That the area swept out by the radial vector at time tis , A ( t ) = 1 2 ∥ r 0 × v 0 ∥ t and thus Kepler’s Second Law continues to hold (the rate is constant) if a planet has zero mass (m = 0), then Newton’s laws of motion reduce to r ' ' ( t ) = 0 and the orbit is a straight line.

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Answer 1

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Chapter 14, Problem 40CRE

To determine

To explain:That the area swept out by the radial vector at time tis , $A (t) = \frac{1}{2} ∥ r_{0} \times v_{0} ∥ t$ and thus Kepler’s Second Law continues to hold (the rate is constant) if a planet has zero mass (m = 0), then Newton’s laws of motion reduce to $r'' (t) = 0$ and the orbit is a straight line.

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Answer 2

Question

Chapter 14, Problem 40CRE

To determine

To explain:That the area swept out by the radial vector at time tis , $A (t) = \frac{1}{2} ∥ r_{0} \times v_{0} ∥ t$ and thus Kepler’s Second Law continues to hold (the rate is constant) if a planet has zero mass (m = 0), then Newton’s laws of motion reduce to $r'' (t) = 0$ and the orbit is a straight line.

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Answer 3

Question

Chapter 14, Problem 40CRE

To determine

To explain:That the area swept out by the radial vector at time tis , $A (t) = \frac{1}{2} ∥ r_{0} \times v_{0} ∥ t$ and thus Kepler’s Second Law continues to hold (the rate is constant) if a planet has zero mass (m = 0), then Newton’s laws of motion reduce to $r'' (t) = 0$ and the orbit is a straight line.

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Answer 4

Question

Chapter 14, Problem 40CRE

To determine

To explain:That the area swept out by the radial vector at time tis , $A (t) = \frac{1}{2} ∥ r_{0} \times v_{0} ∥ t$ and thus Kepler’s Second Law continues to hold (the rate is constant) if a planet has zero mass (m = 0), then Newton’s laws of motion reduce to $r'' (t) = 0$ and the orbit is a straight line.

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Answer 5

Chapter 14, Problem 40CRE

To determine

To explain:That the area swept out by the radial vector at time tis , $A (t) = \frac{1}{2} ∥ r_{0} \times v_{0} ∥ t$ and thus Kepler’s Second Law continues to hold (the rate is constant) if a planet has zero mass (m = 0), then Newton’s laws of motion reduce to $r'' (t) = 0$ and the orbit is a straight line.

Answer 6

Chapter 14, Problem 40CRE

To determine

To explain:That the area swept out by the radial vector at time tis , $A (t) = \frac{1}{2} ∥ r_{0} \times v_{0} ∥ t$ and thus Kepler’s Second Law continues to hold (the rate is constant) if a planet has zero mass (m = 0), then Newton’s laws of motion reduce to $r'' (t) = 0$ and the orbit is a straight line.

Answer 7

Chapter 14, Problem 40CRE

To determine

To explain:That the area swept out by the radial vector at time tis , $A (t) = \frac{1}{2} ∥ r_{0} \times v_{0} ∥ t$ and thus Kepler’s Second Law continues to hold (the rate is constant) if a planet has zero mass (m = 0), then Newton’s laws of motion reduce to $r'' (t) = 0$ and the orbit is a straight line.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 14.1 - Prob. 1PQ Ch. 14.1 - Prob. 2PQ Ch. 14.1 - Prob. 3PQ Ch. 14.1 - Prob. 4PQ Ch. 14.1 - Prob. 5PQ Ch. 14.1 - Prob. 6PQ Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E

That the area swept out by the radial vector at time tis , A ( t ) = 1 2 ∥ r 0 × v 0 ∥ t and thus Kepler’s Second Law continues to hold (the rate is constant) if a planet has zero mass (m = 0), then Newton’s laws of motion reduce to r ' ' ( t ) = 0 and the orbit is a straight line.

Solution Summary: The author explains that the area swept out by the radial vector at time tis explained.

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Chapter 14 Solutions

That the area swept out by the radial vector at time tis , A ( t ) = 1 2 ∥ r 0 × v 0 ∥ t and thus Kepler’s Second Law continues to hold (the rate is constant) if a planet has zero mass (m = 0), then Newton’s laws of motion reduce to r ' ' ( t ) = 0 and the orbit is a straight line.

Solution Summary: The author explains that the area swept out by the radial vector at time tis explained.

Videos

To explain:That the area swept out by the radial vector at time tis ,A(t)=12∥r0×v0∥t and thus Kepler’s Second Law continues to hold (the rate is constant) if a planet has zero mass (m = 0), then Newton’s laws of motion reduce to r''(t)=0 and the orbit is a straight line.

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Chapter 14 Solutions