Organic Chemistry
Organic Chemistry
12th Edition
ISBN: 9781118875766
Author: T. W. Graham Solomons, Craig B. Fryhle, Scott A. Snyder
Publisher: WILEY
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Chapter 14, Problem 40P

Consider these reactions:

Chapter 14, Problem 40P, Consider these reactions: The intermediate A is a covalently bonded compound that has typical 1H NMR

The intermediate A is a covalently bonded compound that has typical 1 H NMR signals for aromatic ring hydrogens and only one additional signal at δ 1.21, with an area ratio of 5:3, respectively. Final product B is ionic and has only aromatic hydrogen signals.

What are the structures of A and B?

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Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The 1H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively. - Identify compound B, explaining your reasoning
19. A compound with molecular formula C6H12O2 exhibits two singlets in its 1H NMR spectrum, at d 1.4 (9H) and d 2.0 (3H). Its IR spectrum shows a strong absorption band near 1740 cm-1. What is the structure for this compound? Show the correlation of the spectra with the molecular structure.
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NMR Spectroscopy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=SBir5wUS3Bo;License: Standard YouTube License, CC-BY