Explanation Now r ( t ) = ( 4 t 1 2 , ln t , 2 t ) ∥ r ' ( t ) ∥ = ( 4 t + 1 t 2 + 4 ) ∥ r ' ( t ) ∥ = 4 t 2 + 4 t + 1 t 2 ∥ r ' ( t ) ∥ = ( 2 t + 1 ) 2 t 2 ∥ r ' ( t ) ∥ = ( 2 t + 1 ) t ∥ r ' ( t )

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Chapter 14.3, Problem 12E

To determine

Arc length function for

$r (t) = (4 t^{\frac{1}{2}}, \ln t, 2 t)$ , a = 1

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Chapter 14.3, Problem 11E

Chapter 14.3, Problem 13E

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Find the x-coordinate of each point where the function f (2) ) = arcsin (5 r- 2 z) has a horizontal tangent line. 2. a) OI = -1 and a = b) O = 0 and r 1. c) O I = d) Oz= 215 %3D 2/5

Chapter 14 Solutions

CALCULUS W/SAPLING ACCESS >IC<

Ch. 14.1 - Prob. 1PQ Ch. 14.1 - Prob. 2PQ Ch. 14.1 - Prob. 3PQ Ch. 14.1 - Prob. 4PQ Ch. 14.1 - Prob. 5PQ Ch. 14.1 - Prob. 6PQ Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E

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Area Between The Curve Problem No 1 - Applications Of Definite Integration - Diploma Maths II; Author: Ekeeda;https://www.youtube.com/watch?v=q3ZU0GnGaxA;License: Standard YouTube License, CC-BY

Arc length function for r ( t ) = ( 4 t 1 2 , ln t , 2 t ) , a = 1

Solution Summary: The author explains that length of arc function is s (t ) = 2 t + ln

Concept explainers

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Arc length function for

$r (t) = (4 t^{\frac{1}{2}}, \ln t, 2 t)$ , a = 1

Want to see the full answer?

Chapter 14 Solutions

Arc length function for r ( t ) = ( 4 t 1 2 , ln t , 2 t ) , a = 1

Solution Summary: The author explains that length of arc function is s (t ) = 2 t + ln

Concept explainers

Videos

Arc length function for r(t)=(4t12,lnt,2t), a = 1

Want to see the full answer?

Chapter 14 Solutions

Arc length function for

$r (t) = (4 t^{\frac{1}{2}}, \ln t, 2 t)$ , a = 1