The current through a 6.8 k
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- find the phase, frequency, amplitude, period of the sinusoid v(t) = 10sin(377t +45°). Graphically sketch the position of the sinusoidarrow_forwardA chirp is a signal of the form x(t) = A sin(2πϕ(t)) where A is the amplitude and the function ϕ(t) is the phase of the chirp. If the phase has the form ϕ(t) = f0 ((t1 − t0) / ln ( f1/ f0 )) * ((f1/ f0)^( t−t0/ t1−t0 ) − 1 ) + ϕ0, Then the signal is called a logarithmic chirp, exponential chirp, or exponentially swept sine. Here, f0 is the frequency at time t0, f1 is the frequency at time t1, and ϕ0 is the phase at time t0, where t1 > t0, f1 ̸= f0, and f1f0 > 0 The frequency of a chirp at time t is f(t) = dϕ/ dt . What would the frequency of a logarithmic chirp as a function of time t and show that the frequency strictly increases for t0 < t < t1 when f1 > f0 and strictly decreases for t0 < t < t1 when f1 < f0.? Thank you for the help.arrow_forward1) Given the sinusoids v1(t) = 8cos (250t +15°) V and v2(t) = 6cos (250t – 45°) V, determine the time by which v2(t) is advanced or delayed with respect to v1(t).arrow_forward
- Compute for the Energy and Power of the following signals in terms of per unit use the proper formula whether the signal is continuous or discrete. 1. sin[n] 2. cos(t)arrow_forwardThe current in an L-R-C series circuit has amplitude 0.120 Aand angular frequency 8.00 * 103 rad/s, and it has its maximum positivevalue at t = 0. The resistance is 95.0 Ω, the inductance is 6.50 mH,and the capacitance is 0.440 mF. For the resistor, inductor, and capacitor,find (a) the voltage amplitudes and (b) the instantaneous voltages att = 0.305 ms.arrow_forwardThe phasor current Ib in the circuit is 25 0 . mA.1. Find Ia, Ic, and Ig.2. If ω=1500 rad/s, write expressions for ia(t), ic(t), and ig(t).arrow_forward
- A circuit has an ac voltage source and a resistor and capacitorconnected in series. There is no inductor. The ac voltage source hasvoltage amplitude 900 V and angular frequency v = 20.0 rad/s. Thevoltage amplitude across the capacitor is 500 V. The resistor has resistanceR = 300 Ω. What is the average rate at which the ac source supplies electrical energy to the circuit?arrow_forward1. Find the equation defined by the waveform x(t) as shown in the figure below. evaluate x(t) using the integral from -∞ to ∞ of x(t)∂(t)dt and also evaluate x(t) at 1.5. Determine also the power content, energy content and plot the odd and even component. Answers should be in 8 decimal placesarrow_forwardx(t)= C0 + C1*sin(w*t+theta1) + C2*sin(2*w*t+theta2) x(t)= A0 + A1*cos(w*t) + B1*sin(w*t) + A2*cos(2*w*t) + B2*sin(2*w*t) A0=-1, A1= 5, B1= 6, A2=-3, B2= 4, w=500 rad/sec. Express all angles between plus and minus 180 degrees. Determine C0, C1, theta1 (deg), C2, theta2 (deg)arrow_forward
- The following circuit is powered by a polyharmonic voltage whose expression is: v(t) = 100+141.sin (1000t) + 70.7.sin (2000t) V. It is requested: a) The expression of the instantaneous current.b) Plot the amplitude and phase spectra of the voltage and current.c) The values of the apparent, active, reactive and distortion powers, justifying the resultsarrow_forwardThe circuit is operating in thesinusoidal steady state. Find io(t) if vs(t)=25 sin 4000t Varrow_forwardThe voltage across the terminals of the 5μF capacitor is 30 cos (4000t + 25°) V. Calculate (a) the capacitive reactance; (b) the impedance of the capacitor; (c) the phasor current I; and (d) the steady-state expression for i (t). 5 μF + v iarrow_forward
- Delmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning