses:

Null hypothesis:

H0:β1=0.

That is, there is no significant relationship between y and x1.

Alternative hypothesis:

H1:β10.

That is, there is significant relationship between y and x1.

In case of individual regression coefficient test the t test statistic is defined as,

t=bisbi, where bi and sbi are the ith regression coefficient and the standard deviation of the ith regression coefficient.

According to the output in Part (a) the t statistic value corresponding to x1 is 2.61 with 25 degrees of freedom.

Conclusion:

Here, p-value corresponding to the “Service”(x1) is 0.015.

Hence, p-value(=0)<α(=0.05).

That is, the p-value is less than the level of significance.

Therefore, reject the null hypothesis.

Hence, it can be concluded that there is significant relationship between y and x1.

For independent variable x2:

Consider that β2 is the population regression coefficient of independent variable x2.

State the hypotheses:

Null hypothesis:

H0:β2=0.

That is, there is no significant relationship between y and x2.

Alternative hypothesis:

H1:β20.

That is, there is significant relationship between y and x2.

According to the output in Part (a) the value of t test statistic corresponding to x2 is –1.06 with 25 degrees of freedom.

Conclusion:

Here, p-value corresponding to the “Age”(x2) is 0.301.

Hence, p-value(=0.301)>α(=0.05).

That is, the p-value is greater than the level of significance.

Therefore, fail to reject the null hypothesis.

Hence, it can be concluded that there is no significant relationship between y and x2.

For independent variable x3:

Consider that β3 is the population regression coefficient of independent variable x3.

State the hypotheses:

Null hypothesis:

H0:β3=0.

That is, there is no significant relationship between y and x3.

Alternative hypothesis:

H1:β30.

That is, there is significant relationship between y and x3.

According to the output in Part (d) the value of t test statistic corresponding to x3 is 2.28 with 25 degrees of freedom.

Conclusion:

Here, p-value corresponding to the “Gender”(x3) is 0.032.

Hence, p-value(=0.032)<α(=0.05).

That is, the p-value is less than the level of significance.

Therefore, reject the null hypothesis.

Hence, it can be concluded that there is significant relationship between y and x3.

For independent variable x4:

Consider that β4 is the population regression coefficient of independent variable x4.

State the hypotheses:

Null hypothesis:

H0:β4=0.

That is, there is no significant relationship between y and x4.

Alternative hypothesis:

H1:β40.

That is, there is significant relationship between y and x4.

According to the output in Part (a) the value of t test statistic corresponding to x4 is –0.37 with 25 degrees of freedom.

Conclusion:

Here, p-value corresponding to the “Job”(x4) is 0.712.

Hence, p-value(=0.712)>α(=0.05).

That is, the p-value is greater than the level of significance.

Therefore, fail to reject the null hypothesis.

Hence, it can be concluded that there is no significant relationship between y and x4.

As there is no significant relationship between the dependent variable “Salary” and the independent variables “Age” and “Job”, thus it is better to omit these two variables and perform the regression analysis only with the independent variables “Service” and “Gender”.

e.

To determine

Find the regression equation using the significant independent variables.

Find the amount of money does a man earn per month than a woman.

Explain whether there is any difference

e.

Expert Solution
Check Mark

Answer to Problem 25CE

The regression equation is y^=784+9.02x1+224.4x2_.

Explanation of Solution

Calculation:

Dummy variable:

A dichotomous variable is defined as a dummy variable, where one outcome is defined as 1 another as 0.

In the Part the predicted dependent variable y is the monthly salary and the length of service (x1), and the gender (x2) are the independent variables.

The independent random variable x2 is defined as dummy variable.

Hence,

x2={1,male0,female.

Step by step procedure to obtain the regression equation using MINITAB software:

  • Choose Stat > Regression > Regression > Fit Regression Model.
  • Under Responses, enter the column of Salary.
  • Under Continuous predictors, enter the columns of Service, and Gender.
  • Click OK.

Output using MINITAB software is given below:

STATISTICAL TECHNIQUES FOR BUSINESS AND, Chapter 14, Problem 25CE , additional homework tip  2

Thus, the regression equation is y^=784+9.02x1+224.4x2_.

Here, the coefficient of x2 is 224.4. For x2=1(Male) the slope coefficient value is 224.4 and for x2=0(Female) the slope coefficient value is 0. Hence, it can be said that a man earns $224.4 more than a woman.

As there is no significant relationship between the monthly salary and the designation of the employees, hence whether the employee has a management or engineering position does not make any difference.

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Chapter 14 Solutions

STATISTICAL TECHNIQUES FOR BUSINESS AND

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